HW 5 Tutorial 5 WRF Chapter 19 WWWR

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HW # 5 /Tutorial # 5 WRF Chapter 19; WWWR Chapter 20 ID Chapters

HW # 5 /Tutorial # 5 WRF Chapter 19; WWWR Chapter 20 ID Chapters 7 -9 • Tutorial # 5 • WRF#19. 3; WRF#19. 8; WWWR #20. 13, ; WRF#19. 23, WWWR#20. 42. • To be discussed during the week 17 Feb. – 21 Feb. , 2020. • By either volunteer or class list. • Homework # 5 (Self practice). • WRF#19. 4; WRF#19. 25 • ID# 7. 24, 7. 35. • Correction: #20. 42: Table: Unit for Cp should be corrected from J/kg-K to k. J/kg-K.

Convective Heat Transfer Correlations

Convective Heat Transfer Correlations

Natural Convection

Natural Convection

Horizontal Plates Mc. Adam’s Correlations: Hot surface facing up or cold surface surfacing down

Horizontal Plates Mc. Adam’s Correlations: Hot surface facing up or cold surface surfacing down H C C H

Horizontal Cylinders g

Horizontal Cylinders g

In each of the correlations to follow the temperature of the hotter of the

In each of the correlations to follow the temperature of the hotter of the two large surfaces is designed in T 1, and the cooler surface is at temperature T 2. Fluid properties are evaluated at the film temperature, Tf = (T 1 + T 2) / 2. Convective heat flux is expressed as q = h(T - T ) 1 2 A

Example 1

Example 1

H H

H H

Initial Guess T = 385 K, Resulting T=381. 1 K Second Iteration

Initial Guess T = 385 K, Resulting T=381. 1 K Second Iteration

Forced Convection For Internal Flow

Forced Convection For Internal Flow

Turbulent Flow

Turbulent Flow

Example 2 Hydraulic fluid (MIL-M-5606), in fully developed flow , flows through a 2.

Example 2 Hydraulic fluid (MIL-M-5606), in fully developed flow , flows through a 2. 5 cm diameter copper tube that is 0. 61 m long, with a mean velocity of 0. 05 m/s. The oil enters at 295 K. Steam condenses on the outside tube surface with an effective heat transfer coefficient of 11400 W/m 2 -K. Find the rate of heat transfer to the oil. Ro Rc 295 K Ri Rc << Ro, Ri

Ro Example 2 Rc 295 K =(295+305)/2 Ri 305 K? Rc << Ro, Ri

Ro Example 2 Rc 295 K =(295+305)/2 Ri 305 K? Rc << Ro, Ri

=373 -(373 -300)*[98. 1/(98. 1+11400)] =372. 3 K

=373 -(373 -300)*[98. 1/(98. 1+11400)] =372. 3 K

Example 3

Example 3

Forced Convection For External Flow Parallel To Plane Surface

Forced Convection For External Flow Parallel To Plane Surface

Cylinders In Crossflow

Cylinders In Crossflow

Tube Banks In Crossflow SL : Center-to-center distance between tubes along the direction of

Tube Banks In Crossflow SL : Center-to-center distance between tubes along the direction of flow ST: Center-to-center distance between tubes normal to the direction of flow

Adapted from ID Page 437

Adapted from ID Page 437