Graphing exercise Phet Simulation Using the Phet Simulation

Graphing exercise Phet Simulation

Using the Phet Simulation x

A person is moving at a constant rate of 2 m/s from a 0 position with no acceleration. Draw the following graphs for the first 7 seconds Time 0 1 2 3 4 5 6 7 Displacement

To fill in the displacement column, we need to use the d = v*t equation. Time d = 2 m/s * 1 s = 2 meters d = 2 m/s * 2 s = 4 meters d = 2 m/s * 3 s = 6 meters d = 2 m/s * 4 s = 8 meters d = 2 m/s * 5 s = 10 meters d = 2 m/s * 6 s = 12 meters d = 2 m/s * 7 s = 14 meters 0 Displacement 0 1 2 2 4 3 6 4 8 5 10 6 12 7 14

Using excel, connected scattered 16 14 12 10 8 Series 1 6 4 2 0 0 1 2 3 4 5 6 7 8

For the velocity vs. time graph, Time Velocity 0 2 2 1, 5 2 2 1 3 2 4 2 5 2 6 2 7 2 2, 5 Series 1 0, 5 0 0 2 4 6 8

For the acceleration vs. time graph Time Acceleration 0 0 1 0 2 0 3 0 4 0 5 0 6 0 7 0

2. A person is moving with an initial 2 m/s from a 0 position with constant 1 m/s 2 acceleration. For this problem you have to use the equation d = d 0 + vit + ½ at 2 Our d 0 is the starting point which is 0.

d = vit + ½ at 2 d = 2(0) + ½ (1)(0)2 = 0 d = 2(1) + ½ (1)(1)2 = 2. 5 Repeating the process d=6 d = 10. 5 d = 16 d = 22. 5 d = 30 d = 38. 5 Time Displacement 0 0 1 2. 5 2 6 3 10. 5 4 16 5 22. 5 6 30 7 38. 5

Using vf = vi + at vf = 2 + (1)(0) = 2 vf = 2 + (1)(1) = 3 vf = 2 + (1)(2) = 4 vf = 2 + (1)(3) = 5 vf = 2 + (1)(4) = 6 vf = 2 + (1)(5) = 7 vf = 2 + (1)(6) = 8 vf = 2 + (1)(7) = 9

Time Velocity 0 2 1 3 2 4 3 5 4 6 5 7 6 8 7 9 10 9 8 7 6 5 4 3 2 1 0 Series 1 0 2 4 6 8

Time Acceleration 0 1 1 1 2 1 3 1 4 1 5 1 6 1 7 1 1, 2 1 0, 8 0, 6 Series 1 0, 4 0, 2 0 0 2 4 6 8

A person is moving from an initial position of -5 m with a constant velocity of 3 m/s and an acceleration of -0. 25 m/s 2. Draw the following graphs for the first 7 seconds. Using the earlier methods, complete this problem.

Displacement vs. time 0 1 2 3 4 5 6 7 -5 -2. 125 0. 5 2. 875 5 6. 875 8. 5 9. 875 12 10 8 6 4 Series 1 2 0 0 -2 -4 -6 1 2 3 4 5 6 7 8