Introduction to Quantum Information Processing QIC 710 CS

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Introduction to Quantum Information Processing QIC 710 / CS 768 / PH 767 /

Introduction to Quantum Information Processing QIC 710 / CS 768 / PH 767 / CO 681 / AM 871 Lectures 10– 11 (2019) Richard Cleve QNC 3129 cleve@uwaterloo. ca 1 © Richard Cleve 2020

More state distinguishing problems 2 © Richard Cleve 2020

More state distinguishing problems 2 © Richard Cleve 2020

More state distinguishing problems Which of these states are distinguishable? Divide them into equivalence

More state distinguishing problems Which of these states are distinguishable? Divide them into equivalence classes: 1. 0 + 1 2. − 0 − 1 3. 0 with prob. ½ 1 with prob. ½ 4. 0 + 1 with prob. ½ 0 − 1 with prob. ½ 5. 0 with prob. ½ 0 + 1 with prob. ½ 6. 0 1 0 + 1 0 − 1 with prob. ¼ 7. The first qubit of 01 − 10 Answers later on. . . This is a probabilistic mixed state © Richard Cleve 2020 3

Density matrix formalism 4 © Richard Cleve 2020

Density matrix formalism 4 © Richard Cleve 2020

Density matrices (1) Until now, we’ve represented quantum states as vectors (e. g. ψ

Density matrices (1) Until now, we’ve represented quantum states as vectors (e. g. ψ , and all such states are called pure states) An alternative way of representing quantum states is in terms of density matrices (a. k. a. density operators) The density matrix of a pure state ψ is the matrix = ψ ψ Example: the density matrix of 0 + 1 is 5 © Richard Cleve 2020

Density matrices (2) How do quantum operations work using density matrices? Effect of a

Density matrices (2) How do quantum operations work using density matrices? Effect of a unitary operation on a density matrix: † applying U to yields U U (this is because the modified state is U ψ ψ U† ) Effect of a measurement on a density matrix: measuring state with respect to the basis 1 , 2 , . . . , d , yields the k th outcome with probability k k (this is because k k = k ψ ψ k = k ψ 2 ) —and the state collapses to k k © Richard Cleve 2020 6

Density matrices (3) A probability distribution on pure states is called a mixed state:

Density matrices (3) A probability distribution on pure states is called a mixed state: ( ( ψ1 , p 1), ( ψ2 , p 2), …, ( ψd , pd)) The density matrix associated with such a mixed state is: Example: the density matrix for (( 0 , ½ ), ( 1 , ½ )) is: Question: what is the density matrix of (( 0 + 1 , ½ ), ( 0 − 1 , ½ )) ? © Richard Cleve 2020 7

Density matrices (4) How do quantum operations work for these mixed states? Effect of

Density matrices (4) How do quantum operations work for these mixed states? Effect of a unitary operation on a density matrix: † applying U to still yields U U This is because the modified state is: Effect of a measurement on a density matrix: measuring state with respect to the basis 1 , 2 , . . . , d , still yields the k th outcome with probability k k Why? © Richard Cleve 2020 8

Recap: density matrices Quantum operations in terms of density matrices: • Applying U to

Recap: density matrices Quantum operations in terms of density matrices: • Applying U to yields U U† • Measuring state with respect to the basis 1 , 2 , . . . , d , yields: k th outcome with probability k k —and causes the state to collapse to k k Since these are expressible in terms of density matrices alone (independent of any specific probabilistic mixtures), states with identical density matrices are operationally indistinguishable 9 © Richard Cleve 2020

Return to state distinguishing problems … 10 © Richard Cleve 2020

Return to state distinguishing problems … 10 © Richard Cleve 2020

State distinguishing problems (1) The density matrix of the mixed state (( ψ1 ,

State distinguishing problems (1) The density matrix of the mixed state (( ψ1 , p 1), ( ψ2 , p 2), …, ( ψd , pd)) is: Examples (from earlier in lecture): 1. & 2. 0 + 1 and − 0 − 1 both have 3. 0 with prob. ½ 1 with prob. ½ 4. 0 + 1 with prob. ½ 0 − 1 with prob. ½ 6. 0 1 0 + 1 0 − 1 © Richard Cleve 2020 with prob. ¼ 11

State distinguishing problems (2) Examples (continued): 5. 0 with prob. ½ 0 + 1

State distinguishing problems (2) Examples (continued): 5. 0 with prob. ½ 0 + 1 with prob. ½ has: 7. The first qubit of 01 − 10 . . . ? (later) 12 © Richard Cleve 2020

Characterizing density matrices Three properties of : • Tr = 1 (Tr M =

Characterizing density matrices Three properties of : • Tr = 1 (Tr M = M 11 + M 22 +. . . + Mdd ) • = † (i. e. is Hermitian) • 0, for all states (i. e. is positive semidefinite) Moreover, for any matrix satisfying the above properties, there exists a probabilistic mixture whose density matrix is Exercise: show this 13 © Richard Cleve 2020

Taxonomy of various normal matrices 14 © Richard Cleve 2020

Taxonomy of various normal matrices 14 © Richard Cleve 2020

Normal matrices Definition: A matrix M is normal if M†M = MM† Theorem: M

Normal matrices Definition: A matrix M is normal if M†M = MM† Theorem: M is normal iff there exists a unitary U such that M = U†DU, where D is diagonal (i. e. unitarily diagonalizable) Examples of abnormal matrices: is not even diagonalizable is diagonalizable, but not unitarily eigenvectors: 15 © Richard Cleve 2020

Unitary and Hermitian matrices Normal: with respect to some orthonormal basis Unitary: M†M =

Unitary and Hermitian matrices Normal: with respect to some orthonormal basis Unitary: M†M = I which implies | k |2 = 1, for all k Hermitian: M = M† which implies k ∈ ℝ for all k Question: which matrices are both unitary and Hermitian? Answer: reflections ( k {+1, – 1}, for all k) 16 © Richard Cleve 2020

Positive semidefinite: Hermitian and k 0, for all k Theorem: M is positive semidefinite

Positive semidefinite: Hermitian and k 0, for all k Theorem: M is positive semidefinite iff M is Hermitian and, for all , M 0 (Positive definite: k > 0, for all k) 17 © Richard Cleve 2020

Projectors and density matrices Projector: Hermitian and M 2 = M, which implies that

Projectors and density matrices Projector: Hermitian and M 2 = M, which implies that M is positive semidefinite and k ∈ {0, 1}, for all k Density matrix: positive semidefinite and Tr M = 1, so Question: which matrices are both projectors and density matrices? Answer: rank-1 projectors ( k = 1 if k = j; otherwise k = 0) 18 © Richard Cleve 2020

Taxonomy of normal matrices normal unitary Hermitian Reflection* *through hyperplane positive semidefinite density matrix

Taxonomy of normal matrices normal unitary Hermitian Reflection* *through hyperplane positive semidefinite density matrix projector rank one projector 19 © Richard Cleve 2020

Bloch sphere for qubits 20 © Richard Cleve 2020

Bloch sphere for qubits 20 © Richard Cleve 2020

Bloch sphere for qubits (1) Consider the set of all 2 x 2 density

Bloch sphere for qubits (1) Consider the set of all 2 x 2 density matrices They have a nice representation in terms of the Pauli matrices: Note that these matrices—combined with I—form a basis for the vector space of all 2 x 2 matrices We will express density matrices in this basis Note: coefficient of I must be ½, since X, Y, Z are traceless 21 © Richard Cleve 2020

Bloch sphere for qubits (2) We will express First consider the case of pure

Bloch sphere for qubits (2) We will express First consider the case of pure states , where, without loss of generality, = cos( ) 0 + e 2 i sin( ) 1 ( , [0, π]) Therefore cz = cos(2 ), cx = cos(2 )sin(2 ), cy = sin(2 ) These are polar coordinates of a unit vector (cx , cy , cz) ℝ 3 22 © Richard Cleve 2020

Bloch sphere for qubits (3) 0 + = 0 + 1 – = 0

Bloch sphere for qubits (3) 0 + = 0 + 1 – = 0 – 1 – i + – +i = 0 + i 1 –i = 0 – i 1 +i 1 Note that orthogonal corresponds to antipodal here Pure states are on the surface, and mixed states are inside (being weighted averages of pure states) © Richard Cleve 2020 23

Distinguishing mixed states 24 © Richard Cleve 2020

Distinguishing mixed states 24 © Richard Cleve 2020

Distinguishing mixed states (1) What’s the best distinguishing strategy between these two mixed states?

Distinguishing mixed states (1) What’s the best distinguishing strategy between these two mixed states? 0 with prob. ½ 1 with prob. ½ 0 with prob. ½ 0 + 1 with prob. ½ 1 1 also arises from this orthogonal mixture: + 0 … as does 2 from: 0 0 with prob. cos 2( /8) 1 with prob. sin 2( /8) 0 with prob. ½ 1 with prob. ½ 25 © Richard Cleve 2020

Distinguishing mixed states (2) We’ve effectively found an orthonormal basis 0 , 1 in

Distinguishing mixed states (2) We’ve effectively found an orthonormal basis 0 , 1 in which both density matrices are diagonal: 1 1 + 0 Rotating 0 , 1 to 0 , 1 the scenario can now be examined using classical probability theory: 0 Distinguish between two classical coins, whose probabilities of “heads” are cos 2( /8) and ½ respectively (details: exercise) Question: what do we do if we aren’t so lucky to get two density matrices that are simultaneously diagonalizable? 26 © Richard Cleve 2020

general quantum operations more commonly known as quantum channels 27 © Richard Cleve 2020

general quantum operations more commonly known as quantum channels 27 © Richard Cleve 2020

General quantum operations (1) Also known as: “quantum channels” “completely positive trace preserving maps”,

General quantum operations (1) Also known as: “quantum channels” “completely positive trace preserving maps”, “admissible operations” Let A 1, A 2 , …, Am be matrices satisfying Then the mapping is a general quantum op Note: A 1, A 2 , …, Am do not have to be square matrices Example 1 (unitary op): applying U to yields U U† 28 © Richard Cleve 2020

General quantum operations (2) Example 2 (decoherence): let A 0 = 0 0 and

General quantum operations (2) Example 2 (decoherence): let A 0 = 0 0 and A 1 = 1 1 This quantum op maps to 0 0 + 1 1 For ψ = 0 + 1 , Corresponds to measuring “without looking at the outcome” After looking at the outcome, becomes 0 0 with prob. | |2 1 1 with prob. | |2 29 © Richard Cleve 2020

General quantum operations (3) Example 3 Let A 0 = I 0 • Any

General quantum operations (3) Example 3 Let A 0 = I 0 • Any state of the form • State and A 1 = I 1 (product state) becomes It’s the same density matrix as for ((½ , 0 ), (½ , 1 )) • Corresponds to “discarding the second register” The operation is called the partial trace Tr 2 30 © Richard Cleve 2020