Example 2 Given Class D Concrete Air Content

Example #2 Given: • Class D Concrete • Air Content – 7% • Minimum amount of Cement • Maximum Replacement of Fly Ash • Maximum w/c ratio • Maximum amount of Fine Aggregate • Specific Gravities: • • Cement – 3. 15 Fly Ash – 2. 55 Coarse Aggregate – 2. 79 Fine Aggregate – 2. 63

D 620 75% 3. 15 25% 2. 55 0% 0. 40 1. 00 0 7% 2. 79 2. 63 44% 27. 0

Paste Material Weights Cementitious Material: WCEMENT= WCM * %WCEMENT Water: WWATER= WCM * W/CM Paste: WPASTE= WCM + WWATER

Paste Material Weights Cementitious Material: WCEMENT= WCM * %WCEMENT Water: WWATER= WCM * W/CM Paste: WPASTE= WCM + WWATER

D 75% 620 25% 465 155 3. 15 248 1. 00 2. 55 0% 0. 40 0 7% 868 2. 79 2. 63 44% 27. 0

Paste Material Volume Cementitious Material: VCEMENT= WCEMENT / (GCEMENT * U) Water: VWATER=WWATER / U Air: VAIR=(Design Air * 27)/100 Paste: VPASTE= VCEMENT +VWATER+ VAIR U= 62. 4 lbs/ft 3

D 465 155 75% 620 25% 3. 15 2. 37 2. 55 0. 97 0% 0 248 0. 40 3. 97 1. 00 0 7% 868 1. 89 9. 20 2. 79 2. 63 44% 27. 0

Aggregate Volume Total Aggregate Volume: VAGG= 27 -VPASTE Coarse Aggregate Volume: VCA= %VCA * VAGG /100 Fine Aggregate Volume: VFA= %VFA * VAGG /100

D 465 155 75% 620 25% 3. 15 2. 37 2. 55 0. 97 0% 0 248 0. 40 3. 97 1. 00 0 7% 868 1. 89 9. 20 17. 80 2. 79 56% 9. 97 2. 63 44% 7. 83 27. 0

Aggregate Weights Coarse Aggregate Weight: WCA= VCA * GCA *U Fine Aggregate Weight: WFA= VFA * GFA *U U= 62. 4 lbs/ft 3

D 465 155 75% 620 25% 3. 15 2. 37 2. 55 0. 97 0% 0 248 0. 40 3. 97 1. 00 0 7% 868 1. 89 9. 20 17. 80 1735 2. 79 56% 9. 97 1285 2. 63 44% 7. 83 27. 0

Total and Unit Weight Total Weight: WTOTAL= WCA + WFA + WPASTE Unit Weight: UCONCRETE= WTOTAL / VTOTAL

D 465 155 75% 620 25% 3. 15 2. 37 2. 55 0. 97 0% 0 248 0. 40 3. 97 1. 00 7% 0 868 1. 89 9. 20 17. 80 1735 2. 79 56% 9. 97 1285 2. 63 44% 7. 83 3888 27. 0 144. 0

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