Electrical Circuits Determine the current and voltage for

Electrical Circuits Determine the current and voltage for each resistor. Also, determine the total current coming from the battery. V=5. 0 V R 1 = 35Ω R 2 = 25Ω Similarly, we can consider the loop that starts below the battery and goes through the 25 Ω resistor to find the voltage across that resistor. With the voltage and the resistance, we can calculate the current. Equation It is easier for parallel circuits to think of separate loops for each resistor. So, first I will look at the loop starting below the battery then going through the 35 Ω resistor than back to the bottom of the battery. Resistor 1 Resistor 2 Solve The battery must supply both of those currents. So , the current from the battery is the sum of those two currents. Using this loop, we can see that the voltage across the 35 Ω resistor is 5 V. Solve The current through resistor 1 is 0. 143 A and through resistor 2 is 0. 2 A, the current through the battery is 0. 343 A and the voltage across both resistors is 5 V.

Electrical Circuits Determine the current and the voltage for the following circuit. Using the voltage and ohm’s law, we can find the current through all of the resistors. Equation V=5. 0 V R 1 = 35Ω R 2 = 25Ω R 3 = 15Ω Looking at the loops. It doesn’t matter which resistor you consider, you can make a loop that starts at the bottom of the battery and just goes through that individual resistor. So the voltage across all of the resistors is 5. 0 V. Resistor 1 Solve Resistor 2 Resistor 3 The current from the battery is the total current for all of the resistors. Solve The voltage across the resistors is 5 V. The current through resistor 1 is 0. 143 A, through resistor 2 is 0. 2 A, through resistor 3 is 0. 33 A and through the battery is 0. 673 A.

Electrical Circuits Determine the unknown voltages and currents in the circuit below. Now look at the loop that starts below the battery goes through resistor 1 and then through resistor 3. R 1 = 10Ω R 2 = 35Ω V=9. 0 V R 3 = 14 Ω V = 4. 5 V Now using Ohm’s Law we can find the current through that resistor. Equation Solve First, look at the voltage loop that starts below the battery then goes through resistor 1 and resistor 2. Finally, looking at resistor 2 using ohm’s law Equation Using the voltage for resistor 1 and ohm’s law you can find the current through resistor 1. Solve Equation Solve For resistor 1 the voltage drop is 4. 5 V and the current is 0. 45 A. For resistor 2 the voltage drop is 4. 5 V and the current is 0. 32 A. For resistor 3 the voltage is 4. 5 V and the current is 0. 13 A

Electrical Circuits Determine the unknown voltages and currents for the following circuit. Now consider the loop that starts below the battery and goes through resistor 1 and then resistor 3. R 1 = 20Ω V=5 V R 2 = 20Ω R 3 = 30 Ω Using this voltage and ohm’s law. Equation V=8. 0 V Solve First consider the loop that starts below the battery and goes the resistor 1 and resistor 2. Using ohm’s law for resistor 1 Equation Solve Using this voltage and ohm’s law. Equation Solve For resistor 1 the voltage drop is 5 V and the current is 0. 25 A. For resistor 2 the voltage drop is 3 V and the current is 0. 15 A. For resistor 3 the voltage drop is 3 V and the current is 0. 1 A.