FORMULAS Definitions Area PerimeterCircumference Surface Area Volume Distance

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FORMULAS

FORMULAS

Definitions Area Perimeter/Circumference Surface Area Volume Distance / Rate Simple Interest Density

Definitions Area Perimeter/Circumference Surface Area Volume Distance / Rate Simple Interest Density

Distance = Rate x Time How far did you travel if you drove at

Distance = Rate x Time How far did you travel if you drove at a rate of 60 miles per hour for 5 hours? D = rt D = 60 x 5 D = 300 Answer: 300 miles

Time = Distance / Rate How much time did it take for you to

Time = Distance / Rate How much time did it take for you to travel 300 miles at a rate of 60 miles per hour? T = D/r T = 300 / 50 D = 5 Answer: 5 hours

D = rt Find D if r = 12 and t = 8 D

D = rt Find D if r = 12 and t = 8 D = rt D = 12 x 8 D = 96 Find r if D = 240 and t = 8 D = rt 240 = r x 8 Solve backwards 240 / 8 = r 30 = r D = rt 240 = 8 r 8 8 30 = r

Simple Interest I = PRT Interest = Principle x Rate x Time How much

Simple Interest I = PRT Interest = Principle x Rate x Time How much interest would you make if you deposited $500 at the bank at a rate of 10% per year for 4 years? I = 500 x. 10 x 4 I = $200

Simple Interest I = PRT Interest = Principle x Rate x Time How much

Simple Interest I = PRT Interest = Principle x Rate x Time How much time did you keep your money in the bank if you made $400 in interest at a rate of 5% with an initial deposit of $800 ( principle)? 400 = 800 x. 05 x t 400 = 40 x t 401400 / 40 = 10 years

Simple Interest I = PRT How much time did you keep your money in

Simple Interest I = PRT How much time did you keep your money in the bank if you made $400 in interest at a rate of 5% with an initial deposit of $800 ( principle)? I = PRT 400 = 800 x. 05 x t 400 = 40 t 401400 = 402 40 403 10 40 t 40 = t

Circumference of a Circle PI TIMES DIAMETER PI TIMES DOUBLE THE RADIUS 3. 14

Circumference of a Circle PI TIMES DIAMETER PI TIMES DOUBLE THE RADIUS 3. 14 d

Circumference of a Circle C = 3. 14 d Find C if d =

Circumference of a Circle C = 3. 14 d Find C if d = 10 31. 4 units Find C if d = 5 15. 7 units Find C if r = 5 31. 4 units

Circumference of a Circle C = 3. 14 d Find d if C =

Circumference of a Circle C = 3. 14 d Find d if C = 400 20 units Substitute 400 for C C = 3. 14 d Solve backwards 400 = 3. 14 d 3. 14 times what is 400 = 3. 14 d Divide 400 by 3. 14 4013. 14 20 = d

Area of a Circle PI TIMES RADIUS TO SECOND POWER A = 3. 14

Area of a Circle PI TIMES RADIUS TO SECOND POWER A = 3. 14 r 2 A = 3. 14 x r

Area of a Circle A = 3. 14 r Find A if r =

Area of a Circle A = 3. 14 r Find A if r = 10 Find A if r = 5 Find A if r = 20 314 2 square units 78. 5 square units 1256 square units

Area of a Circle A = 3. 14 r 2 Find r if A

Area of a Circle A = 3. 14 r 2 Find r if A = 2826 sq units 2826 = 3. 14 x r 2 30 units A = 3. 14 r 2 Work backwards 2826= 3. 14 r 2 Undo operations 28272826 Step by step 3. 14 Divide by 3. 14 900 Square Root 901 30 = 3. 14 r 2 3. 14 = r 2 = r

Surface Area of a Rectangular Prism SA is double the area of the front

Surface Area of a Rectangular Prism SA is double the area of the front + double the area of the side + double the area of the top SA = 2 lw + 2 lh + 2 wh

SA = 2 lw + 2 lh + 2 wh H = 6 cm

SA = 2 lw + 2 lh + 2 wh H = 6 cm W = 5 cm L = 10 cm SA = 280 square centimeters

Surface Area Hint: 6 cm use every combination 5 cm 10 cm SA =

Surface Area Hint: 6 cm use every combination 5 cm 10 cm SA = 2 lw + 2 lh + 2 wh SA = 2*10*5 + 2*10*6 + 2*5*6 SA = + + 100 120 60 SA = 280 square centimeters

Surface Area

Surface Area

Volume of a Rectangular Prism V = lwh H = 6 inches W =

Volume of a Rectangular Prism V = lwh H = 6 inches W = 4 inches L = 25 inches 600 cubic inches

Volume 6 inches 25 inches V = 4 inches lwh V = 25 *

Volume 6 inches 25 inches V = 4 inches lwh V = 25 * 4 * 6 V = 600 cubic inches

Volume of a Rectangular Prism

Volume of a Rectangular Prism

Density = Mass / Volume Take a look at the two boxes above. Each

Density = Mass / Volume Take a look at the two boxes above. Each box has the same volume. If each ball has the same mass, which box would weigh more? Why? The box that has more balls has more mass per unit of volume. This property of matter is called density. The density of a material helps to distinguish it from other materials. Since mass is usually expressed in grams and volume in cubic centimeters, density is expressed in grams/cubic centimeter.

Density = Mass / Volume 6 cm 5 cm 4 cm 1. Calculate Volume:

Density = Mass / Volume 6 cm 5 cm 4 cm 1. Calculate Volume: V = lwh V = 120 cc 2. Calculate Mass: 3. Each marble weighs 10 grams Box 1 contains 24 marbles M = 240 g Box 2 contains 12 marbles M = 120 g

Density = Mass / Volume 6 cm 5 cm 4 cm Calculate Density: Volume

Density = Mass / Volume 6 cm 5 cm 4 cm Calculate Density: Volume = 120 cc D = M/V Mass 1 = 250 g D = 240/120 Mass 2 = 130 g D = 120/120 D=2 D=1