ELECTROMAGNETIC WAVES ELECTROMAGNETIC WAVES LEVEL1 HOME WORK ELECTROMAGNETIC

ELECTROMAGNETIC WAVES

ELECTROMAGNETIC WAVES LEVEL-1 HOME WORK

ELECTROMAGNETIC WAVES DISPLACEMENT CURRENT: Solution: id = 0. 1274 A

ELECTROMAGNETIC WAVES 1) 5. 50 A Solution:

ELECTROMAGNETIC WAVES = 8. 85× 3. 14× 5× 4 × 10 =5557. 8 A KEY: 2

ELECTROMAGNETIC WAVES 3) A parallel plate condenser of capacity 10 F is charged with a constant charging current of 0. 16 A. The displacement current is. . . 1) 0. 16 A Solution: 2) 0. 16 A 3) 0. 96 A 4) 9. 6 A

ELECTROMAGNETIC WAVES 4) A parallel plate condenser has conducting plates of radius 12 cm separated by a distance of 5 mm. It is charged with a constant charging current of 0. 16 A, the rate at which the potential difference between the plates change is. . . 12 -1 9 -1 1) 1 × 109 V s-1 2) 2 × 1010 V s-1 3) 3 × 10 V s 4) 2 × 10 V s Solution: i = 0. 16 A

ELECTROMAGNETIC WAVES KEY: 4

ELECTROMAGNETIC WAVES 4) 9. 42 A; 94. 2 A Solution: n = 50 Hz V = 300 V

ELECTROMAGNETIC WAVES KEY: 3

ELECTROMAGNETIC WAVES 1) 1. 062 amp Solution: V = 400 V;

ELECTROMAGNETIC WAVES KEY: 2

ELECTROMAGNETIC WAVES MAGNETIC FIELD PRODUCED BETWEEN THE PLATES OF A PARALLAL PLATE CONDENSER: 1) 0. 1 A Solution: 2) 0. 2 A 3) 0. 3 A 4) 0. 15 A

ELECTROMAGNETIC WAVES 8) The diameter of the plates of a condenser is 10 cm and it is charged by an external source with a steady current of 0. 1 A. The maximum magnetic field induced in the gap is. . . Solution: B=?

ELECTROMAGNETIC WAVES 9) A condenser of capacity 50 p. F is connected to an AC supply of 220 V and 50 Hz. The rms value of magnetic field at a distance of 5 cm from the axis is. . . 1) 22 × 10 -14 T 2) 22 × 10 -12 T 3) 44 × 10 -13 T Solution: V = 220 V; n = 50 Hz;

ELECTROMAGNETIC WAVES 1) 1: 1 2) 2 : 1 Solution: B�� r; 3) 1: 2 4) 1 : 4

ELECTROMAGNETIC WAVES Solution:

ELECTROMAGNETIC WAVES KEY: 2

ELECTROMAGNETIC WAVES EM WAVE AND REFRACTIVE INDEX 12) The refractive index of a medium of di-electric constant 2 and relative permeability 1. 28 is. . . 1) 2. 56 Solution: 2) 0. 8 3) 1. 6 4) 1. 3

ELECTROMAGNETIC WAVES 13) The relative permeability of glass is 3/8 and the dielectric constant of glass is 8. The refractive index of glass is. . . 1) 1. 5 Solution: 2) 1. 1414 3) 1. 732 4) 1. 6

ELECTROMAGNETIC WAVES Solution:

ELECTROMAGNETIC WAVES Relation between B & E 15) A plane EM wave of frequency 40 MHz travels along X-axis. At same point at same instant, the electric field E has maximum value of 750 N/C in Y-direction. The magnitude and direction of magnetic field is. . . Solution: E = 750 N/C in y-axis

ELECTROMAGNETIC WAVES MOMENTUM AND FORCE Solution: Radius =1. 4 m

ELECTROMAGNETIC WAVES Time = 10 min = 600 sec KEY: 3

ELECTROMAGNETIC WAVES 17) Light with energy flux of 24 Wm-2 is incident on a well polished disc of radius 3. 5 cm for one hour. The momentum transferred to the disc is. . . 2) 2. 2 kgms-1 1) 1. 1 kgms-1 3) 3. 3 kgms-1 Solution: 4) 4. 4 kgms-1 t = 3600 sec=1 hr P=?

ELECTROMAGNETIC WAVES KEY: 2

ELECTROMAGNETIC WAVES ENERGY DENSITY 1) 3. 4 × 10 -8 Solution: 2) 13. 7 × 10 -8 3) 6. 8 × 10 -8 4) 1. 7 × 10 -8

ELECTROMAGNETIC WAVES 19) In an electromagnetic wave in vacuum, the electrical and magnetic fields are 40 V/m and 0. 4 × 10 -7 T. The magnitude of pointing vector. . . 1) 4. 4 W m-1 2) 0. 44 W m-1 3) 5. 65 W m-1 4) 4. 0 W m-1 Solution:

ELECTROMAGNETIC WAVES INTENSITY 20) The intensity of electromagnetic wave at a distance of 1 Km from a source of power 12. 56 KW. is. . . 1) 10 -3 W m-2 4) 1. 256 × Solution: 10 -3 2) 4 × 10 -3 W m-2 3) 12. 56 × 10 -3 W m-2

ELECTROMAGNETIC WAVES 1) 39. 2 m. W 2) 19. 6 m. W 3) 9. 8 m. W Solution: P=? 4) 4. 9 m. W

ELECTROMAGNETIC WAVES 22) At the threshold of detection an FM receiver can pick up a signal for which E 0 = 2 V/m. The intensity of the electromagnetic wave. . . 1) 5. 31 × 10 -15 W 2) 5. 31 × 10 -12 W 3) 5. 31 × 10 -4 W 4) 1. 77 × 10 -23 W Solution:

ELECTROMAGNETIC WAVES 23) The sun radiates electromagnetic energy at the rate of 3. 9 × 1026 W. Its radius is 6. 96 × 108 m. The intensity of sun light at the solar surface will be (in W/m 2). . . 3) 64 × 106 4) 5. 6 × 107 1) 1. 4 × 104 2) 2. 8 × 105 Soluti on: I=?

ELECTROMAGNETIC WAVES Thank you…