GCF remaining factor Factor the following 1 8

GCF( remaining factor) Factor the following. 1) 8 x + 32 = 8 (x + 4) 2) 10 x – 35 = 5 ( 2 x – 7 ) 3) x 2 – 9 x = x (x – 9) 4) 6 x 2 + 12 x = 6 x ( x + 2 ) = 2 x 2 ( 7 x + 10 ) 5) 14 x 3 + 20 x 2

14. 03 Factoring 2 x + bx + c c>0

Find two numbers whose product is 12 and whose sum is 8 2 and 6 whose product is 48 and whose sum is 14 6 and 8 whose product is 6 and whose sum is – 5 – 2 and – 3 whose product is 36 and whose sum is – 13 – 4 and – 9

Trinomials of the form x 2 + bx + c will factor into 2 binomials whose 1 st terms are x and whose 2 nd terms are two numbers whose product is “c” and whose sum is “b”. x 2 + bx + c = ( x + d )( x + e ) where d · e = c and d + e = b Factor x 2 + 8 x + 12 ( x + 2 )( x + 6 ) The 1 st terms in each binomial is x The 2 nd terms are two numbers whose product is 12 and whose sum is 8.

x 2 + bx + c = ( x + d )( x + e ) where d · e = c and d + e = b Factor x 2 + 12 x + 27 ( x + 3 )( x + 9 ) Factor x 2 – 9 x + 20 ( x – 4 )( x – 5 ) Factor x 2 + 10 x + 9 ( x + 9 )( x + 1 )

Try This: x 2 + bx + c = ( x + d )( x + e ) d · e = c and d + e = b Factor the following trinomials. x 2 + 5 x + 6 = ( x + 2 )( x + 3 ) x 2 – 15 x + 54 = ( x – 6 )( x – 9 ) x 2 + 15 x + 36 = ( x + 3 )( x + 12 ) x 2 – 11 x + 24 = ( x – 3 )( x – 8 ) x 2 + 19 x + 48 = ( x + 3 )( x + 16 )