FiveMinute Check over Chapter 4 CCSS ThenNow New

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Five-Minute Check (over Chapter 4) CCSS Then/Now New Vocabulary Concept Summary: Properties of Exponents

Five-Minute Check (over Chapter 4) CCSS Then/Now New Vocabulary Concept Summary: Properties of Exponents Key Concept: Simplifying Monomials Example 1: Simplify Expressions Example 2: Degree of a Polynomial Example 3: Simplify Polynomial Expressions Example 4: Simplify by Using the Distributive Property Example 5: Real-World Example: Write a Polynomial Expression Example 6: Multiply Polynomials

Over Chapter 4 Find the x-coordinate of the vertex of f(x) = 5 x

Over Chapter 4 Find the x-coordinate of the vertex of f(x) = 5 x 2 + 15 x + 1. A. B. C. D. – 3

Over Chapter 4 Write a quadratic equation with roots of – 3 and Write

Over Chapter 4 Write a quadratic equation with roots of – 3 and Write the equation in the form ax 2 + bx + c = 0, where a, b, and c are integers. A. 12 x 2 + 4 x – 3 = 0 B. 4 x 2 + 9 x – 9 = 0 C. 3 x 2 + 7 x – 4 = 0 D. –x 2 + 4 x + 3 = 0 .

Over Chapter 4 Find the exact solutions for –x 2 + 8 x –

Over Chapter 4 Find the exact solutions for –x 2 + 8 x – 12 = 0 using the method of your choice. A. 2, 6 B. 1, 3 C. – 1, 2 D. – 3, 2

Over Chapter 4 Find the number of seconds it will take an object to

Over Chapter 4 Find the number of seconds it will take an object to land on the ground if it is dropped from a height of 300 feet, assuming there is no air resistance. Use the equation h(t) = – 16 t 2 + h 0, where h(t) is the height of the object in feet at the time t, t is the time in seconds, and h 0 is the initial height in feet. Round to the nearest tenth, if necessary. A. 16. 9 s B. 12. 6 s C. 7. 4 s D. 4. 3 s

Over Chapter 4 Find the solution to the quadratic inequality x 2 + 3

Over Chapter 4 Find the solution to the quadratic inequality x 2 + 3 x ≤ 54. A. x ≤ – 9 B. – 9 ≤ x ≤ 6 C. x ≥ 6 D. x ≤ 54

Content Standards A. APR. 1 Understand that polynomials form a system analogous to the

Content Standards A. APR. 1 Understand that polynomials form a system analogous to the integers, namely, they are closed under the operations of addition, subtraction, and multiplication; add, subtract, and multiply polynomials. Mathematical Practices 2 Reason abstractly and quantitatively.

You evaluated powers. • Multiply, divide, and simplify monomials and expressions involving powers. •

You evaluated powers. • Multiply, divide, and simplify monomials and expressions involving powers. • Add, subtract, and multiply polynomials.

 • simplify • degree of a polynomial

• simplify • degree of a polynomial

Simplify Expressions A. Simplify the expression that no variable equals 0. . Assume Original

Simplify Expressions A. Simplify the expression that no variable equals 0. . Assume Original expression Definition of negative exponents Definition of exponents

Simplify Expressions Divide out common factors. Simplify.

Simplify Expressions Divide out common factors. Simplify.

Simplify Expressions B. Simplify the expression variable equals 0. . Assume that no Quotient

Simplify Expressions B. Simplify the expression variable equals 0. . Assume that no Quotient of powers Subtract powers. Definition of negative exponents Answer:

Simplify Expressions C. Simplify the expression variable equals 0. . Assume that no Power

Simplify Expressions C. Simplify the expression variable equals 0. . Assume that no Power of a quotient Power of a product

Simplify Expressions Power of a power

Simplify Expressions Power of a power

A. Simplify the expression Assume that no variable equals 0. A. B. C. D.

A. Simplify the expression Assume that no variable equals 0. A. B. C. D. .

B. Simplify the expression variable equals 0. A. B. C. D. Assume that no

B. Simplify the expression variable equals 0. A. B. C. D. Assume that no

C. Simplify the expression variable equals 0. A. B. C. D. . Assume that

C. Simplify the expression variable equals 0. A. B. C. D. . Assume that no

Degree of a Polynomial Answer:

Degree of a Polynomial Answer:

Degree of a Polynomial Answer: This expression is a polynomial because each term is

Degree of a Polynomial Answer: This expression is a polynomial because each term is a monomial. The degree of the first term is 5 and the degree of the second term is 2 + 7 or 9. The degree of the polynomial is 9.

Degree of a Polynomial C. Determine whether is a polynomial. If it is a

Degree of a Polynomial C. Determine whether is a polynomial. If it is a polynomial, state the degree of the polynomial. Answer: The expression is not a polynomial because is not a monomial: Monomials cannot contain variables in the denominator.

A. Is a polynomial? If it is a polynomial, state the degree of the

A. Is a polynomial? If it is a polynomial, state the degree of the polynomial. A. yes, 5 B. yes, 8 C. yes, 3 D. no

B. Is a polynomial? If it is a polynomial, state the degree of the

B. Is a polynomial? If it is a polynomial, state the degree of the polynomial. A. yes, 2 B. yes, C. yes, 1 D. no

C. Is a polynomial? If it is a polynomial, state the degree of the

C. Is a polynomial? If it is a polynomial, state the degree of the polynomial. A. yes, 5 B. yes, 6 C. yes, 7 D. no

Simplify Polynomial Expressions A. Simplify (2 a 3 + 5 a – 7) –

Simplify Polynomial Expressions A. Simplify (2 a 3 + 5 a – 7) – (a 3 – 3 a + 2) Distribute the – 1. Group like terms. = a 3 + 8 a – 9 Answer: a 3 + 8 a – 9 Combine like terms.

Simplify Polynomial Expressions B. Simplify (4 x 2 – 9 x + 3) +

Simplify Polynomial Expressions B. Simplify (4 x 2 – 9 x + 3) + (– 2 x 2 – 5 x – 6). Align like terms vertically and add. 4 x 2 – 9 x + 3 (+) – 2 x 2 – 5 x – 6 2 x 2 – 14 x – 3 Answer: 2 x 2 – 14 x – 3

A. Simplify (3 x 2 + 2 x – 3) – (4 x 2

A. Simplify (3 x 2 + 2 x – 3) – (4 x 2 + x – 5). A. 7 x 2 + 3 x – 8 B. –x 2 + 3 x – 8 C. –x 2 + 3 x + 2 D. –x 2 + x + 2

B. Simplify (– 3 x 2 – 4 x + 1) – (4 x

B. Simplify (– 3 x 2 – 4 x + 1) – (4 x 2 + x – 5). A. 9 x 2 + 6 x + 7 B. – 7 x 2 – 5 x + 6 C. 3 x 2 – 6 x + 7 D. 3 x 2 – 2 x + 6

Simplify by Using the Distributive Property Find –y(4 y 2 + 2 y –

Simplify by Using the Distributive Property Find –y(4 y 2 + 2 y – 3) = –y(4 y 2) – y(2 y) – y(– 3) Distributive Property = – 4 y 3 – 2 y 2 + 3 y Multiply the monomials. Answer: – 4 y 3 – 2 y 2 + 3 y

Find –x(3 x 3 – 2 x + 5). A. – 3 x 2

Find –x(3 x 3 – 2 x + 5). A. – 3 x 2 – 2 x + 5 B. – 4 x 2 – 3 x 2 – 6 x C. – 3 x 4 + 2 x 2 – 5 x D. – 3 x 4 – 2 x 3 + 5 x

Write a Polynomial Expression E-SALES A small online retailer estimates that the cost, in

Write a Polynomial Expression E-SALES A small online retailer estimates that the cost, in dollars, associated with selling x units of a particular product is given by the expression 0. 001 x 2 + 5 x + 500. The revenue from selling x units is given by 10 x. Write a polynomial to represent the profits generated by the product if profit = revenue – cost.

Write a Polynomial Expression 10 x – (0. 001 x 2 + 5 x

Write a Polynomial Expression 10 x – (0. 001 x 2 + 5 x + 500) Original expression = 10 x – 0. 001 x 2 – 5 x – 500 Distributive Property = – 0. 001 x 2 + 5 x – 500 Add 10 x to – 5 x. Answer: The polynomial is – 0. 001 x 2 + 5 x – 500.

INTEREST Olivia has $1300 to invest in a government bond that has an annual

INTEREST Olivia has $1300 to invest in a government bond that has an annual interest rate of 2. 2%, and a savings account that pays 1. 9% per year. Write a polynomial for the interest she will earn in one year if she invests x dollars in the government bond. A. – 0. 003 x + 24. 7 B. – 0. 003 x + 28. 6 C. 0. 003 x + 28. 6 D. 0. 003 x + 24. 7

Multiply Polynomials Find (a 2 + 3 a – 4)(a + 2) Distributive Property

Multiply Polynomials Find (a 2 + 3 a – 4)(a + 2) Distributive Property Multiply monomials.

Multiply Polynomials = a 3 + 5 a 2 + 2 a – 8

Multiply Polynomials = a 3 + 5 a 2 + 2 a – 8 Answer: a 3 + 5 a 2 + 2 a – 8 Combine like terms.

Find (x 2 + 3 x – 2)(x + 4). A. x 3 +

Find (x 2 + 3 x – 2)(x + 4). A. x 3 + 7 x 2 + 10 x – 8 B. x 2 + 4 x + 2 C. x 3 + 3 x 2 – 2 x + 8 D. x 3 + 7 x 2 + 14 x – 8