Ideal Gas Law Perfect gas molecules Ideal Gas

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Ideal Gas Law Perfect gas molecules

Ideal Gas Law Perfect gas molecules

Ideal Gas Law For every problem we have done, we also could have used

Ideal Gas Law For every problem we have done, we also could have used the ideal gas law. We could treat each gas molecule like a perfect sphere. Each atom or molecule has almost no volume. Each atom or molecule would have an elastic collision with each other like billiard balls.

Ideal gas law can be derived from the combined gas law n (22. 4

Ideal gas law can be derived from the combined gas law n (22. 4 L) = Volume of any gas at STP (n is the number of moles) plug this into combined gas law for initial state. PV/T = PV/T (using k. Pa for pressure) PV/T = (101. 2 k. Pa) (n • 22. 414 L) / 273 K PV = n (8. 31 k. Pa • L/K mol) T 8. 31 k. Pa • L/K mol is the ideal gas constant for these units. It is abbreviated “R”

The equation PV = n. RT *R can also be. 0821 atm • L/K

The equation PV = n. RT *R can also be. 0821 atm • L/K mol The units of R must match the other units in the problem. If you are using 8. 31 k. Pa • L/K mol, your units are: k. Pa(L) = mol (8. 31 k. Pa • L/K mol) K

Idea Gas Law Assumes: • Each gas molecule or atom has no attractive or

Idea Gas Law Assumes: • Each gas molecule or atom has no attractive or repulsive force with one another. • Each gas molecule or atom has an elastic collision with one another. • Momentum is conserved.

Converting pressures Use the standard pressures as a conversion factor 1. 00 atm =

Converting pressures Use the standard pressures as a conversion factor 1. 00 atm = 101 k. Pa = 760. torr convert 135 k. Pa to atm 135 k. Pa x 1 atm / 101 k. Pa = 1. 34 atm convert 768 torr to k. Pa 768 torr x 101 k. Pa / 760 torr = 102 k. Pa

Using the ideal gas law What volume will. 76 mol of a gas occupy

Using the ideal gas law What volume will. 76 mol of a gas occupy at. 82 atm and 264 K? . 82 atm x 101 k. Pa / 1. 00 atm = 82. 82 k. Pa PV = n. RT 82. 82 k. Pa V = 0. 76 mol (8. 31 k. Pa • L/K mol )264 K V = 20. L

Ideal Gas Law Problem If a gas occupies 14 L at 135 k. Pa

Ideal Gas Law Problem If a gas occupies 14 L at 135 k. Pa and 285 K, what volume will it occupy at STP? 135 k. Pa (14 L) = n 8. 31 k. Pa • L/K mol (285 K) n =. 798 mol x 22. 4 L / 1 mol = 18 L

or you can also take the. 798 mol and plug it back into PV

or you can also take the. 798 mol and plug it back into PV = n. RT (you would have to do this if you were not going to STP) 101 k. Pa V= (. 798 mol) 8. 31 (273 K) V = 18 L (still)

Homework Problem If a gas occupies 34 L at 115 k. Pa and 290

Homework Problem If a gas occupies 34 L at 115 k. Pa and 290 K, what volume will it occupy at STP? solve for n then use Avogadro’s law to determine its volume at STP You MUST use the IDEAL GAS LAW not the combined gas law to receive credit for this problem