Gas Laws The Kinetic Molecular Theory Gas particles

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Gas Laws

Gas Laws

The Kinetic Molecular Theory • Gas particles do not repel or attract each other.

The Kinetic Molecular Theory • Gas particles do not repel or attract each other. • Gas particles are much smaller than the distances between them. • Gas particles are in constant, random motion. • No kinetic energy is lost when gas particles collide. • All gases have the same kinetic energy at a given temperature.

Pressure • Pressure is force applied over an area. • For gases, the pressure

Pressure • Pressure is force applied over an area. • For gases, the pressure is determined by the number of collisions with the walls of the container. • Units: – atm: atmospheres – k. Pa: kilo. Pascal (= 1 N/m 2) – mm. Hg: millimeters of mercury – psi: pound force per square inch

The variables and their units Variable Symbol Units Pressure P atm Volume V Liters

The variables and their units Variable Symbol Units Pressure P atm Volume V Liters Amount of gas n Moles Temperature T Kelvin

Conversion Factors Conversion for Pressure 1 Torr = 1 mm Hg

Conversion Factors Conversion for Pressure 1 Torr = 1 mm Hg

Conversion Factors Conversion for Temperature

Conversion Factors Conversion for Temperature

STP

STP

The Relationships before Copy in color: after 10 x 4 = 8 x ?

The Relationships before Copy in color: after 10 x 4 = 8 x ? ? • What is the missing number? • From before to after: – How did the red number change? – How did the black number change? • What is the math term for this relationship? • Which two gas variables have this type of relationship?

The Relationships Inversely proportional 10 x 4 = 8 x ? ? Pressure and

The Relationships Inversely proportional 10 x 4 = 8 x ? ? Pressure and volume P 1 V 1 = P 2 V 2

The Relationships before Copy in color: ? 6 after = 16 48 • What

The Relationships before Copy in color: ? 6 after = 16 48 • What is the missing number? • From before to after: – How did the red number change? – How did the black number change? • What is the math term for this relationship? • Which two gas variables have this type of relationship?

The Relationships Directly proportional ? 6 = 16 48 Pressure and Temperature Volume and

The Relationships Directly proportional ? 6 = 16 48 Pressure and Temperature Volume and amount of gas

The Combined Gas Law if every gas variable changed, this is the relationship Things

The Combined Gas Law if every gas variable changed, this is the relationship Things that don’t change cancel or drop out.

The Combined Gas Law if every gas variable changed, this is the relationship Simplifies

The Combined Gas Law if every gas variable changed, this is the relationship Simplifies to If amount of gas and volume stay the same, they cancel or drop out.

The Combined Gas Law if every gas variable changed, this is the relationship Simplifies

The Combined Gas Law if every gas variable changed, this is the relationship Simplifies to P 1 V 1 = P 2 V 2 If amount of gas and temperature stay the same, they cancel or drop out.

Let’s Practice T 1 V 1 At 20°C, the volume of a gas is

Let’s Practice T 1 V 1 At 20°C, the volume of a gas is 100. 0 m. L. T 2 The temperature is raised to 100°C. How do you expect the volume to change? It should increase Simplify the Combined Gas Law for this scenario. Simplifies to

Let’s Practice T 1 V 1 At 20°C, the volume of a gas is

Let’s Practice T 1 V 1 At 20°C, the volume of a gas is 100. 0 m. L. +273 = 293 K T 2 The temperature is raised to 100°C. +273 = 373 K V 2 = 127 m. L Does this match your prediction? You said it would increase.

Let’s Practice V 1 P 1 50. 0 m. L of a gas has

Let’s Practice V 1 P 1 50. 0 m. L of a gas has a pressure of 740. 0 mm. Hg when it is in a container. P 2 The pressure changes to 760. 0 mm. Hg. How do you expect the volume to change? It should decrease Simplify the Combined Gas Law for this scenario. Simplifies to P 1 V 1 = P 2 V 2

Let’s Practice V 1 P 1 50. 0 m. L of a gas has

Let’s Practice V 1 P 1 50. 0 m. L of a gas has a pressure of 740. 0 mm. Hg when it is in a container. P 2 The pressure changes to 760. 0 mm. Hg? P 1 V 1 = P 2 V 2 (740. 0 mm. Hg)(50. 0 m. L) = (760. 0 mm. Hg)V 2 48. 7 m. L = V 2 Does this match your prediction? You said it would increase.