Last Time Magnetic Force Motors and Generators Gauss

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Last Time Magnetic Force Motors and Generators Gauss' Law 1

Last Time Magnetic Force Motors and Generators Gauss' Law 1

Gauss’s Law Features: 1. Proportionality constant 2. Size and shape independence 3. Independence on

Gauss’s Law Features: 1. Proportionality constant 2. Size and shape independence 3. Independence on number of charges inside 4. Charges outside contribute zero 2

Today Gauss' Law: Examples Ampere's Law 3

Today Gauss' Law: Examples Ampere's Law 3

Example: Amount of induced charge inside a conductor Hollow region Net charge Q (

Example: Amount of induced charge inside a conductor Hollow region Net charge Q ( > 0) on the conductor Net charge –q < 0 Hollow region Field ? Net charge induced = +q + + + Net charge (Q-q) on the outside surface

i. Clicker question A conductor has a net charge of -24 C on it.

i. Clicker question A conductor has a net charge of -24 C on it. It also has a hollow region in the interior. If you place a charge of +12 μC in this hollow region, what will be the total charge on the exterior surface of the object? A. B. C. D. E. -24 C 12 C -36 C -12 C 5

Again: Continuous Charge Distribution 1: Charged Line At a point P on perpendicular axis:

Again: Continuous Charge Distribution 1: Charged Line At a point P on perpendicular axis: x a e P th 6 s la t m o r f

Infinitely long uniformly charged line E Gauss’s Law: h r Same result but much

Infinitely long uniformly charged line E Gauss’s Law: h r Same result but much less work! 7

Long Cylindrical Capacitor 1. Put charges +q on inner cylinder of radius a, -q

Long Cylindrical Capacitor 1. Put charges +q on inner cylinder of radius a, -q on outer cylindrical shell of inner radius b. 2. Calculate E by Gauss’ Law b a +q L -q 3. Calculate V 4. Divide q by V • • • C dep. log. on a, b 8

Spherical Capacitor 1. Put charges +q on inner sphere of radius a, -q on

Spherical Capacitor 1. Put charges +q on inner sphere of radius a, -q on outer shell of inner radius b. 2. Calculate E by Gauss’s Law 3. Calculate V from E 4. Divide q by V • q is proportional to V • C only depends on a, b 9 (isolated sphere)

i. Clicker Question A. B. 0 C. D. 10

i. Clicker Question A. B. 0 C. D. 10

Uniformly charged thin, infinite sheet Gauss’s Law! A h 11

Uniformly charged thin, infinite sheet Gauss’s Law! A h 11

Gauss' Law for Magnetism? GAUSS' LAW for charge So far, no experiment has found

Gauss' Law for Magnetism? GAUSS' LAW for charge So far, no experiment has found a "magnetic charge" (a. k. a. magnetic monopole) Big fat ZERO! Gauss' Law for Magnetism is simpler: NO TIC E N G A M S OLE MONOP http: //www. congresshotelstrike. info/ GAUSS' LAW FOR MAGNETISM 12

Next Up: Ampere's Law First review Biot-Savart Law 13

Next Up: Ampere's Law First review Biot-Savart Law 13

Very Close to the Wire Very close to the wire: r << L CLOSE

Very Close to the Wire Very close to the wire: r << L CLOSE TO THE WIRE B I t 14 http: //physick. wikispaces. com/Electric+Current as P e h t 13 m e o r r ts f ctu a Le l B

Very Long Wire Very Long wire: L >> r VERY LONG WIRE B I

Very Long Wire Very Long wire: L >> r VERY LONG WIRE B I t 15 http: //physick. wikispaces. com/Electric+Current as P e h t 13 m e o r r ts f ctu a Le l B

Very Long Wire Viewed from the end Current coming out of board s 16

Very Long Wire Viewed from the end Current coming out of board s 16

Very Long Wire Viewed from the end Current coming out of board Cylindrical pattern

Very Long Wire Viewed from the end Current coming out of board Cylindrical pattern of B-field Let's take a line integral along one circle is along our circle AMPERE'S LAW 17

Gauss' Law for Point Charge E-field Point Charge Gauss' Law for Point Charge: s

Gauss' Law for Point Charge E-field Point Charge Gauss' Law for Point Charge: s Works for any size sphere because r cancels On each sphere: Field Surface Area Something similar is going to happen for B of a wire 18 e? M r be 3 em ide m Sl e R

Ampere's Law for Long Wire Biot-Savart Law B-field Long Wire Current coming out of

Ampere's Law for Long Wire Biot-Savart Law B-field Long Wire Current coming out of board Ampere's Law for Long Wire: s Works for any size circle because r cancels On each circle: Field Circumference 19

Ampere's Law for Long Wire Biot-Savart Law B-field Long Wire Current coming out of

Ampere's Law for Long Wire Biot-Savart Law B-field Long Wire Current coming out of board Ampere's Law for Long Wire: s Works for any size circle because r cancels On each circle: In any segment, the contribution from any circle is the same. (Like a flashlight. ) Field Circumference 20

Ampere's Law for Long Wire Biot-Savart Law Current coming out of board B-field Long

Ampere's Law for Long Wire Biot-Savart Law Current coming out of board B-field Long Wire In any segment, the contribution from any "circle" is the same. (Like a flashlight. ) s On each circle: Field Circumference 21

Ampere's Law for Long Wire Biot-Savart Law Current coming out of board s B-field

Ampere's Law for Long Wire Biot-Savart Law Current coming out of board s B-field Long Wire In any segment, the contribution from any circle is the same. (Like a flashlight. ) Surround the wire with any shape by following different circles in different places. On each circle: Field Circumference 22

Ampere's Law for Long Wire Biot-Savart Law Current coming out of board s B-field

Ampere's Law for Long Wire Biot-Savart Law Current coming out of board s B-field Long Wire In any segment, the contribution from any circle is the same. (Like a flashlight. ) Surround the wire with any path by following different circles in different places. Line integral aruond outer surface is always same. On each circle: Field Circumference 23

Ampere's Law for Long Wire Biot-Savart Law Current coming out of board s B-field

Ampere's Law for Long Wire Biot-Savart Law Current coming out of board s B-field Long Wire In any segment, the contribution from any circle is the same. (Like a flashlight. ) Surround the wire with any path by following different circles in different places. Line integral around outer surface is always same. Limit of small segments works for any smooth path On each circle: Field Circumference 24

Ampere’s Law in Magnetostatics Biot-Savart’s Law can be used to derive another relation: Ampere’s

Ampere’s Law in Magnetostatics Biot-Savart’s Law can be used to derive another relation: Ampere’s Law The path integral of the dot product of magnetic field and unit vector along a closed loop, Amperian loop, is proportional to the net current encircled by the loop, • Choosing a direction of integration. • A current is positive if it flows along the RHR normal direction of the Amperian loop, as defined by the direction of integration. 25

i. Clicker Question Three currents I 1, I 2, and I 3 are directed

i. Clicker Question Three currents I 1, I 2, and I 3 are directed perpendicular to the plane of this page as shown. The value of the Ampere’s Law line integral of B∙ dl counterclockwise around the circular path is + 0 I 1. What’s the currents in I 2 and I 3? a. I 2=0, I 3 can be any value b. I 2=0, I 3 can only be zero c. I 2=I 1, I 3 can be any value d. I 2=2 I 1, I 3 can be any value e. I 2=0. 5 I 1, I 3 can be any value I 1 I 3 I 2 26

i. Clicker Question Three currents I, 2 I, and 3 I are directed perpendicular

i. Clicker Question Three currents I, 2 I, and 3 I are directed perpendicular to the plane of this page as shown. What is the value of the Ampere’s Law line integral of B∙ dl counterclockwise around the circular path shown? a. 4 0 I b. 2 0 I c. 2 0 I d. 6 0 I e. zero 2 I 3 I I 27

i. Clicker question Use Ampere’s law to calculate the magnetic field inside a solenoid.

i. Clicker question Use Ampere’s law to calculate the magnetic field inside a solenoid. (n is number of wraps per unite length). A. B. • Ampere’s Law: C. n windings per unit length D. 28

Example: Magnetic field of a long wire outside the wire 29

Example: Magnetic field of a long wire outside the wire 29

Example: A Non-Uniform Current Distribution Long, hollow cylindrical current of current density: Insider the

Example: A Non-Uniform Current Distribution Long, hollow cylindrical current of current density: Insider the cylinder, the total current encircled by the Amperian loop is 30

i. Clicker Question outside the wire Assume uniform current density, what’s the magnetic field

i. Clicker Question outside the wire Assume uniform current density, what’s the magnetic field vs. r inside the long wire. A). C). B). D). 31

i. Clicker Question outside the wire inside the wire 32

i. Clicker Question outside the wire inside the wire 32