Equations of Uniform Accelerated Motion AP Physics C
- Slides: 15
Equations of Uniform Accelerated Motion AP Physics C Mrs. Coyle
Uniform Accelerated Motion n Motion with constant acceleration q Straight line q Same direction
Equations for Uniform Accelerated Motion n Velocity v= vo+ at n Position x= xo + vot + ½ at 2 n v 2 = vo 2 + 2 a(x-xo) Remember: Displacement= Dx = x-xo
More Equations of Motion for Uniform Accelerate d Motion n vavg = n Dx n ½ (vo +v) = ½ (vo+ v)t Assume that ti=0
Example of Position vs Time (Positive Acceleration) Position (m) x= xo + vot + ½ at 2 Parabola o Time (s) Slope of Tangent at a given time= Instantaneous Velocity at that time
Example of Velocity vs Time (Positive Acceleration) v= vo+ at Velocity (m/s) o Time (s) Slope of Line= Acceleration Area Under Line=Displacement
Example of Acceleration vs Time (Const. a) Acceleration (m/s 2) o Time (s) Area under line = Change in Velocity
How do we derive Dx = ½ (vo+ v)t from the graph? Velocity (m/s) v vo o t Hint: Area Under the Line=Displacement Δx Time (s)
Example of Position vs Time (Negative Acceleration) Position (m) Parabola o Time (s)
Example of Velocity vs Time (Negative Acceleration) Velocity (m/s) o Time (s) Slope of Line= Acceleration Area Under Line=Displacement
Example of Acceleration vs Time (Negative a) Acceleration (m/s 2) o Time (s) Area under line = Change in Velocity
How do we derive x= xo + vot + ½ at 2 ? Hint: Start with Dx = ½ (vo+ v)t and then substitute for v that v = vo+at.
How do we derive v 2 = vo 2 + 2 a(xxo)? n Hint: Start with Dx = ½ (vo+ v)t then substitute for t = (v – vo) /a
Problem 1 A ball initially stationary, accelerates at 0. 25 m/s 2 down a 2 m inclined plane. It then rolls up another incline, where it comes to rest after rolling up 1 m. a) What is the speed of the ball at the bottom of the incline and how much time did this take? b) What is the acceleration along the second plane? Answer: a) 1 m/s, 4 sec, b) -0. 5 m/s 2
Problem 2 A Mustang travelling with a constant velocity of 35 m/s, passes a stationary police car. The reaction time of the officer was 2. 5 sec and he then accelerates at 5. 0 m/s 2 to catch the Mustang. How long does it take for the police car to catch the Mustang? Answer: 15. 8 sec
- Uniformly variable rectilinear motion
- Chapter 3 accelerated motion answers
- Chapter 3 accelerated motion practice problems answers
- Rearranging kinematic equations
- Uniform and non uniform linear motion
- How to derive vf^2=vi^2+2ad
- Equations of motion higher physics
- Uniformly accelerated motion formulas
- Uniformly accelerated motion
- Comic strip showing uniformly accelerated motion
- Rectilinear motion with variable acceleration
- How do you classify uniform and non-uniform mixtures?
- How do you classify uniform and non-uniform mixtures?
- Contoh soal aliran seragam
- Circular motion lab
- Uniform linear motion examples