Exponential Function 5 Item MCQ ANSILUZ H BETCO

Exponential Function 5 Item MCQ ANSILUZ H. BETCO San Bartolome High School NEXT

Directions Read analyze the following questions properly. Click on the correct answer. BAC K NEX T

1. Which of the following define an exponential function? a) 2 x 2 + 3 x – 6= 8 b) 2/3 m – 5 = 15 c) y = 2 x + 1 d) p 3 + 2 p -3 = 0 BAC K NEXT

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Exponential Function Definition: → If a>0 and a ≠ 1, then the exponential function with the base a is a function defined by f(x) = ax, where x is any real numbers. → therefore y= 2 x +1 is the only equation wherein the exponent x vary. NEXT

2) Which of the following graphs represent an exponential function? a) c) b) d) BAC K NEXT

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Graph of Exponential Function The graph of y = ax is upward-sloping, and increases faster as x increases. The graph always lies above the x-axis but can get arbitrarily close to it for negative x; thus, the x-axis is a horizontal asymptote. The slope of the graph at each point is equal to its y coordinate at that point. NEXT

3) Solve for x: 3 x 9 = 5 -x (1/3) a) x = 1 b) x = -1 c) x = 2 d) x = -2 BAC K NEXT

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3) 93 x = (1/3)5 -x Solution 93 x = (1/3)5 -x 32(3 x)= 3 -1(5 -x) 6 x = -5+x change the equation with same base bring down the exponents 5 x = -5 x = -1 solve for x answer NEXT

4) A certain city has a population of 20000 and a growth rate of 3. 5%. What will be the expected population after 3 years? 24, 145 b) 23, 501 c) 23, 219 d) 22, 174 a) BAC K

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The Exponential Growth is in the form Y = P( 1 + r)x where P = original number r = rate of change x = unit of time y = total number after x years So, P = 20000 r = 3. 5% or 0. 035 t = 3 years Substitute Y = P( 1 + r)x = 20, 000 (1 +. 035)3 = 20, 000 (1. 1087) = 22, 174 expected population after 3 yrs NEXT

5) If a car depreciates at an annual rate of 15%, how much would be its value at the end of two years if its cost is $450, 000 when new? a) $325, 125 b) $276, 356 c) $315, 134 d) $412, 300 BAC K

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The Exponential Decay is in the form Y = P( 1 - r)x where P = original amount r = rate of change x = unit of time y = total amount after x years So, P= $450, 000 r = 15% or 0. 15 t= 2 years Substitute Y = P( 1 - r)x = 450, 000 (1 -. 15)2 = 450, 000 (0. 85)2 = 450, 000 (0. 7225) = $325, 125 amount of car after 2 years NEXT

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