LCT 50 Formulation LCT 50 Course Overview 1

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LCT 50 Formulation

LCT 50 Formulation

LCT 50 Course Overview 1. 2. 3. 4. 5. 6. Purpose History Philosophy: CATO

LCT 50 Course Overview 1. 2. 3. 4. 5. 6. Purpose History Philosophy: CATO vs. NTOA Formula and Calculations Practical Applications Tactical Case Study

LCT 50 Purpose 1. Helps determine amount of chemical agent to use. 2. Estimates

LCT 50 Purpose 1. Helps determine amount of chemical agent to use. 2. Estimates the time a suspect can remain in agent environment. 3. Provides a guideline for command staff and for potential criminal & civil litigation.

LCT 50 Defined “Concentration (LC 50) multiplied by the time (T) of exposure that

LCT 50 Defined “Concentration (LC 50) multiplied by the time (T) of exposure that is lethal to 50% of exposed personnel. ” (Usually expressed in minutes of exposure. )

LCT 50 History · Formula developed from an Edgewood Arsenal study of CS exposure

LCT 50 History · Formula developed from an Edgewood Arsenal study of CS exposure in 1967. • Edgewood Arsenal is a chemical research facility (now known as US Army Medical Research Institute of Chemical Defense). · Conducted for the U. S Army who was replacing CN with CS for outside riot control. Not inside or for civil law enforcement! · Conducted in a static, sealed container. · Formula values determined concentration levels were lethal for 50% of population.

LCT 50 Philosophy · National Tactical Officer’s Association · California Association of Tactical Officers

LCT 50 Philosophy · National Tactical Officer’s Association · California Association of Tactical Officers

LCT 50 Philosophy NTOA · Based on use of force “reasonableness” standard (Graham vs.

LCT 50 Philosophy NTOA · Based on use of force “reasonableness” standard (Graham vs. Connor). · Don’t need a formula to use other forms of force. · LCT 50 based on faulted research: · No consideration given to biological/metabolic differences. · Conducted in static sealed containers. · CS was intended for outside riot control, not inside sealed environments.

LCT 50 Philosophy CATO · Formula and incident based. · Uses Edgewood Arsenal Study

LCT 50 Philosophy CATO · Formula and incident based. · Uses Edgewood Arsenal Study as a “baseline. ” · Bases concentration variable (i. e. . 004, . 008, etc) on tactical situation. · Estimates the time a suspect can remain in the agent.

LCT 50 Formula 3 -Step Process 1. Compute room(s) volume ( L x W

LCT 50 Formula 3 -Step Process 1. Compute room(s) volume ( L x W x H ) Equals = CUBIC FEET 2. CUBIC FEET X CONCENTRATION VARIABLE Equals = GRAMS of AGENT NEEDED 3. CUBIC FEET GRAMS of AGENT NEEDED X. 71 (CS Constant) = LCT 50 in minutes

LCT 50 Formula (CV) Concentration Variable • Equates to grams of agent per 1000

LCT 50 Formula (CV) Concentration Variable • Equates to grams of agent per 1000 cubic feet. • US Department of Energy research determined 4 grams per 1000 cubic feet ( or. 004) as the smallest concentration to yield agent symptoms. • A higher variable will give a higher concentration of agent, but a shorter LCT 50. • A lower variable will yield a lower agent concentration, but a higher LCT 50. • For Example: –. 012 = 60 minutes –. 008 = 89 minutes –. 004 = 178 minutes • Concentration variables should be based on SWAT chemical agent deployment philosophy.

LCT 50 Formula (Constant) Constant (. 71) • Based on US Army research. •

LCT 50 Formula (Constant) Constant (. 71) • Based on US Army research. • Research that was based on how much agent would kill a human. • Will never change.

LCT 50 Worksheet (part 1) 1. _______ x _______ = ______ Length Width Height

LCT 50 Worksheet (part 1) 1. _______ x _______ = ______ Length Width Height Cubic Feet 2. _____ x CV = _________ Cubic Feet Total Grams Needed 3. _____ Cubic Feet ____ x. 71 = _______ Total # of LCT 50 (minutes) Grams

LCT 50 Worksheet (part 2) Proposed LCT 50 - Time 1. _______ x _______

LCT 50 Worksheet (part 2) Proposed LCT 50 - Time 1. _______ x _______ = ______ Length Width Height Cubic Feet 2. _____ x. 71 Cubic Feet ________ = ________ Proposed LCT 50 Grams of Agent

LCT 50 Worksheet (part 2) Amount of Agent Used 1. _______ x _______ =

LCT 50 Worksheet (part 2) Amount of Agent Used 1. _______ x _______ = ______ Length Width Height Cubic Feet 2. _____ Cubic Feet _______ x. 71 = ________ Grams of Agent LCT 50 (minutes)

LCT 50 Munitions Needed Now that we know the “total # of grams of

LCT 50 Munitions Needed Now that we know the “total # of grams of agent” and our LCT 50, how many munitions will we need? ANSWER: Divide total # of grams of agent by the amount of agent in your munition of choice. This is where a munitions data card comes in handy!

Munition Data Cards

Munition Data Cards

Questions or Comments

Questions or Comments