Electronic Instrumentation Experiment 2 Part A Intro to
- Slides: 61
Electronic Instrumentation Experiment 2 * Part A: Intro to Transfer Functions and AC Sweeps * Part B: Phasors, Transfer Functions and Filters * Part C : Using Transfer Functions and RLC Circuits * Part D: Equivalent Impedance and DC Sweeps
Part A Introduction to Transfer Functions and Phasors w Complex Polar Coordinates w Complex Impedance (Z) w AC Sweeps w
Transfer Functions w The transfer function describes the behavior of a circuit at Vout for all possible Vin.
Simple Example
More Complicated Example What is H now? w H now depends upon the input frequency (w = 2 pf) because the capacitor and inductor make the voltages change with the change in current.
How do we model H? We want a way to combine the effect of the components in terms of their influence on the amplitude and the phase. w We can only do this because the signals are sinusoids w • cycle in time • derivatives and integrals are just phase shifts and amplitude changes
We will define Phasors A phasor is a function of the amplitude and phase of a sinusoidal signal w Phasors allow us to manipulate sinusoids in terms of amplitude and phase changes. w Phasors are based on complex polar coordinates. w Using phasors and complex numbers we will be able to find transfer functions for circuits. w
Review of Polar Coordinates point P is at ( rpcosqp , rpsinqp )
Review of Complex Numbers zp is a single number represented by two numbers w zp has a “real” part (xp) and an “imaginary” part (yp) w
Complex Polar Coordinates z = x+jy where x is A cosf and y is A sinf w wt cycles once around the origin once for each cycle of the sinusoidal wave (w=2 pf) w
Now we can define Phasors The real part is our signal. w The two parts allow us to determine the influence of the phase and amplitude changes mathematically. w After we manipulate the numbers, we discard the imaginary part. w
The “V=IR” of Phasors The influence of each component is given by Z, its complex impedance w Once we have Z, we can use phasors to analyze circuits in much the same way that we analyze resistive circuits – except we will be using the complex polar representation. w
Magnitude and Phase w Phasors have a magnitude and a phase derived from polar coordinates rules.
Influence of Resistor on Circuit Resistor modifies the amplitude of the signal by R w Resistor has no effect on the phase w
Influence of Inductor on Circuit Note: cosq=sin(q+p/2) Inductor modifies the amplitude of the signal by w. L w Inductor shifts the phase by +p/2 w
Influence of Capacitor on Circuit Capacitor modifies the amplitude of the signal by 1/w. C w Capacitor shifts the phase by -p/2 w
Understanding the influence of Phase
Complex Impedance w Z defines the influence of a component on the amplitude and phase of a circuit • Resistors: ZR = R • change the amplitude by R • Capacitors: ZC=1/jw. C • change the amplitude by 1/w. C • shift the phase -90 (1/j=-j) • Inductors: ZL=jw. L • change the amplitude by w. L • shift the phase +90 (j)
AC Sweeps
Notes on Logarithmic Scales
Capture/PSpice Notes w Showing the real and imaginary part of the signal • in Capture: PSpice->Markers->Advanced • ->Real Part of Voltage • ->Imaginary Part of Voltage • in PSpice: Add Trace • real part: R( ) • imaginary part: IMG( ) w Showing the phase of the signal • in Capture: • PSpice->Markers->Advanced->Phase of Voltage • in PSPice: Add Trace • phase: P( )
Part B Phasors w Complex Transfer Functions w Filters w
Definition of a Phasor The real part is our signal. w The two parts allow us to determine the influence of the phase and amplitude changes mathematically. w After we manipulate the numbers, we discard the imaginary part. w
Phasor References http: //ccrmawww. stanford. edu/~jos/filters/Phasor_Notat ion. html w http: //www. ligo. caltech. edu/~vsanni/ph 3/Ex p. ACCircuits/ACCircuits. pdf w http: //robotics. eecs. berkeley. edu/~cssharp/P hasors/Phasors. html w
Phasor Applet
Adding Phasors & Other Applets
Magnitude and Phase w Phasors have a magnitude and a phase derived from polar coordinates rules.
Euler’s Formula
Manipulating Phasors (1) w Note wt is eliminated by the ratio • This gives the phase change between signal 1 and signal 2
Manipulating Phasors (2)
Complex Transfer Functions If we use phasors, we can define H for all circuits in this way. w If we use complex impedances, we can combine all components the way we combine resistors. w H and V are now functions of j and w w
Complex Impedance w Z defines the influence of a component on the amplitude and phase of a circuit • Resistors: ZR = R • Capacitors: ZC=1/jw. C • Inductors: ZL=jw. L w We can use the rules for resistors to analyze circuits with capacitors and inductors if we use phasors and complex impedance.
Simple Example
Simple Example (continued)
High and Low Pass Filters High Pass Filter wc=2 pfc H = 0 at w ® 0 H = 1 at w ® ¥ H = 0. 707 at wc fc wc=2 pfc Low Pass Filter H = 1 at w ® 0 H = 0 at w ® ¥ fc H = 0. 707 at wc
Corner Frequency The corner frequency of an RC or RL circuit tells us where it transitions from low to high or visa versa. w We define it as the place where w w For RC circuits: w For RL circuits:
Corner Frequency of our example
H(jw), wc, and filters We can use the transfer function, H(jw), and the corner frequency, wc, to easily determine the characteristics of a filter. w If we consider the behavior of the transfer function as w approaches 0 and infinity and look for when H nears 0 and 1, we can identify high and low pass filters. w The corner frequency gives us the point where the filter changes: w
Taking limits w At low frequencies, (ie. w=10 -3), lowest power of w dominates w At high frequencies (ie. w =10+3), highest power of w dominates
Taking limits -- Example w At low frequencies, (lowest power) w At high frequencies, (highest power)
Our example at low frequencies
Our example at high frequencies
Our example is a low pass filter What about the phase?
Our example has a phase shift
Part C Using Transfer Functions w Capacitor Impedance Proof w More Filters w Transfer Functions of RLC Circuits w
Using H to find Vout
Simple Example (with numbers)
Capacitor Impedance Proof Prove:
Band Filters Band Pass Filter H = 0 at w ® 0 H = 0 at w ® ¥ f 0 H = 1 at w 0=2 pf 0 Band Reject Filter H = 1 at w ® 0 H = 1 at w ® ¥ f 0 H = 0 at w 0 =2 pf 0
Resonant Frequency The resonant frequency of an RLC circuit tells us where it reaches a maximum or minimum. w This can define the center of the band (on a band filter) or the location of the transition (on a high or low pass filter). w We are already familiar with the equation for the resonant frequency of an RLC circuit: w
Another Example
At Very Low Frequencies At Very High Frequencies
At the Resonant Frequency if L=10 u. H, C=1 n. F and R=1 K W w 0=10 M rad/sec f 0=1. 6 M Hz |H|=0. 1
Our example is a low pass filter Phase -90 f = 0 at w ® 0 f = -180 at w ® ¥ Magnitude H = 1 at w ® 0 0. 1 H = 0 at w ® ¥ f 0=1. 6 M Hz
Part D Equivalent Impedance w Transfer Functions of More Complex Circuits w
Equivalent Impedance Even though this filter has parallel components, we can still handle it. w We can combine complex impedances like resistors to find the equivalent impedance of the components combined. w
Equivalent Impedance
Determine H
At Very Low Frequencies At Very High Frequencies
At the Resonant Frequency
Our example is a band pass filter Magnitude H = 0 at w ® 0 H=1 at w 0 H = 0 at w ® ¥ Phase f = 90 at w ® 0 f = 0 at w 0 f = -90 at w ® ¥
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