Equation Stoichiometry Using a balanced equation to calculate
Equation Stoichiometry: Using a balanced equation to calculate the mass, amount of moles, the number of particles, or the volume of any substance in a reaction.
How to do this! 1. Balance the reaction if it is a skeleton equation or write it out if equation is expressed in words. 2. Convert the given information into moles for that substance. 3. Convert the number of moles of the given substance to the number of moles of the substance you want to learn other information about. 4. Convert the number of moles to the answer to your question. • See the mole road map at the front of the class to learn how many steps any problem will take.
• EX: 2 Cu + S ---- Cu 2 S • How much sulfur will react with 1. 15 g copper? 1. Balance the reaction if it is a skeleton equation or write it out if equation is expressed in words. • See the mole road map at the front of the class to learn how many steps any problem will take. 1. 15 g Cu x 1 32 g S = 0. 2893 g = 0. 289 g 1 mole Cu x 1 mole S x 2 mole Cu 1 mole S 63. 6 g Cu 2. Convert the given information into moles for that substance. 3. Convert the number of moles of the given substance to the number of moles of the substance you want to learn other information about. 4. Convert the number of moles to the answer to your question.
• EX: N 2 (g) +3 H 2(g) ---- 2 NH 3(g) • How many liters of NH 3 are produced when 55 g hydrogen react with excess nitrogen at STP? 1. Balance the reaction if it is a skeleton equation or write it out if equation is expressed in words. • See the mole road map at the front of the class to learn how many steps any problem will take. 55 g H 2 x 1 1 mole H 2 2 g H 2 x 2 mole NH 3 x 22. 4 L NH 3 = 410. 67 L 3 mole H 2 1 mole NH 3 = 410 L 2. Convert the given information into moles for that substance. 3. Convert the number of moles of the given substance to the number of moles of the substance you want to learn other information about. 4. Convert the number of moles to the answer to your question.
Limiting Reagent Limiting reagent: The reactant that limits the amount of product that can be made. - The reagent that will run out first
Percent Yield: the percentage of the possible amount you can make in a reaction Theoretical Yield: The maximum amount of products that could be formed from given amounts of reactants Actual Yield: The actual amount of products formed from given amounts of reactants Percent Yield = Actual Yield x 100% Theoretical Yield
- Slides: 6