Impulse and Momentum Unit 9 Impulse Application of
- Slides: 14
Impulse and Momentum Unit 9
Impulse Application of force during a small amount of time n Applies to COLLISIONS n – Ball and bat – Racket and ball – Karate – Car on car – Airbags, yellow barrels on highway
Newton’s 2 nd Law applies to all forces: SF = ma SF = m. Dv/Dt SFDt = m. Dv Left side SFDt is defined as IMPULSE Right side m. Dv is defined as MOMENTUM (p)
Impulse is the area under the F-t curve
SFDt = m. Dv Impulse = change in momentum n A net force applied in a time span will cause a change of velocity or acceleration n This restates Newton’s 2 nd law n
Momentum by itself is not interesting, but a change of momentum is! Dp = m. Dv How do you do this? 1. Change velocity 2. Change mass 3. Change both mass and velocity
You can also change impulse to create a change in momentum. Dp = FDt How do you do this? 1. Change force 2. Change time 3. Change both force and time
Example 1: Changing momentum n n n Ex. – hitting a ball -pushing a car -rocket engines -hit a ball BIG force x BIG time = BIG D in momentum Small force x small time = small D in momentum
Example 2: Decreasing momentum over a LONG time n Ex. – airbags -bending knees -landing mats -circus safety nets -yellow water barrels on roads Car accident: Dp is same whether you hit a wall or a barrel Not safe F wt w = F b t b Safer Increasing IMPACT TIME reduces impact force
Example 3: Decreasing momentum in a SHORT time n Why would you want to lessen impact time to increase impact force?
Example 3: Decreasing momentum in a SHORT time n Why would you want to lessen impact time to increase impact force? Discovermagazine. com
What? ? n n Hand motion has large momentum as it approaches bricks (large Vi) In hitting bricks, your hand experiences a large change of momentum (Vf = 0) By bouncing hand off impact you REDUCE time of impact to a small amount Result: Decreasing IMPACT TIME increases impact force
Why does bouncing create BIGGER impact force? FOLLOW THROUGH Vi = -10 m/s 1 kg board BOUNCE OFF Vi = -10 m/s 1 kg board Vf = -5 m/s Vf = +10 m/s FD t = m D v F=(1 kg)(5 m/s)/0. 01 s F=500 N FD t = m D v F=(1 kg)(20 m/s)/0. 01 s F=2000 N
Summary: Impulse = FDt Impulse is area under F vs. t graph Momentum p = mv Impulse = change in momentum FD t = m D v = D p
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