Equations for ideal gases The ideal gas equation
![Equations for ideal gases The ideal gas equation and its variant for N molecules Equations for ideal gases The ideal gas equation and its variant for N molecules](https://slidetodoc.com/presentation_image_h2/71d9e3b4e3606b431e193e1dd7f3e4d7/image-1.jpg)
![Particle in a Box Deriving Particle in a Box Deriving](https://slidetodoc.com/presentation_image_h2/71d9e3b4e3606b431e193e1dd7f3e4d7/image-2.jpg)
![The particle in a box • The idea is to derive an expression for The particle in a box • The idea is to derive an expression for](https://slidetodoc.com/presentation_image_h2/71d9e3b4e3606b431e193e1dd7f3e4d7/image-3.jpg)
![Assumptions 1. 2. 3. 4. 5. 6. Intermolecular forces are negligible except during collisions. Assumptions 1. 2. 3. 4. 5. 6. Intermolecular forces are negligible except during collisions.](https://slidetodoc.com/presentation_image_h2/71d9e3b4e3606b431e193e1dd7f3e4d7/image-4.jpg)
![• We also start with the knowledge that : 1. Pressure = Force • We also start with the knowledge that : 1. Pressure = Force](https://slidetodoc.com/presentation_image_h2/71d9e3b4e3606b431e193e1dd7f3e4d7/image-5.jpg)
![We start with one molecule and take the simplest case, that I is moving We start with one molecule and take the simplest case, that I is moving](https://slidetodoc.com/presentation_image_h2/71d9e3b4e3606b431e193e1dd7f3e4d7/image-6.jpg)
![The molecule collides with A and bounces back in the opposite direction. Its momentum The molecule collides with A and bounces back in the opposite direction. Its momentum](https://slidetodoc.com/presentation_image_h2/71d9e3b4e3606b431e193e1dd7f3e4d7/image-7.jpg)
![This means that its change in momentum is 2 mu A u m y This means that its change in momentum is 2 mu A u m y](https://slidetodoc.com/presentation_image_h2/71d9e3b4e3606b431e193e1dd7f3e4d7/image-8.jpg)
![its rate of change of momentum is given by: this is equal to the its rate of change of momentum is given by: this is equal to the](https://slidetodoc.com/presentation_image_h2/71d9e3b4e3606b431e193e1dd7f3e4d7/image-9.jpg)
![remembering that velocity is distance travelled / time taken So the time taken between remembering that velocity is distance travelled / time taken So the time taken between](https://slidetodoc.com/presentation_image_h2/71d9e3b4e3606b431e193e1dd7f3e4d7/image-10.jpg)
![so the rate of change of momentum of the molecule Is ie Now this so the rate of change of momentum of the molecule Is ie Now this](https://slidetodoc.com/presentation_image_h2/71d9e3b4e3606b431e193e1dd7f3e4d7/image-11.jpg)
![So the force on the wall from this one particle is As pressure is So the force on the wall from this one particle is As pressure is](https://slidetodoc.com/presentation_image_h2/71d9e3b4e3606b431e193e1dd7f3e4d7/image-12.jpg)
![This is an expression for the pressure due to 1 molecule of the ideal This is an expression for the pressure due to 1 molecule of the ideal](https://slidetodoc.com/presentation_image_h2/71d9e3b4e3606b431e193e1dd7f3e4d7/image-13.jpg)
![But there are three components of velocity u in the x direction , say But there are three components of velocity u in the x direction , say](https://slidetodoc.com/presentation_image_h2/71d9e3b4e3606b431e193e1dd7f3e4d7/image-14.jpg)
- Slides: 14
![Equations for ideal gases The ideal gas equation and its variant for N molecules Equations for ideal gases The ideal gas equation and its variant for N molecules](https://slidetodoc.com/presentation_image_h2/71d9e3b4e3606b431e193e1dd7f3e4d7/image-1.jpg)
Equations for ideal gases The ideal gas equation and its variant for N molecules Relates pressure to the density of a gas and root mean square velocity. You may have to manipulate this one Relates absolute temperature to average molecular energy
![Particle in a Box Deriving Particle in a Box Deriving](https://slidetodoc.com/presentation_image_h2/71d9e3b4e3606b431e193e1dd7f3e4d7/image-2.jpg)
Particle in a Box Deriving
![The particle in a box The idea is to derive an expression for The particle in a box • The idea is to derive an expression for](https://slidetodoc.com/presentation_image_h2/71d9e3b4e3606b431e193e1dd7f3e4d7/image-3.jpg)
The particle in a box • The idea is to derive an expression for to relate the pressure and volume of a gas to the movement of the many individual molecules which make it up • We are building a MATHEMATICAL MODEL of what is happening and to do this we will need to make several assumptions
![Assumptions 1 2 3 4 5 6 Intermolecular forces are negligible except during collisions Assumptions 1. 2. 3. 4. 5. 6. Intermolecular forces are negligible except during collisions.](https://slidetodoc.com/presentation_image_h2/71d9e3b4e3606b431e193e1dd7f3e4d7/image-4.jpg)
Assumptions 1. 2. 3. 4. 5. 6. Intermolecular forces are negligible except during collisions. All collisions are perfectly elastic The volume of the molecules themselves can be neglected compared with the volume occupied by the gas. The time for any collision is negligible compared with the time spent between collisions. Between collisions molecules move with uniform velocity. There is a sufficiently large number of molecules for statistics to be meaningfully applied. These conditions imply that all of the internal energy of the gas is kinetic.
![We also start with the knowledge that 1 Pressure Force • We also start with the knowledge that : 1. Pressure = Force](https://slidetodoc.com/presentation_image_h2/71d9e3b4e3606b431e193e1dd7f3e4d7/image-5.jpg)
• We also start with the knowledge that : 1. Pressure = Force / Area 2. Force = rate of change of momentum
![We start with one molecule and take the simplest case that I is moving We start with one molecule and take the simplest case, that I is moving](https://slidetodoc.com/presentation_image_h2/71d9e3b4e3606b431e193e1dd7f3e4d7/image-6.jpg)
We start with one molecule and take the simplest case, that I is moving only in the x direction heading for face A A u m y z x The molecule has mass m and velocity u so its momentum is mu
![The molecule collides with A and bounces back in the opposite direction Its momentum The molecule collides with A and bounces back in the opposite direction. Its momentum](https://slidetodoc.com/presentation_image_h2/71d9e3b4e3606b431e193e1dd7f3e4d7/image-7.jpg)
The molecule collides with A and bounces back in the opposite direction. Its momentum velocity has changed from u to -u A u m y z x So its momentum has chaged from mu to -mu
![This means that its change in momentum is 2 mu A u m y This means that its change in momentum is 2 mu A u m y](https://slidetodoc.com/presentation_image_h2/71d9e3b4e3606b431e193e1dd7f3e4d7/image-8.jpg)
This means that its change in momentum is 2 mu A u m y z x So its momentum has chaged from mu to -mu
![its rate of change of momentum is given by this is equal to the its rate of change of momentum is given by: this is equal to the](https://slidetodoc.com/presentation_image_h2/71d9e3b4e3606b431e193e1dd7f3e4d7/image-9.jpg)
its rate of change of momentum is given by: this is equal to the force acting on the particle The time (∆t) between successive collisions is the time it takes to travel from wall A to the far wall of the box and back. y A m u The distance it has to travel is 2 x. x It does this travelling at velocity u
![remembering that velocity is distance travelled time taken So the time taken between remembering that velocity is distance travelled / time taken So the time taken between](https://slidetodoc.com/presentation_image_h2/71d9e3b4e3606b431e193e1dd7f3e4d7/image-10.jpg)
remembering that velocity is distance travelled / time taken So the time taken between collisions (∆t) is
![so the rate of change of momentum of the molecule Is ie Now this so the rate of change of momentum of the molecule Is ie Now this](https://slidetodoc.com/presentation_image_h2/71d9e3b4e3606b431e193e1dd7f3e4d7/image-11.jpg)
so the rate of change of momentum of the molecule Is ie Now this is equal to the force of the wall which acts on the particle to change its momentum and by Newton’s third law this must be equal to the force of the particle acting on the wall.
![So the force on the wall from this one particle is As pressure is So the force on the wall from this one particle is As pressure is](https://slidetodoc.com/presentation_image_h2/71d9e3b4e3606b431e193e1dd7f3e4d7/image-12.jpg)
So the force on the wall from this one particle is As pressure is force / area and the area of wall A is y x z The pressure on wall A due to this one molecule is y A= y x z z
![This is an expression for the pressure due to 1 molecule of the ideal This is an expression for the pressure due to 1 molecule of the ideal](https://slidetodoc.com/presentation_image_h2/71d9e3b4e3606b431e193e1dd7f3e4d7/image-13.jpg)
This is an expression for the pressure due to 1 molecule of the ideal gas moving in the x direction. BUT there are N molecules in the gas and they have individual velocities: u 12, + u 22+ u 32, ……u. N 2
![But there are three components of velocity u in the x direction say But there are three components of velocity u in the x direction , say](https://slidetodoc.com/presentation_image_h2/71d9e3b4e3606b431e193e1dd7f3e4d7/image-14.jpg)
But there are three components of velocity u in the x direction , say v in the y direction and w in the z direction v w u Then taking c 2 rms = u 2 rms+ v 2 rms+w 2 rms So u 2 rms = 1/3 c 2 rms
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