example 1 The circumference of the circle is
- Slides: 19
example 1 : The circumference of the circle is 50 feet. The area of the shaded region = ____
50 The circumference of the circle is 50 feet. 50 The area of the shaded region = ____ C = d = 50 therefore the diameter of the circle is 50 feet.
50 The circumference of the circle is 50 feet. 25 The area of the shaded region = ____ C = d = 50 therefore the diameter of the circle is 50 feet and the radius is 25 feet.
50 The circumference of the circle is 50 feet. 25 The area of the shaded region = ____ C = d = 50 therefore the diameter of the circle is 50 feet 50 and the radius is 25 feet. The area of the circle = (25)2 = 625 square feet the area of the square = 50 x 50 = 2500 square feet
50 The circumference of the circle is 50 feet. 25 The area of the shaded region = ____ C = d = 50 therefore the diameter of the circle is 50 feet 50 and the radius is 25 feet. The area of the circle = (25)2 = 625 square feet 2500 square feet - 625 square feet
50 The circumference of the circle is 50 feet. 25 The area of the shaded region =(2500 - 625 ) square feet C = d = 50 therefore the diameter of the circle is 50 feet 50 and the radius is 25 feet. The area of the circle = (25)2 = 625 square feet 2500 square feet - 625 square feet
example 2 : The circumference of the circle is 50 feet. The area of the shaded region = ____
The circumference of the circle is 50 feet. The area of the shaded region = ____ C = d = 50 therefore the diameter of the circle is 50 feet.
The circumference of the circle is 50 feet. 50 x x The area of the shaded region = ____ C = d = 50 therefore the diameter of the circle is 50 feet. Let x = the side of the square
The circumference of the circle is 50 feet. 50 The area of the shaded region = ____ x C = d = 50 x therefore the diameter of the circle is 50 feet. Let x = the side of the square x 2 + x 2 = 502 = 2500 x 2 = 1250 area of circle = 625 = the area of the square
The circumference of the circle is 50 feet. 50 The area of the shaded region = ____ x C = d = 50 x therefore the diameter of the circle is 50 feet. Let x = the side of the square x 2 + x 2 = 502 = 2500 x 2 = 1250 area of circle = 625 = the area of the square - area of square = 1250
The circumference of the circle is 50 feet. 50 The area of the shaded region =(625 - 1250) sq feet x C = d = 50 x therefore the diameter of the circle is 50 feet. Let x = the side of the square x 2 + x 2 = 502 = 2500 x 2 = 1250 area of circle = 625 = the area of the square - area of square = 1250
example 3 : AB = 30 feet A 30 B What is the SUM of the areas of the purple squares? _____
example 3 : AB = 30 feet A 30 x x y B y What is the SUM of the areas of the purple squares? _____ Let x = the length of the side of the large square and let y = the length of the side of the small square
example 3 : AB = 30 feet A Area = x 2 30 x x y y B Area = y 2 What is the SUM of the areas of the purple squares? x 2 + y 2 Let x = the length of the side of the large square and let y = the length of the side of the small square
example 3 : AB = 30 feet A Area = x 2 30 x x y y B Area = y 2 What is the SUM of the areas of the purple squares? x 2 + y 2 = 302 = 900 sq ft Let x = the length of the side of the large square and let y = the length of the side of the small square
example 4 : 10 feet If the area of the triangle is 14 square feet, then the area of the rectangle is ______ 7 feet
example 4 : 10 feet If the area of the triangle is 14 square feet, then the area of the rectangle is ______ The area of a triangle = ½ height x base 7 feet 14 = ½ height x 7 28 = height x 7 4 = height
example 4 : 10 feet 4 If the area of the triangle is 14 square feet, then the area of the rectangle is 10 x 4 = 40 sq ft The area of a triangle = ½ height x base 7 feet 14 = ½ height x 7 28 = height x 7 4 = height
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