Exam Question On your whiteboards LSF ASF VSF

Exam Question

On your whiteboards LSF ASF VSF A: 5 : 25 : 125 : B 6 36 216 Volume of B = 5000 ÷ 125 x 216 = 8640 cm 3 LSF ASF VSF X: Y 2: 3 4: 9 8 : 27 SA of X = 225 ÷ 9 x 4 = 100 cm 2

ASF LSF Height Small : Large 1 : 1. 44 1 : 1. 2 10 cm : 12 cm (44% increase) (10 cm x 1. 2)

Did you expect these answers? Small : Large 1/ : 1 LSF (1/5 of the original) 5 1/ VSF (1/5 cubed) 125 : 1 Mass is directly proportional to volume. So the mass will increase by the same factor as the volume if the two spheres have the same density. Mass of smaller spheres = 375 x 1/125 = 3 kg Small : Large 1/ : 1 LSF (1/5 of the original) 5 1/ ASF (1/5 squared) 25 : 1 SA of 1 smaller sphere = 8000 x 1/25 = 320 cm 2 If each small sphere has a volume 1/125 of the original, then there must be 125 smaller spheres. Thus, the total SA = 125 x 320 = 40, 000 cm 2.

If the total height is 3 h, then the height of the tip of the cone (which is similar to the whole cone) is 1 h. LSF VSF Tip of Cone : Whole Cone 1: 3 1 : 27 The volume of the whole cone is 27 times bigger than the tip. Volume of small cone = 459 cm 3 ÷ 27 = 17 cm 3 Volume of cup (a “frustum”) = 459 – 17 = 442 cm 3

What is the question?

Challenge

Challenge Volume of cone: The volume of a cone is 1/3 of the volume of a cylinder with the same base and height. If a cone and cylinder with the same base also have the same volume, then the height must be 3 times bigger. Check it!

Challenge