General Genetics Human karyotype Objectives 1 Students will

General Genetics Human karyotype

Objectives: 1. Students will be able to demonstrate a microtechnique for reliable chromosomal analysis of leucocytes obtained from blood. 2. Students will be able to prepare a karyotype from the chromosomes of a normal human male or female. 3. Students will be able to use the karyotyping techniques for diagnosing a chromosomal disorder.

INTRODUCTION: Chromosomal aberrations are abnormalities in the number or microscopically chromosomes. observable structure of The “normal” human diploid cell has 23 pairs of chromosomes visible only at the metaphase stage of mitosis, 22 homologous pairs of autosomes and two sex chromosomes.

Cont. Each chromosome has a characteristic size and shape in the “normal” cell. Chromosome pair #1 contains the largest chromosomes, while the Y chromosome is the smallest. Chromosomes of similar size and morphology are grouped together by letter; the chromosomes can be arranged in 7 groups (A, B, C, D, E, F, G). Group A contains pairs #1, #2, and #3 chromosomes.

Karyotyping is a technique that allows for the visualization and identification of human metaphase chromosomes. This technique can be used to assess the “normalcy” of an individual’s chromosomes and to assay for various genetic diseases such as Down’s syndrome and Klinefelter’s syndrome …etc.

Cont. It is estimated that one in 156 live births have some kind of chromosomal abnormality. To create a karyotype, chromosomes from a cell are arranged, stained and photographed. The photograph is enlarged and cut up into individual chromosomes. The homologous chromosomes can be distinguished by length and by the position of the centromer.

Cont. A chromosome is divided by its centromer into short arm (p) and long arm (q). chromosomes can be classified by the position of their centromer: 1. Metacentric: If its two arms are equal in length. 2. Submetacentric: If arms' lengths are unequal. 3. Acrocentric: If the p arm is so short that is hard to observe, but still present.

If there are chromosomal number abnormalities, how do they form? • Meiosis: the process of creating sperm or egg from a diploid cell • If there is a mistake when chromosomes are separating, then the resulting sperm or egg will have too many or too few chromosomes.

Meiosis 1

Meiosis II Prophase II Metaphase II Anaphase II Meiosis I results in two The chromosomes line up in a The sister chromatids haploid (N) daughter cells, similar way to the metaphase separate and move toward each with half the number of stage of mitosis. opposite ends of the cell. chromosomes as the original. Telophase II Meiosis II results in four haploid (N) daughter cells.

Nondisjunction

What other chromosomal disorders can arise? • • Deletion Inversion Translocation* Duplication *Don’t worry about this one.

Chromosomal mutations Deletion Duplication Inversion Translocation

Problems with chromosomes • Duplication: copied parts of chromosome A A B B C B D B C D

Problems with chromosomes • Deletion: missing parts of chromosome A A B D C D

Problems with chromosomes • Inversion: parts of chromosome tched A A B C C B D D

A blood sample is taken and white blood cells grown in special medium for three days under the influence of the mitotic stimulant ( phytohemagglutinin " PHA " ) to enter into mitosis by DNA replication. After 68 -72 hours, a mitotic inhibitor ( Cholchicin ) is added to the culture to stop mitosis in the metaphase stage. After treatment by hypotonic solution ( KCl ) to causes a swelling of the cells and allow dispersion of the chromosomes within the cell membrane.

Cont. Fixation is used as wash solution to lyses the remaining red cells and remove some chromosomes protein. After staining by Giemsa Staine, chromosomes can be microscopically observed and evaluated for abnormalities.

Metirals Required: Heparinzed whole blood Heparin sodium injection Peripheral blood Karyotyping medium with PHA (RPMI 1640) Incubator 5%CO 2 at 37ºC Colcemide solution 10µg/ml 0. 075 M kcl Fixative solution ( 3 x methanol : 1 x glacial acetic acid ) Giemsa stain solution Slides and Microscope

Karyotyping procedure: 1. Inoculate 0. 5 ml of heparinized whole blood into tube with 10 ml of karyotyping medium. 2. Incubate the tubes in incubator with 5% CO 2 at 37ºC for total of 72 hours. 3. After total of 69 hours from seeding add 100μl of Colcemid Solution to each culture tubes. 4. Incubate the tubes at 37 o. C for an additional 20 -30 minutes. 5. Spin at 500 g (1500 rpm) for 7 minutes.

Cont. 6. Remove the supernatant and re-suspend the cells in 5 ml of hypotonic 0. 075 M KCl pre wormed to 37ºC. 7. Incubate at 37 o. C for 15 minutes. 8. Add drop-by- drop (with vortexing) 1 ml fresh ice cold fixative. 9. Spin at 500 g (1500 RPM) for 7 minutes. 10. Remove the supernatant, agitate the cellular sediment and add drop-by- drop (with continous vortexing), 5 ml of fresh, ice-cold fixative. 11. Leave at 4ºC for 20 minutes. 12. Repeat steps 9 and 10, until the supernatant is clear. 13. Spine at 500 g (1500 RPM) for 7 minutes.

Cont. 14. Re-suspend the cell pellet with a 1. 5 ml of fresh fixative. 15. Drop 4 -5 drops, from ahigh of approximately 30 cm onto aclean slide and blow carefully on the drops for spreading them on the slide. 16. Put the slides on a 45ºC heated plate for 2 -4 minutes. 17. Heat the slides to 60 ºC for overnight or to 90 ºC for 90 minutes. 18. Place the slides and flood them with Giemsa stain solution for 8 minutes. 19. Gently rinse the slides in distilled water and air dry. 20. Observe the chromsomes under microscope by using 10, 40 and 100 x and photograph it and cut each chromosome from the photograph and arrange the chromosomes according to the size and position of centomer.