Introduction to Thermodynamics Heat Chemical Energy in Physical

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Introduction to Thermodynamics Heat (Chemical Energy) in Physical & Chemical Changes Principles, Equations &

Introduction to Thermodynamics Heat (Chemical Energy) in Physical & Chemical Changes Principles, Equations & Diagrams Dr. Ron Rusay

UNITS: Celsius (o. C) & Kelvin (K) Temperature Scales Temperature is NOT ENERGY “Temperature

UNITS: Celsius (o. C) & Kelvin (K) Temperature Scales Temperature is NOT ENERGY “Temperature (sometimes called thermodynamic temperature) is a measure of the average kinetic energy of the particles in a system. Adding heat (energy) to a system causes its temperature to rise. ” August. 15, 2015 +142 o. F Manama, Bahrain o. C? K? = 61. 7 o. C +273. 15 = 334. 85 K

Kinetic Energy One of Many Types of Energy ð Kinetic Energy is due to

Kinetic Energy One of Many Types of Energy ð Kinetic Energy is due to the motion of an object. KE = 1/2 mv 2 (m = mass, v = velocity) ð ð

Energy: Heat is one form of energy. How many other different types of energy

Energy: Heat is one form of energy. How many other different types of energy are included in the graphic? UNITS: m = meter joule (J) calorie (c) kilocalorie (C) Kilowatt hour (k. Wh)

Energy: Heat, one form of energy. Others: Light (solar/radiant) Motion (kinetic) Electrical Chemical Biological

Energy: Heat, one form of energy. Others: Light (solar/radiant) Motion (kinetic) Electrical Chemical Biological Nutritional (Food) Nuclear Tectonic

Thermoregulation HOT (higher energy) cold (lower energy) Your Body Thermoregulation balance involves the heat

Thermoregulation HOT (higher energy) cold (lower energy) Your Body Thermoregulation balance involves the heat transfer to or from your body, and to or from the surroundings Your “Body Mass” is important to Thermoregulation; subcutaneous adipose tissue (fat) provides an insulating layer that impedes heat loss. This can be an advantage or a disadvantage depending on the surroundings. Do you know your Body Mass Index? See the NIH link below: http: //www. nhlbi. nih. gov/health/educational/lose_wt/BMI/bmi-m. htm

Thermoregulation: heat transfer to or from your body, and to or from the surroundings

Thermoregulation: heat transfer to or from your body, and to or from the surroundings Fever is a temperature above your normal temperature due to an increase in the body's temperature set-point. Hyperthermia is an increase in body temperature over your temperature set-point, due to either too much heat production or not enough heat loss. Hypothermia is a decrease in body temperature over your temperature set-point, due to too much heat loss.

Abdominal and hand thermograms of a BMI >30 female (A) and a BMI <30

Abdominal and hand thermograms of a BMI >30 female (A) and a BMI <30 female (B). BMI >30 BMI < 30 David M Savastano et al. Am J Clin Nutr 2009; 90: 1124 -1131 Increased heat production is associated with BMI >30; To regulate body temperature, those individuals must increase their heat dissipation through their hands. Is Dr. R’s hand temperature above normal? © 2009 by American Society for Nutrition

Lying & Temperature Effects (2018) Dr Emilio Gómez Milán University of Granada

Lying & Temperature Effects (2018) Dr Emilio Gómez Milán University of Granada

Heat Exchange Exo- and Endo- thermic Processes & Reactions (Exergonic and Endergonic) reactant(s) product(s)

Heat Exchange Exo- and Endo- thermic Processes & Reactions (Exergonic and Endergonic) reactant(s) product(s) Two types of thermochemical reactions: ð Exothermic: Heat is a reaction product; the heat flows to the surroundings. The amount is the difference between the products minus the reactants. …It is a negative value for the reaction. ð Endothermic: Heat is a reactant; the heat flows from the surroundings. The amount is the difference between the products minus the reactants…It is a positive value for the reaction.

PIZZA &

PIZZA &

Why can you burn the top of your mouth with hot pizza just out

Why can you burn the top of your mouth with hot pizza just out of the oven and not the bottom? (The top & bottom are at the same temperature!!!) http: //chemconnections. org/general/movies/Pizza-thermo%202. mp 4

http: //www. eia. gov/energyexplained/ Cp UNITS: J/(g⋅K) or J/(mol⋅K) Energy : joule (J) calorie

http: //www. eia. gov/energyexplained/ Cp UNITS: J/(g⋅K) or J/(mol⋅K) Energy : joule (J) calorie (c) kilocalorie (C) Kilowatt hour (k. Wh) Chemical Nuclear Electrical Light (solar) Motion (kinetic) (Cp) Body fat: In obese mice (fat content 52. 76% body wt) the heat capacity is 3. 66 k. J kg-1 K-1 and in lean mice (fat content 7. 55% body wt) the heat capacity is 2. 65 k. J kg-1 K-1.

Specific Heat Interactive Simulation http: //chemconnections. org/general/chem 120/Flash/specific_heat_s. html

Specific Heat Interactive Simulation http: //chemconnections. org/general/chem 120/Flash/specific_heat_s. html

QUESTION

QUESTION

Answer 0. 13 J/g C = 48. 8 J / 15 grams. 25 C

Answer 0. 13 J/g C = 48. 8 J / 15 grams. 25 C

https: //phet. colorado. edu/en/simulation/ states-of-matter-basics http: //chemconnections. org/general/movies/Heating. Curves. swf

https: //phet. colorado. edu/en/simulation/ states-of-matter-basics http: //chemconnections. org/general/movies/Heating. Curves. swf

http: //chemconnections. org/general/movies/Heating. Curves. swf Temperature and Physical States s �l �g Temperature o.

http: //chemconnections. org/general/movies/Heating. Curves. swf Temperature and Physical States s �l �g Temperature o. C Time: second (SI unit)

Energy Diagram Heat @ constant Pressure (Enthalpy) H s �l �g H 2 O

Energy Diagram Heat @ constant Pressure (Enthalpy) H s �l �g H 2 O (l) @ 25 o. C H = Cp liq x mass x T H = 5. 22 k. J H H 2 O (l) @ 0 o. C H 2 O (s) @- 25 o. C Hfusion = 6. 009 k. J/mol Hfusion = 16. 69 k. J H = Cp ice x mass x T H = 2. 54 k. J Process Path H = Hice + Hfusion + Hliq If 50. 0 g of ice @ -25 o. C warms H = ? to 25 o. C what is H of the H = 24. 45 k. J process?

 Hdeposition= (-) H = J or k. J cal or kcal Hcondensation= (-)

Hdeposition= (-) H = J or k. J cal or kcal Hcondensation= (-) Hsolidification= (-) f. p. o. C cooling heating b. p. o. C m. p. o. C Hvaporization= (+) Hfusion= (+) Hsublimation= (+)

QUESTIONs

QUESTIONs

QUESTION

QUESTION

Answer A) endothermic Hfusion= (+)

Answer A) endothermic Hfusion= (+)

QUESTION Gas Liquid

QUESTION Gas Liquid

Answer A) endothermic Hvaporization= (+) Gas Liquid

Answer A) endothermic Hvaporization= (+) Gas Liquid

QUESTION Gas Liquid

QUESTION Gas Liquid

Answer B) exothermic Hcondensation= (-) Gas Liquid

Answer B) exothermic Hcondensation= (-) Gas Liquid

QUESTION Gas Solid

QUESTION Gas Solid

Answer A) endothermic Hvaporization= (+) Hfusion= (+) Hsublimation= (+) Gas Solid

Answer A) endothermic Hvaporization= (+) Hfusion= (+) Hsublimation= (+) Gas Solid

QUESTION ?

QUESTION ?

Answer B) exothermic Hsolidifcation= (-) Liquid Solid

Answer B) exothermic Hsolidifcation= (-) Liquid Solid

Heat of Reaction The heat of any reaction can be calculated from the heat(s)

Heat of Reaction The heat of any reaction can be calculated from the heat(s) of formation of products minus reactants. ð Hrxn° = np Hf (products) nr Hf (reactants) Endothermic Hrxn°=(+) and Exothermic Hrxn°=(-)

Heat of Reaction Endergonic Hrxn°=(+) and Exergonic Hrxn°=(-)

Heat of Reaction Endergonic Hrxn°=(+) and Exergonic Hrxn°=(-)

QUESTION

QUESTION

Answer

Answer

QUESTION

QUESTION

Answer

Answer

Endothermic Reactions Photosynthesis 6 CO 2 (g) + 6 H 2 O(l) + energy

Endothermic Reactions Photosynthesis 6 CO 2 (g) + 6 H 2 O(l) + energy C 6 H 12 O 6 (s) + 6 O 2(g) https: //www. youtube. com/watch? v=ea. ACs. EXAjh. A Hrxn° = np Hf (products) nr Hf (reactants) Hrxn° = (+) = + 2800 k. J/mol C = (+) = + 2800 k. J/mol 6 H 12 O 6 (glucose or fructose)

(Enthalpy H) Endothermic Reactions Ba(OH)2. 8 H 2 O(s) + 2 NH 4 Cl(s)

(Enthalpy H) Endothermic Reactions Ba(OH)2. 8 H 2 O(s) + 2 NH 4 Cl(s) → 2 NH 3(g) + 10 H 2 O(l) + Ba. Cl 2(s) http: //chemconnections. org/general/movies/Endoterm. HMVID 12. MOV Hrxn° = np Hf (products) nr Hf (reactants) Hrxn° = (+) = + ? k. J/mol

QUESTION

QUESTION

Answer Hrxn° = np Hf (products) nr Hf (reactants) Hrxn° = - 3811 k.

Answer Hrxn° = np Hf (products) nr Hf (reactants) Hrxn° = - 3811 k. J – (-3973 k. J) = + 162 k. J/mol

Exothermic Reactions Pointe Du Hoc �Hrxn° = - 14, 455 k. J/mol http: //www.

Exothermic Reactions Pointe Du Hoc �Hrxn° = - 14, 455 k. J/mol http: //www. youtube. com/watch? v=rd. Csb. Zf 1_Ng 1: 37

Hot Food: MRE’s Exothermic Reaction Enough heat to raise the temperature of 8 ounces

Hot Food: MRE’s Exothermic Reaction Enough heat to raise the temperature of 8 ounces of food to 56 o. C (100 o. F). Mg(s) + 2 H 2 O(l) Mg(OH)2 (aq) + H 2 (g)+ energy:

Exothermic Reactions Combustion: Burning Carbon Compounds Cx. Hy + (x + y/4) O 2

Exothermic Reactions Combustion: Burning Carbon Compounds Cx. Hy + (x + y/4) O 2 � x CO 2 + y/2 H 2 O + energy https: //www. youtube. com/watch? v=Uigj. FAI 2 u. WM

Exothermic Reactions Octane (Gas) Combustion Engine 2 C 8 H 18(l)+ 25 O 2(g)

Exothermic Reactions Octane (Gas) Combustion Engine 2 C 8 H 18(l)+ 25 O 2(g) 16 CO 2(g)+18 H 2 O(l) + energy �Hrxn° = - 5, 075 k. J/mol �Hrxn° / gallon = ? 1 gallon = 3, 785 m. L Density = 0. 7 g/m. L 1 mole = 114 g/mol 1 gallon C 8 = 23. 2 mol C 8 �Hrxn° / gallon = 118, 000 k. J ~ 25 miles > 18 lbs CO 2 http: //chemconnections. org/general/movies/4 Stroke. Engine_Ortho_3 D_Small. gif

Exothermic Reactions Glycolysis: Food / eg. “Burning” Sugar (Photosynthesis in Reverse) energy http: //chemconnections.

Exothermic Reactions Glycolysis: Food / eg. “Burning” Sugar (Photosynthesis in Reverse) energy http: //chemconnections. org/general/chem 106/Calories-Guide. html C 6 H 12 O 6 (s) + 6 O 2(g) 6 CO 2 (g) + 6 H 2 O(l) + energy https: //www. youtube. com/watch? v=u. WOURkrxp. H 4 Hrxn° = np Hf (products) nr Hf (reactants) Hrxn° = (-) = - 2800 k. J/mol C = (-) = - 2800 k. J/mol 6 H 12 O 6 (glucose or fructose)

Calorimetry Interactive How many kcal of energy (food Calories) do you get from eating

Calorimetry Interactive How many kcal of energy (food Calories) do you get from eating (burning) 1 gram of sucrose? . . . from 1 mole of sucrose? m x Cp x ΔT = q (heat) q=? http: //chemconnections. org/general/chem 120/Flash/calorimetry_s. html ΔH Reaction = ? k. J /g sucrose ΔH Reaction = ? k. J /mol sucrose

Calorimetry Interactive How many kcal of energy (food Calories) do you get from eating

Calorimetry Interactive How many kcal of energy (food Calories) do you get from eating (burning) 1 gram of sucrose? . . . from 1 mole of sucrose? m x Cp x ΔT = q (heat) 1000. g H 20 x 4. 184 J/g°C x (1. 7°C) = = + 7110 J + 420 J/°C x (1. 7°C) q = -7800 J/ 0. 500 g sucrose q = -15600 J / g sucrose q = -15. 6 k. J / g sucrose -3. 7 Cal /g (kcal /g sucrose ) http: //chemconnections. org/general/chem 120/Flash/calorimetry_s. html ΔH Reaction = -15. 6 k. J /g sucrose x Molar Mass sucrose [342. 3 g/mol] ΔH Reaction = -5340 k. J /mol sucrose

Calorimetry Interactive How many kcal of energy (food Calories) do you get from eating

Calorimetry Interactive How many kcal of energy (food Calories) do you get from eating 1 gram of lactose versus 1 gram of sucrose? m x Cp x ΔT = q (heat) 1000. g H 20 x 4. 184 J/g°C x (1. 7°C) = = + 7110 J + 420 J/°C x (1. 7°C) ΔHReaction = -7800 J ΔHReaction = / 0. 500 g sucrose -15600 J / g sucrose http: //chemconnections. org/general/chem 120/Flash/calorimetry_s. html ΔH Reaction = -15. 6 k. J /g sucrose = -3. 7 kcal /g sucrose = -15. 6 k. J /g lactose = -3. 7 kcal /g lactose

Bomb Calorimetry (Interactive) How many kcal of energy (food Calories) do you get from

Bomb Calorimetry (Interactive) How many kcal of energy (food Calories) do you get from eating 1 gram of lactose versus 1 gram of sucrose? m x Cp x ΔT = q (heat) 1000. g H 20 x 4. 184 J/g°C x (1. 7°C) = = + 7100 J + 420 J/°C x (1. 7°C) sucrose lactose C 12 H 22 O 11 ΔHReaction = -7800 J ΔHReaction = / 0. 500 g sucrose -15600 J / g sucrose http: //chemconnections. org/general/chem 120/Flash/calorimetry_s. html ΔH Reaction = -15. 6 k. J /g sucrose = -3. 7 kcal /g sucrose = -15. 6 k. J /g lactose = -3. 7 kcal /g lactose

How many k. J of energy would you get from eating 1 gram of

How many k. J of energy would you get from eating 1 gram of TNT versus 1 gram of sucrose or lactose? . . 1 mole? TNT “HE”: High Explosive TNT Trinitrotoluene per mole ΔH Reaction = -14. 2 k. J /g TNT x 227. 13 g·mol− 1= -3, 225 k. J /mol TNT

TNT “HE”: High Explosive https: //www. youtube. com/watch? v=3 G 3 kh 39 o.

TNT “HE”: High Explosive https: //www. youtube. com/watch? v=3 G 3 kh 39 o. DPo 400 grams (< 1 lb) Trinitrotoluene explosion https: //www. youtube. com/watch? v=zh. Ti. RYw. Jq. HY 5 kilograms (~ 10 lb) Trinitrotoluene explosion https: //www. youtube. com/watch? v=b. IQr 62 l. Zbs. M 50, 000 kilograms (~ 50 tons) Trinitrotoluene explosion TNT Trinitrotoluene per mole ΔH Reaction = -14. 2 k. J /g TNT x 227. 13 g·mol− 1= -3, 225 k. J /mol TNT 500, 000 kilograms (~ 500 tons) Trinitrotoluene explosion

What makes TNT “explosive” versus sucrose or lactose? TNT Trinitrotoluene 12, 900 k. J

What makes TNT “explosive” versus sucrose or lactose? TNT Trinitrotoluene 12, 900 k. J 3, 225 k. J/mol Kinetics (speed of reaction) & Gases Produced

 per mole ΔH Reaction = -14. 2 k. J /g TNT x 227.

per mole ΔH Reaction = -14. 2 k. J /g TNT x 227. 13 g·mol− 1= -772 k. J /mol TNT

TNT (“HE”: High Explosive) Trinitrotoluene Combustion _4_ 4 C 7 H 5 N 3

TNT (“HE”: High Explosive) Trinitrotoluene Combustion _4_ 4 C 7 H 5 N 3 O 6 + _21_ + 21 O 2(g) 6 N 2(g) + 10 H 2 O (g) + 28 CO 2 (g) + energy Balance the above reaction.

TNT (“HE”: High Explosive) Trinitrotoluene combustion __ + ____ __ C 7 H 5

TNT (“HE”: High Explosive) Trinitrotoluene combustion __ + ____ __ C 7 H 5 N 3 O 6 + __ O 2(g) __ N 2(g) + __ H 2(g) + __ CO(g) + __ C(s) + energy Balance the above reaction.

TNT (“HE”: High Explosive) Trinitrotoluene Combustion _4_ + _21_ _4_ C 7 H 5

TNT (“HE”: High Explosive) Trinitrotoluene Combustion _4_ + _21_ _4_ C 7 H 5 N 3 O 6 + _21_ O 2(g) _6_ N 2(g) + _10_ H 2 O (g) + _28_ CO 2 (g) + energy Balance the above reaction.

TNT “HE”: High Explosive 400 grams (< 1 lb) Trinitrotoluene explosion https: //www. youtube.

TNT “HE”: High Explosive 400 grams (< 1 lb) Trinitrotoluene explosion https: //www. youtube. com/watch? v=3 G 3 kh 39 o. DPo _2_ C 7 H 5 N 3 O 6 (MM = 227. 13 g·mol− 1) _3_ N 2(g) + _5_ H 2(g) + _12_ CO(g) + _2_ C(s) + energy How many k. J is produced per gram of TNT? …. . per mole of TNT?

TNT “HE”: High Explosive 400 grams (< 1 lb) Trinitrotoluene explosion https: //www. youtube.

TNT “HE”: High Explosive 400 grams (< 1 lb) Trinitrotoluene explosion https: //www. youtube. com/watch? v=3 G 3 kh 39 o. DPo _2_ C 7 H 5 N 3 O 6 (MM = 227. 13 g·mol− 1) _3_ N 2(g) + _5_ H 2(g) + _12_ CO(g) + _2_ C(s) + energy How many k. J is produced per gram of TNT? …. . per mole of TNT?

Bonus: “Bomb Calorimetry” (Interactive) How many k. J of energy is produced from the

Bonus: “Bomb Calorimetry” (Interactive) How many k. J of energy is produced from the explosion of 250 milligrams of TNT high explosive? m x Cp x ΔT = q (heat) 750. g H 20 x 4. 184 J/g°C x (1. 0°C) = = + 3138 J + 420 J/°C x (1. 0°C) ΔHReaction = -3558 J / 0. 250 g TNT ΔHReaction = -14232 J / g http: //chemconnections. org/general/chem 120/Flash/calorimetry_s. html ΔH Reaction = -14. 2 k. J /g TNT = -3. 4 kcal /g TNT ΔH Reaction = -14. 2 k. J /g TNT x 227. 13 g·mol− 1= -772 k. J /mol TNT

Chemical Energy (Heat) Thermodynamics https: //www. youtube. com/watch? v=Rfz. Yl 7 Ll 5 Ug

Chemical Energy (Heat) Thermodynamics https: //www. youtube. com/watch? v=Rfz. Yl 7 Ll 5 Ug

https: //www. youtube. com/watch? v =YM-uyk. Vfq_E Enthalpy H (“Heat”) Entropy S (“Disorder”) https:

https: //www. youtube. com/watch? v =YM-uyk. Vfq_E Enthalpy H (“Heat”) Entropy S (“Disorder”) https: //www. youtube. com/watch? v =8 m 6 Rt. Opqvt. U

Cold Packs (Entropy S) Endothermic Processes H 2 O(l) + NH 4 NO 3(s)

Cold Packs (Entropy S) Endothermic Processes H 2 O(l) + NH 4 NO 3(s) → NH 4 NO 3(aq) → NH 4+(aq) + NO 3 -(aq) https: //www. youtube. com/watch? v=h. Vh-bp. Av 4_E Srxn° = np S (products) nr S (reactants) Srxn° = (+) = + ? k. J/mol

FASEB J. April 2009 596. 2 The relative heat capacity (Cp) of an obese

FASEB J. April 2009 596. 2 The relative heat capacity (Cp) of an obese person (BMI >30) is higher than that of a lean person. It has a pronounced effect on thermoregulation and cooling of the body. https: //www. nhlbi. nih. gov/health/educational/lose_wt/BMI/bmi_tbl. htm

Thermoregulation: heat transfer to or from our body, and to or from the surroundings

Thermoregulation: heat transfer to or from our body, and to or from the surroundings If your core body temperature drops to below 35°C (95°F), you are ‘hypothermic’, @ 31°C (88 o. F) comatose, @ 26 -28°C (7982°F) arrhythmia and death