Engineering Electromagnetics Lecture 7 Dr Ing Erwin Sitompul

Engineering Electromagnetics Lecture 7 Dr. -Ing. Erwin Sitompul President University http: //zitompul. wordpress. com President University Erwin Sitompul EEM 7/1

Chapter 5 Current and Conductors Current and Current Density n Electric charges in motion constitute a current. n The unit of current is the ampere (A), defined as a rate of movement of charge passing a given reference point (or crossing a given reference plane). n Current is defined as the motion of positive charges, although conduction in metals takes place through the motion of electrons. n Current density J is defined, measured in amperes per square meter (A/m 2). President University Erwin Sitompul EEM 7/2

Chapter 5 Current and Conductors Current and Current Density n The increment of current ΔI crossing an incremental surface ΔS normal to the current density is: n If the current density is not perpendicular to the surface, n Through integration, the total current is obtained: President University Erwin Sitompul EEM 7/3

Chapter 5 Current and Conductors Current and Current Density n Current density may be related to the velocity of volume charge density at a point. • An element of charge ΔQ = ρvΔSΔL moves along the x axis • In the time interval Δt, the element of charge has moved a distance Δx • The charge moving through a reference plane perpendicular to the direction of motion is ΔQ = ρvΔSΔx President University Erwin Sitompul EEM 7/4

Chapter 5 Current and Conductors Current and Current Density n The limit of the moving charge with respect to time is: n In terms of current density, we find: n This last result shows clearly that charge in motion constitutes a current. We name it here convection current. n J = ρvv is then called convection current density. President University Erwin Sitompul EEM 7/5

Chapter 5 Current and Conductors Continuity of Current n The principle of conservation of charge: “Charges can be neither created nor destroyed. ” n But, equal amounts of positive and negative charge (pair of charges) may be simultaneously created, obtained by separation, destroyed, or lost by recombination. • The Continuity Equation in Closed Surface n Any outward flow of positive charge must be balanced by a decrease of positive charge (or perhaps an increase of negative charge) within the closed surface. n If the charge inside the closed surface is denoted by Qi, then the rate of decrease is –d. Qi/dt and the principle of conservation of charge requires: • The Integral Form of the Continuity Equation President University Erwin Sitompul EEM 7/6

Chapter 5 Current and Conductors Continuity of Current n The differential form (or point form) of the continuity equation is obtained by using the divergence theorem: n We next represent Qi by the volume integral of ρv: n If we keep the surface constant, the derivative becomes a partial derivative. Writing it within the integral, • The Differential Form (Point Form) of the Continuity Equation President University Erwin Sitompul EEM 7/7

Chapter 5 Current and Conductors Continuity of Current n Example The current density is given by . • Total outward current at time instant t = 1 s and r = 5 m. • Total outward current at time instant t = 1 s and r = 6 m. • Finding volume charge density: President University Erwin Sitompul EEM 7/8

Chapter 5 Current and Conductors Metallic Conductors n The energy-band structure of three types of materials at 0 K is shown as follows: n Energy in the form of heat, light, or an electric field may raise the energy of the electrons of the valence band, and in sufficient amount they will be excited and jump the energy gap into the conduction band. President University Erwin Sitompul EEM 7/9

Chapter 5 Current and Conductors Metallic Conductors n First let us consider the conductor. n Here, the valence electrons (or free conductive electrons) move under the influence of an electric field E. n An electron having a charge Q = –e will experiences a force: n In the crystalline material, the progress of the electron is impeded by collisions with the lattice structure, and a constant average velocity is soon attained. n This velocity vd is termed the drift velocity. It is linearly related to the electric field intensity by the mobility of the electron μe: • The Point Form of Ohm’s Law President University Erwin Sitompul EEM 7/10

Chapter 5 Current and Conductors Metallic Conductors n The application of Ohm’s law in point form to a macroscopic region leads to a more familiar form. n Assuming J and E to be uniform, in a cylindrical region shown below, we can write: President University Erwin Sitompul EEM 7/11

Chapter 5 Current and Conductors Conductor Properties and Boundary Conditions n Property 1: The charge density within a conductor is zero (ρv = 0) and the surface charge density resides on the exterior surface. n Property 2: In static conditions, no current may flow, thus the electric field intensity within the conductor is zero (E = 0). n Now our next concern is the fields external to the conductor. n The external electric field intensity and electric flux density are decomposed into the tangential components and the normal components. President University Erwin Sitompul EEM 7/12

Chapter 5 Current and Conductors Conductor Properties and Boundary Conditions n The tangential component of the electric field intensity is seen to be zero Et = 0 Dt = 0. If not, then a force will be applied to the surface charges, resulting in their motion and thus it is no static conditions. n The normal component of the electric flux density leaving the surface is equal to the surface charge density in coulombs per square meter (DN = ρS). According to Gauss’s law, the electric flux leaving an incremental surface is equal to the charge residing on that incremental surface. The flux cannot penetrate into the conductor since the total field there is zero. It must leave the surface normally. President University Erwin Sitompul EEM 7/13

Chapter 5 Current and Conductors Conductor Properties and Boundary Conditions President University Erwin Sitompul EEM 7/14

Chapter 5 Current and Conductors Conductor Properties and Boundary Conditions n Example Given the potential V = 100(x 2–y 2) and a point P(2, – 1, 3) that is predefined to lie on a conductor-to-free-space boundary, find V, E, D, and ρS at P, and also the equation of the conductor surface. • Carefully examine the surface direction President University Erwin Sitompul EEM 7/15

Chapter 5 Current and Conductors Homework 6 n D 5. 1 n D 5. 2. n D 5. 4. n D 5. 5. (Bonus Question, + 20 points if correctly made) n All homework problems from Hayt and Buck, 7 th Edition. n Deadline: 05 June 2012, at 08: 00. President University Erwin Sitompul EEM 7/16