ENE 325 Electromagnetic Fields and Waves Lecture 4

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ENE 325 Electromagnetic Fields and Waves Lecture 4 Electric potential, Gradient, Current and Conductor,

ENE 325 Electromagnetic Fields and Waves Lecture 4 Electric potential, Gradient, Current and Conductor, and Ohm’s law 1

Review Gauss’s law is another approach to evaluate the electric field and is proper

Review Gauss’s law is another approach to evaluate the electric field and is proper for highly symmetrical configuration. n n Divergence is defined by n Point form of Gauss’s law: 2

Outline Electric potential n Gradient n Current and Conductor n Ohm’s law n 3

Outline Electric potential n Gradient n Current and Conductor n Ohm’s law n 3

Electric work n A work done to move one charge from one to point

Electric work n A work done to move one charge from one to point to another is defined by n A work done by the field in moving the charge from point a to point b is n A work done by an external force against the field is 4

Ex 1 Calculate work required to move a 5 n. C charge from the

Ex 1 Calculate work required to move a 5 n. C charge from the origin to point P (1, 1, 0) against the static field given V/m. 5

Electric potential (1) n The electric potential difference Vba is a work done by

Electric potential (1) n The electric potential difference Vba is a work done by an external force to move a charge from point a to point b in an electric field divided by the amount of charge moved. Va and Vb are the absolute potentials measured with respect to the reference potential at ground plane. 6

Electric potential (2) n If then the electric potential is independent of the chosen

Electric potential (2) n If then the electric potential is independent of the chosen path. n If a closed path is chosen and is done. n An absolute potential at some finite radius from a point charge fixed at the origin is no work 7

Electric potential (3) n The electric potential resulted from N charges is found by

Electric potential (3) n The electric potential resulted from N charges is found by adding the potential for each charge. n If a collection of charges become a continuous distribution, the total potential is then 8

Ex 2 Let n. C/m V/m and L is 100 a) Find the work

Ex 2 Let n. C/m V/m and L is 100 a) Find the work done in moving a 10 n. C from = 3 m to = 1 m. b) Determine the potential difference Vba. 9

Ex 3 Find a work done in moving a charge Q = 5 C

Ex 3 Find a work done in moving a charge Q = 5 C from the origin to point P (2, , 4/ /2) in spherical coordinates by giving V/m. Note: line different element. 10

Gradient A plot of the electrostatic potential superimposed over the field lines for a

Gradient A plot of the electrostatic potential superimposed over the field lines for a point charge. The electric field can be found by finding the maximum rate and direction of spatial change of the potential field. 11

A gradient equation n For a Cartesian coordinate system: n For a cylindrical coordinate

A gradient equation n For a Cartesian coordinate system: n For a cylindrical coordinate system : n For a spherical coordinate system: 12

Introduction to electromagnetic material n The properties of electromagnetic material is specified by ,

Introduction to electromagnetic material n The properties of electromagnetic material is specified by , , . n Homogeneous material is the material that possesses the same properties at every point in the material. n Isotropic material is the material that its properties are independent of direction. 13

Conductor The material that electrons move freely. The conductivity, , depends on charge density

Conductor The material that electrons move freely. The conductivity, , depends on charge density and scattering of electrons by their interactions with crystal lattice. decreases with increasing temperature. Perfect conductor The conductor that has an infinite conductivity. 14

Current and current density n n Current, current density, resistance, and capacitance can be

Current and current density n n Current, current density, resistance, and capacitance can be explained using electromagnetics. Current, I is defined as the amount of charge that passes through a reference plane in a given amount of time. Amperes (A) n n Current density, J is defined as the amount of current per unit area A/m 2 total current can be expressed as 15

Current density and volume charge density Consider At time t, charges move for a

Current density and volume charge density Consider At time t, charges move for a distance x crossing a reference plane that is normal to the direction of charge movement. Since then where nx is a charge velocity (m/s) or The movement of charge creates “Convection current”. 16

Continuity of current The principle of conservation of charge “charges can be neither created

Continuity of current The principle of conservation of charge “charges can be neither created nor destroyed, although equal amounts of positive and negative charge may be simultaneously created, obtained by separation, destroyed, or lost by recombination. ” The integral form of the continuity equation, indicates an outward-flowing current where Qi is the charge inside the closed surface. We can show its point form as 17

Conduction current arises from free electrons in a conductor. Electrons in valence band have

Conduction current arises from free electrons in a conductor. Electrons in valence band have high enough energy to get into the conduction band. 18

Drift velocity where e is the mobility of the electron in the given material

Drift velocity where e is the mobility of the electron in the given material (m 2/V-s) aluminum = 0. 0012 m 2/V-s copper = 0. 0032 m 2/V-s silver = 0. 0056 m 2/V-s Then where e is the free-electron charge density, a negative value. 19

The point form of Ohm’s law where . n The conductivity is measured in

The point form of Ohm’s law where . n The conductivity is measured in siemens per meter (S/m). aluminum = 3. 82 x 107 S/m copper = 5. 8 x 107 S/m silver = 6. 17 x 107 S/m n The conductivity depends on the temperature. 20

The application of Ohm’s law Assume and are uniform, we can write Ohm’s law

The application of Ohm’s law Assume and are uniform, we can write Ohm’s law as where Ohm ( ). is the resistance with the measured unit of General form: 21

Ex 4 Determine the magnitude of in silver when a) nd = 1 mm/s

Ex 4 Determine the magnitude of in silver when a) nd = 1 mm/s b) J = 107 A/m 2 22

c) A current of 80 A flows through a silver dice of width =

c) A current of 80 A flows through a silver dice of width = 3 mm and length = 3 mm. d) A same silver dice with a 0. 5 m. V drop across a top and a bottom face. 23

Ex 5 An aluminum rod with the length of 1000 feet has a cross

Ex 5 An aluminum rod with the length of 1000 feet has a cross section with the diameter of 0. 8 inch. There is 1. 2 V potential drop across both ends, determine a) J b) current 24

c) power dissipated in the rod 25

c) power dissipated in the rod 25