Example A dc battery of constant emf E

Example A dc battery of constant emf E is being charged through a resistor using halfwave diode rectifier. For source voltage of 230 V, 50 Hz and for R =8Ω, E =150 V, (a) Find the value of average charging current, (b) Find the power supplied to battery and that dissipated in the resistor, (c) Calculate the supply pf, (d) Find the charging time in case battery capacity is 1000 Wh and (e) Find rectifier efficiency and PIV of the diode. Dr. Oday A. Ahmed

the value of average charging current Dr. Oday A. Ahmed

the power supplied to battery the power dissipated in the resistor Dr. Oday A. Ahmed

Calculate the supply pf, Find the charging time in case battery capacity is 1000 Wh (Power delivered to battery) ×(charging time in hours)= Battery capacity in Wh Hence, charging time is Dr. Oday A. Ahmed

rectifier efficiency PIV of the diode What is the PIV of the single-phase diode Rectifier Supply R-Load Dr. Oday A. Ahmed

A single-phase 230 V: 1 k. W heater is connected across I-phase 230 V, 50 Hz supply through an SCR. For firing angle delays of 45° and 90°, calculate the power absorbed in the heater element. 230 V, 1 k. W Heater Dr. Oday A. Ahmed

Solution Heater resistance: Dr. Oday A. Ahmed

Power absorbed by heater element for α=450 Dr. Oday A. Ahmed

In a single-phase full-wave diode bridge rectifier, the diodes have a reverse recovery time of 40 µs. For an AC input voltage of 230 V, determine the effect of reverse recovery time on the average output voltage for a supply frequency of (a) 50 Hz and (b) 2. 5 k. Hz. Solution D 1 and D 2 will not be off at ωt =π but will continue to conduct until t=( π/ω )+trr Dr. Oday A. Ahmed

With zero reverse recovery time, average output voltage, Dr. Oday A. Ahmed

For f= 50 Hz and trr = 40 µs, the reduction in the average output voltage, Percentage reduction in average outpace voltage Dr. Oday A. Ahmed

(a) For f= 2. 5 k Hz, the reduction in the average output voltage, Percentage reduction in average output voltage Dr. Oday A. Ahmed