Electronic Technician Certification Program Electronic Devices DIODE September
Electronic Technician Certification Program Electronic Devices DIODE September 12, 2020 CYCLE: One complete occurrence of a repeating wave (periodic signal) such as one positive and one negative alternation of a sine wave. FREQUENCY: the number of cycles of a signal occur in one second PERIOD: the time distance between two similar position on a periodic wave. WAVELENGTH: the distance traveled by an electromagnetic (radio) wave during one period Wavelength (m) = (300 x 108 m/s ) / f (HZ) where 300 x 108 m/s is speed of light
Electronic Technician Certification Program SINE WAVE ( display on the Oscilloscope) • in display 1 V/division • Vpk=3 V • Vpk-pk=6 V = 2 x Vpk • Vrms = 0. 707 x Vp • Vrms = 2. 12 V • Vavg = 0. 637 x Vpk • in display 1 msec/division • Period T = 7 msec • Frequency F = 1/T • F = 1/ 7 msec= 142. 8 HZ Period T: complete one cycle • T=1 / F in this formula T=second, F= frequency in Hertz • or F = 1 / T • Frequency is the number of cycles of a given waveform that occur in one second
Electronic Technician Certification Program
Electronic Technician Certification Program DIODE PN Junction P type - - - + + N type Depletion region Semiconductor Diode DIODE Symbol Anode A Cathode C Diode Voltage VD=VA – VC Voltage across Diode normally permit electron current flow only in one direction
Electronic Technician Certification Program IDEAL Permit current flow from Anode to Cathode (Diode ON or Forward Bias): ideal Diode VD=VA-VC = 0 V REVERSE BIAS: Diode OFF Open circuit No current flow from A to C Resistance from A to C = infinity Ohm ( )
Electronic Technician Certification Program
Electronic Technician Certification Program
Electronic Technician Certification Program #1 Vout I #2 Vout Calculate: Given VD=0. 7 V 1. Diode on or off ? 2. Vout 3. Current I 4. V across R 1. 2. 3. 4. Diode ON 0. 7 V 9. 3 m. A 9. 3 V Calculate: Given VD=0. 7 V 1. Diode on or off ? 2. Vout 3. Current I 4. V across R 1. 2. 3. 4. Diode OFF 5 V 0 m. A 0 V
Electronic Technician Certification Program #3 Calculate: Given VD=0. 7 V 1. Diode on or off ? 2. Current I #4 Calculate: Given VD=0. 7 V Diode is forward biased or reverse biased ?
Electronic Technician Certification Program
Electronic Technician Certification Program
Electronic Technician Certification Program
Electronic Technician Certification Program
Electronic Technician Certification Program
Electronic Technician Certification Program
Electronic Technician Certification Program
Electronic Technician Certification Program
Electronic Technician Certification Program
Electronic Technician Certification Program
Electronic Technician Certification Program
Electronic Technician Certification Program
Electronic Technician Certification Program
Electronic Technician Certification Program
Electronic Technician Certification Program
Electronic Technician Certification Program
Electronic Technician Certification Program
Electronic Technician Certification Program
Electronic Technician Certification Program
Electronic Technician Certification Program
Electronic Technician Certification Program
Electronic Technician Certification Program
Electronic Technician Certification Program
Electronic Technician Certification Program
Electronic Technician Certification Program
Electronic Technician Certification Program
Electronic Technician Certification Program
Electronic Technician Certification Program
Electronic Technician Certification Program
Electronic Technician Certification Program
Electronic Technician Certification Program
Electronic Technician Certification Program t(ms) Ideal Diode Vd = 0 V Vout RL T(period)
Electronic Technician Certification Program Vout= 4 Vp 0 V Ideal DIODE VD= 0 V Vout= 3. 3 Vp Output Frequency = input Frequency -0. 7 V 0 V Practical DIODE VD= 0. 7 V
Electronic Technician Certification Program Transformer • Transform one voltage to the other • Primary voltage: Vp and Secondary voltage: Vs • Np = number of turns in primary and Ns: number of turns in Secondary • Np / Ns = Vp / Vs then Vs = ( Ns x Vp ) / Np • if Ns > Np = Step-up and Ns < Np = Step-down
Electronic Technician Certification Program Problem. For the circuit shown, solve for: 1. Vp(sec) 2. The rectifier peak voltage VRL 3. Current through the Load in milli. A Note VD=0. 7 V
Electronic Technician Certification Program Vs/2 Vp Vs/2 • The DC average: VDC = 2 x Vp / 6. 284 • Fout = 2 Fin • Ideal Diode Vd=0 V • Practical Diode Vd=0. 7 V and VP(out) = Vp(in) – 0. 7
Electronic Technician Certification Program
Electronic Technician Certification Program
Electronic Technician Certification Program
Electronic Technician Certification Program
Electronic Technician Certification Program The bridge rectifier Vp Vout Vp Vs
Electronic Technician Certification Program The bridge rectifier
Electronic Technician Certification Program The bridge rectifier
Electronic Technician Certification Program The bridge rectifier
Electronic Technician Certification Program The bridge rectifier
Electronic Technician Certification Program
Electronic Technician Certification Program
Electronic Technician Certification Program
Electronic Technician Certification Program
Electronic Technician Certification Program A basic +5. 0 V regulated power supply
Electronic Technician Certification Program THE E N D
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