EMPIRICAL FORMULAS EMPIRICAL SIMPLEST RATIO OF ATOMS IN

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EMPIRICAL FORMULAS EMPIRICAL = SIMPLEST RATIO OF ATOMS IN A COMPOUND C 8 H

EMPIRICAL FORMULAS EMPIRICAL = SIMPLEST RATIO OF ATOMS IN A COMPOUND C 8 H 8 = CH COMPLEX = EMPIRICAL

Steps for empirical formulas given B= 78. 1% H= 21. 9% convert to grams

Steps for empirical formulas given B= 78. 1% H= 21. 9% convert to grams find moles mole ratio formula

Steps for empirical formulas given convert to grams B= 78. 1% 78. 1 grams

Steps for empirical formulas given convert to grams B= 78. 1% 78. 1 grams H= 21. 9% 21. 9 grams find moles mole ratio formula

Steps for empirical formulas given convert to grams find moles B= 78. 1% 78.

Steps for empirical formulas given convert to grams find moles B= 78. 1% 78. 1 grams 78. 1 /10. 8 =7. 22 moles H= 21. 9% 21. 9 grams 21. 9/ 1. 01 =21. 7 moles mole ratio formula

Steps for empirical formulas given convert to grams find moles mole ratio formula B=

Steps for empirical formulas given convert to grams find moles mole ratio formula B= 78. 1% 78. 1 grams 78. 1 /10. 8 7. 22 M = 1 =7. 22 M moles H= 21. 9% 21. 9 grams 21. 9/ 1. 01 21. 7 M = 3 =21. 7 7. 22 M moles

Steps for empirical formulas given convert to grams find moles mole ratio formula B=

Steps for empirical formulas given convert to grams find moles mole ratio formula B= 78. 1% 78. 1 grams 78. 1 /10. 8 7. 22 M = 1 =7. 22 M moles B 1 H= 21. 9% 21. 9 grams 21. 9/ 1. 01 21. 7 M = 3 =21. 7 7. 22 M moles H 3

Steps for empirical formulas given convert to grams P = 4. 43 g O

Steps for empirical formulas given convert to grams P = 4. 43 g O = 5. 72 g find moles mole ratio formula

Steps for empirical formulas given convert to grams find moles P = 4. 43

Steps for empirical formulas given convert to grams find moles P = 4. 43 g 4. 43 / 31. 0 = 0. 143 m O = 5. 72 g 5. 72 / 16. 0 = 0. 357 m mole ratio formula

Steps for empirical formulas given convert to grams find moles P = 4. 43

Steps for empirical formulas given convert to grams find moles P = 4. 43 g 4. 43 / 31. 0 = 0. 143 m O = 5. 72 g 5. 72 / 16. 0 = 0. 357 m mole ratio formula 0. 143 =1 0. 357 0. 143 =2. 5

Steps for empirical formulas given convert to grams find moles P = 4. 43

Steps for empirical formulas given convert to grams find moles P = 4. 43 g 4. 43 / 31. 0 = 0. 143 m O = 5. 72 g 5. 72 / 16. 0 = 0. 357 m mole ratio formula 0. 143 =1 P 1 0. 357 0. 143 =2. 5 O 2. 5

Example #2 WE HAVE TO FIND A NUMBER TO MULTIPLE BOTH NUMBERS BY SO

Example #2 WE HAVE TO FIND A NUMBER TO MULTIPLE BOTH NUMBERS BY SO THAT THEY BECOME WHOLE NUMBERS. P = 1 AND O = 2. 5 SINCE. 5 = 1/2 THEN MULTIPLY BOTH BY 2 P = 2 AND O = 5

Steps for empirical formulas given convert to grams find moles P = 4. 43

Steps for empirical formulas given convert to grams find moles P = 4. 43 g 4. 43 / 31. 0 = 0. 143 m O = 5. 72 g 5. 72 / 16. 0 = 0. 357 m mole ratio formula 0. 143 =1 2 X P 1 0. 357 0. 143 =2. 5 2 X O 2. 5 P 2 O 5

Example #1 STEP 4 THE WHOLE NUMBERS BECOME THE SUBSCRIPTS FOR THE FORMULA. P=2

Example #1 STEP 4 THE WHOLE NUMBERS BECOME THE SUBSCRIPTS FOR THE FORMULA. P=2 O=5 P 2 O 5

DECIMALS = FRACTIONS. 5 = 1/2. 3 = 1/3. 667 = 2/3. 75 =

DECIMALS = FRACTIONS. 5 = 1/2. 3 = 1/3. 667 = 2/3. 75 = 3/4. 25 = 1/4. 20 = 1/5 MULTIPLY BY 2 MULTIPLY BY 3 MULTIPLY BY 4 MULTIPLY BY 5

Steps for empirical formulas given convert to grams find moles mole ratio formula

Steps for empirical formulas given convert to grams find moles mole ratio formula

Steps for empirical formulas given Ni = 20% Br = 80% convert to grams

Steps for empirical formulas given Ni = 20% Br = 80% convert to grams find moles mole ratio formula

Steps for empirical formulas given convert to grams Ni = 20% 20 g Br

Steps for empirical formulas given convert to grams Ni = 20% 20 g Br = 80% 80 g find moles mole ratio formula

Steps for empirical formulas given Ni = 20% convert to grams find moles 20

Steps for empirical formulas given Ni = 20% convert to grams find moles 20 g 20/ 58. 7 =. 341 m mole ratio formula From periodic table Br = 80% 80 g 80/ 79. 9 = 1. 00 m

Steps for empirical formulas given Ni = 20% convert to grams 20 g find

Steps for empirical formulas given Ni = 20% convert to grams 20 g find moles mole ratio formula 20/ 58. 7. 341/. 341 =. 341 m =1 From periodic table Br = 80% 80 g 80/ 79. 9 1. 00/. 341 = 1. 00 m =3

Steps for empirical formulas given Ni = 20% convert to grams 20 g find

Steps for empirical formulas given Ni = 20% convert to grams 20 g find moles mole ratio formula 20/ 58. 7. 341/. 341 =. 341 m =1 Ni =1 From periodic table Br = 80% 80 g 80/ 79. 9 1. 00/. 341 = 1. 00 m =3 Br = 3 Ni Br 3

Determining Empirical Formulas: Homework 1) C H 4 2) K Cl 3) Al P

Determining Empirical Formulas: Homework 1) C H 4 2) K Cl 3) Al P O 4 4) Mg Br 2 5) Na 2 S O 4 Cu S O 4 5 H 2 O 6)

MOLECULAR FORMULAS ARE MORE COMPLEX RATIOS. SUCH AS B 3 H 9. EMPIRICAL FORMULAS

MOLECULAR FORMULAS ARE MORE COMPLEX RATIOS. SUCH AS B 3 H 9. EMPIRICAL FORMULAS ARE THE SIMPLEST RATIOS. FOR EXAMPLE BH 3

EXAMPLE #1 TWO THINGS MUST BE GIVEN IN THESE TYPES OF PROBLEMS 1) THE

EXAMPLE #1 TWO THINGS MUST BE GIVEN IN THESE TYPES OF PROBLEMS 1) THE EMPIRICAL FORMULA = BH 3 2) THE MOLECULAR MASS = 28 grams. STEP 1 DETERMINE THE EMPIRICAL MASS FROM THE EMPIRICAL FORMULA BH 3 =13. 8 ROUND OFF TO 14

Example #1 STEP #2 DIVIDE THE MOLECULAR MASS BY THE EMPIRICAL MASS. THIS SHOULD

Example #1 STEP #2 DIVIDE THE MOLECULAR MASS BY THE EMPIRICAL MASS. THIS SHOULD ALWAYS GIVE YOU A WHOLE NUMBER. 28 GRAMS = 2 14 GRAMS

Example #1 STEP #3 THE WHOLE NUMBER IS MULTIPLIED BY THE SUBSCRIPTS IN THE

Example #1 STEP #3 THE WHOLE NUMBER IS MULTIPLIED BY THE SUBSCRIPTS IN THE EMPIRICAL FORMULA TO GIVE THE MOLECULAR FORMULA. EF= BH 3 X 2 = B 2 H 6=MF

EMPIRICAL FORMULA EF = MOLECULAR FORMULA MF = EMPIRICAL MASS EM = MOLECULAR MASS

EMPIRICAL FORMULA EF = MOLECULAR FORMULA MF = EMPIRICAL MASS EM = MOLECULAR MASS MM =

EMPIRICAL FORMULA EF = BH 3 EMPIRICAL MASS EM = B 1 x 10.

EMPIRICAL FORMULA EF = BH 3 EMPIRICAL MASS EM = B 1 x 10. 8 = 10. 8 H 3 X 1. 01 = 3. 03 13. 8= 14 MOLECULAR FORMULA MF = MOLECULAR MASS MM =

EMPIRICAL FORMULA EF = BH 3 EMPIRICAL MASS EM = B 1 x 10.

EMPIRICAL FORMULA EF = BH 3 EMPIRICAL MASS EM = B 1 x 10. 8 = 10. 8 H 3 X 1. 01 = 3. 03 13. 8= 14 MOLECULAR FORMULA MF = MOLECULAR MASS MM = 28 28/14 = 2

EMPIRICAL FORMULA EF = BH 3 EMPIRICAL MASS EM = B 1 x 10.

EMPIRICAL FORMULA EF = BH 3 EMPIRICAL MASS EM = B 1 x 10. 8 = 10. 8 H 3 X 1. 01 = 3. 03 13. 8= 14 MOLECULAR FORMULA MF = B 2 H 6 MOLECULAR MASS MM = 28 28/14 = 2

EMPIRICAL FORMULA EF = BH 3 EMPIRICAL MASS EM = B 1 x 10.

EMPIRICAL FORMULA EF = BH 3 EMPIRICAL MASS EM = B 1 x 10. 8 = 10. 8 H 3 X 1. 01 = 3. 03 13. 8= 14 MOLECULAR FORMULA MF = B 2 H 6 MOLECULAR MASS MM = 28 28/14 = 2

EMPIRICAL FORMULA EF = BH 3 EMPIRICAL MASS EM = B 1 x 10.

EMPIRICAL FORMULA EF = BH 3 EMPIRICAL MASS EM = B 1 x 10. 8 = 10. 8 H 3 X 1. 01 = 3. 03 13. 8= 14 MOLECULAR FORMULA MF = B 2 H 6 MOLECULAR MASS MM = 28 28/14 = 2

EMPIRICAL FORMULA EF = CH MOLECULAR FORMULA MF = EMPIRICAL MASS EM = MOLECULAR

EMPIRICAL FORMULA EF = CH MOLECULAR FORMULA MF = EMPIRICAL MASS EM = MOLECULAR MASS MM = 78

EMPIRICAL FORMULA EF = CH MOLECULAR FORMULA EMPIRICAL MASS EM =13 MOLECULAR MASS MM

EMPIRICAL FORMULA EF = CH MOLECULAR FORMULA EMPIRICAL MASS EM =13 MOLECULAR MASS MM = 78 MF =C 6 H 6 78 / 13 = 6

EMPIRICAL FORMULA EF = HO MOLECULAR FORMULA MF = EMPIRICAL MASS EM = MOLECULAR

EMPIRICAL FORMULA EF = HO MOLECULAR FORMULA MF = EMPIRICAL MASS EM = MOLECULAR MASS MM = 34

EMPIRICAL FORMULA EF = HO MOLECULAR FORMULA EMPIRICAL MASS EM = 17 MOLECULAR MASS

EMPIRICAL FORMULA EF = HO MOLECULAR FORMULA EMPIRICAL MASS EM = 17 MOLECULAR MASS MM = 34 MF =H 2 O 2 34/17 = 2

Molecular Formulas HW 1) N 2 O 4 2) C 5 H 10 3)

Molecular Formulas HW 1) N 2 O 4 2) C 5 H 10 3) C 2 H 4 O 2 4) C 4 H 10 O 5) C 4 H 8 O 2