FORMWORK DR Nabil Dmaidi Formwork Forms are molds
FORMWORK DR. Nabil Dmaidi
Formwork Forms are molds to receive concrete in its plastic form. n Formwork is a temporary structure; as such, it is not normally shown on the drawings. n DR. Nabil Dmaidi
Formwork for Beams and Slabs DR. Nabil Dmaidi
Formwork Materials n Wood – Either all-wood or some wood components Plywood n Aluminum n Steel n Plastics n DR. Nabil Dmaidi
Lumber n Designated by Cross Sections, Nominal Dimensions (prior to finishing) – After cut length wise, finishing operations reduces actual dimensions n 1 1/2 x 3 1/2 2” by 4” in S 4 S 2 x 4 Plank – Lengths are multiples of 2 ft (8, 10, 12, 14, 16, …) – Specified by type and grade – n Type: pine, oak, fir n Grade: Selected (A, B, C, D) and Common (1, 2, 3, 4) n Selected (A best, D poor quality) Cost Kind, grade, size, length, milling, quantity, freight DR. Nabil Dmaidi
Plywood n 4 ft wide - 8, 10, 12 ft long n 3/4 , 5/8 , 1/2 , 3/8 , 1/4 inch thick DR. Nabil Dmaidi
Plywood Orientation Weak Orientation of Plywood Strong Orientation of Plywood (Face grain parallel to span) (Face grain perpendicular to span) Face Grain Direction DR. Nabil Dmaidi Face Grain Direction
Aluminum Pure aluminum chemically attacked by wet concrete n Light weight allows larger forming units n High reuse value n Aluminum beam “nailer - type” DR. Nabil Dmaidi
Steel For heavy concrete work n With reasonable care will last indefinitely n High initial cost and high handling cost n DR. Nabil Dmaidi
Estimating Issues n Normally, the forms are used more than once n More usage of forms reduces the price n Wood forms have less usage potential than aluminum or steel forms n Complicated shapes of concrete are more expensive because of labor cost and reuse of forms. DR. Nabil Dmaidi
Estimating Issues (cont. ) Majority of cost is _____? ? Not ____? ? n You have to have a construction plan to determine the reuse cycle n Number of reused largely controls _____? ? Cost. n DR. Nabil Dmaidi
Effect of Reuse on Concrete Formwork Cost DR. Nabil Dmaidi
Estimating Issues (Formwork) n Do not deduct – – – Intersection of beams & columns & walls Any opening < 100 sq. ft. DR. Nabil Dmaidi
Formwork n n Unit of Measurement Square Foot Contact Area SFCA Measure just contact area, not area of formwork Contact Area = 2 h(L+B) h Concrete B DR. Nabil Dmaidi L
Wood normally measured: n Linear feet of one size n Board Feet – – FBM (Foot Board Measure) 1”x 12”x 1’(long) or 144 cubic inches example: 2 x 8 x 16 ft long ” 2 x 8” = 1. 33 BF/LF x 16 = 21. 28 FBM ” 12 DR. Nabil Dmaidi
Additional Costs n Nails – – n Form Oil – n For first use, 10 - 20 lb. Per 1000 fbm Additional used, 5 - 10 lb. Per fbm 300 - 500 ft 2/gal Ties – – – Ties keep forms apart and resist bursting pressure of concrete Stay in concrete, pull out Types: n n Steel bands Rods Threaded w/ Nuts and clamps DR. Nabil Dmaidi
Design and Estimating of Forms “Design determines Sheathing thickness, stud size, wale size, tie size” n Use of design tables n Watch for n 1. Rate of pour 2. Temperature and weather 3. Proportions of mix and consistency 4. Method of placement and vibration DR. Nabil Dmaidi
Workshop Example Estimate the cost of formwork for concrete wall (9’ 6” x 25’ 4”) n The rate of placing concrete = 4 ft/hour n Maximum temperature of concrete = 70ºF n DR. Nabil Dmaidi
Wall tie 2 - 2”x 4” wale ” 2 x 4”x 10’- 0 “ stud ” 3/4 plywood sheathing ” 6’ 9 ” 2 x 4” x 10’- 0” brace @ 6’- 0” Concrete Footing ” 4’ 25 ” 2 x 4” sill ” 2 x 4”x 3’- 0” Stake @ 6’- 0” Section through the Wall Side Elevation DR. Nabil Dmaidi
Design of Forms for concrete Walls DR. Nabil Dmaidi
The wall is 9’-6” high and 25’-4” long. n From design table: Max. pressure, 664 lb/ft 2 Max. spacing of studs, 19 in, use 18 in Max. spacing of wales, 25 in, use 24 in Max. spacing of form ties, 31 in n n The 3/4“ plywood sheathing will be placed with the 4 ft wide in the vertical direction and the 8 ft length in the horizontal direction. The total quantity of sheathing will be: No. sheets in vertical direction, 9’-6” 4‘/sheet = 2. 37, use 3 sheets No. sheets in horizontal direction, 25’-4” 8’/sheet = 3. 16, use 4 sheets No. sheets required per side, 3 x 4 = 12 No. sheets required for wall, 12 x 2 = 24 DR. Nabil Dmaidi
n Studs required: Length of wall, (25 x 12)+4 Spacing of studs, 18 in No. studs required per side, (304/18)+1 No. studs required for wall, 2 x 18 Lumber required, 36 pc, 2 x 4 x 10 ft n = 304 in = 18 = 26 = 240 fbm Wales required: Height of wall, 114 in Spacing of wales, 24 in No. required per side, 114/24 = 4. 75, use 5 wales For each wale, use 2 pc of 2 x 4 x 12 ft and 2 pc of 2 x 4 x 14 ft lumber n Lumber required: 20 pc, 2 x 4 x 12 ft = 160 fbm 20 pc, 2 x 4 x 14 ft = 187 fbm DR. Nabil Dmaidi
Total lumber = 240 + 160 +187 = 587 fbm n Add 10 to 20% for misc. (sills, splice…etc) Total quantity of lumber = 587 + 0. 2 x 587 = 704 fbm DR. Nabil Dmaidi
Number of ties needed If we use 4000 lb ties 644 x 9. 5 x 25. 3 Number of ties = 4000 = 51 ties DR. Nabil Dmaidi
Quantity of Nails = 704 x 10 lb/1000 fbm = 7. 04 lbs DR. Nabil Dmaidi
Summary of Materials to Build forms: Plywood required = 24 sheets n Lumber required = 704 fbm n Nails required = 7 lbs n Ties required = 51 n DR. Nabil Dmaidi
- Slides: 27