ENGINEERING MATHEMATICS Lecture 7 Graphical Characteristic of Linear

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ENGINEERING MATHEMATICS Lecture – 7 / Graphical Characteristic of Linear Equation Fall Semester 2018

ENGINEERING MATHEMATICS Lecture – 7 / Graphical Characteristic of Linear Equation Fall Semester 2018 Instructor Twana. A. Hussein – MSc. Structural Engineering Twana. ahmad@ishik. edu. iq Civil Engineering Dept. Ishik University

Ishik University The graph of a linear equation is always a straight line, sometimes

Ishik University The graph of a linear equation is always a straight line, sometimes it can be vertical, horizontal or has a slope. 2 .

Ishik University There are three different methods for graphing equations 1) Using slope-intercept form

Ishik University There are three different methods for graphing equations 1) Using slope-intercept form 2) Using x- and y-intercepts 3) Using table The goal is to determine which method is the easiest to use for each problem! 3 .

Ishik University If the equation is in STANDARD FORM (Ax + By = C),

Ishik University If the equation is in STANDARD FORM (Ax + By = C), graph using the intercepts. If the equation is in SLOPE-INTERCEPT FORM (y = mx + b), graph using slope and intercept. 4 .

Ishik University 5 .

Ishik University 5 .

Ishik University Rise Run. 6

Ishik University Rise Run. 6

Ishik University Start by graphing the y-intercept (b = 2). Y-intercept means x =

Ishik University Start by graphing the y-intercept (b = 2). Y-intercept means x = 0 7 .

Ishik University From the y-intercept, apply “rise over run” using your slope. rise =

Ishik University From the y-intercept, apply “rise over run” using your slope. rise = - 1, run = 3 Y = -1 X=3 Rise = 1 Run = 3 8 .

Ishik University Then draw the line between two points 4 3, 5 3 2,

Ishik University Then draw the line between two points 4 3, 5 3 2, 5 2 Rise = 1 1, 5 1 Run = 3 0, 5 0 -6 . -4 -2 0 2 4 6 9

Ishik University 10 .

Ishik University 10 .

Ishik University 1. 2. 3. . Find your x-intercept: Let y = 0 -2

Ishik University 1. 2. 3. . Find your x-intercept: Let y = 0 -2 x + 3(0) = 12 x = -6; (-6, 0) Find your y-intercept: Let x = 0 -2(0) + 3 y = 12 y = 4; (0, 4) Graph both points and draw a line through them. 11

Ishik University x y -2 0 1 1 3 4 12 .

Ishik University x y -2 0 1 1 3 4 12 .