Domino algorithm Domino algorithm Domino algorithm Domino algorithm

Domino algorithm

Domino algorithm

Domino algorithm

Domino algorithm ass 1 ass 1 ass 2

Domino algorithm reac 1: ass 1 = ass 2 Pt 1: reac 1 ass 2

Domino algorithm ass 3 ass 4 ass 1 ass 2

Domino algorithm reac 2: ass 3 = ass 4 Pt 2: reac 2 reac 3: ass 4 = ass 1 Pt 3: reac 3 ass 4 ass 1 Pt 4: reac 1 ass 2

Domino algorithm

Domino algorithm

Domino algorithm

Domino algorithm

Domino algorithm

Domino algorithm

Domino algorithm

Domino algorithm

Domino algorithm

Domino algorithm

Domino algorithm

Domino algorithm 5 4 3 2 1 Loop=0 1 2 3 4 5 6

Domino algorithm 5 4 3 2 1 Loop=0 (1/5) (2/5) (3/5) (1/4) (2/4) (3/4) (4/4) (5/4) (6/4) (1/3) (2/3) (3/3) (4/3) (5/3) (6/3) (1/2) (2/2) (3/2) (4/2) (5/2) (6/2) (1/1) (2/1) (3/1) (4/1) (5/1) (6/1) 1 2 3 4 5 6

Domino algorithm 5 4 3 2 1 Loop=0 Pt 18 X=400 Y=44. 9 reac 3 Loop 0: (2/1) - (3/1) Pt 20 X=500 Y=353. 5 reac 3 Loop 0: (3/1) - (4/1) Pt 3 X=550. 0 Y=1000 reac 3 Loop 0: (4/1) - (4/2) 1 2 3 4 5 6

Domino algorithm 5 4 3 2 1 Loop=0 Pt 18 X=400 Y=44. 9 reac 3 Loop 0: (2/1) - (3/1) Pt 20 X=500 Y=353. 5 reac 3 Loop 0: (3/1) - (4/1) Pt 3 X=550. 0 Y=1000 reac 3 Loop 0: (4/1) - (4/2) 1 2 3 4 5 6

Domino algorithm 5 4 3 2 1 Loop=0 Pt 18 X=400 Y=44. 9 reac 3 Loop 0: (2/1) - (3/1) Pt 20 X=500 Y=353. 5 reac 3 Loop 0: (3/1) - (4/1) Pt 3 X=550. 0 Y=1000 reac 3 Loop 0: (4/1) - (4/2) 1 2 3 4 5 6

Domino algorithm

3) ac (re Lin e 3 1) ac re 1( e Lin 2) re ac e 2 ( Li n ac 4 ) 4(re Line e 5( Lin c 5) rea Domino algorithm

3) ac bump 1) ac re (re e 5( Lin ac 4 ) 4(re Line ? 1( Lin e 3 2) re ac e 2 ( c 5) rea two points e Lin Li n Domino algorithm open end

Domino algorithm Loop=1

Domino algorithm Loop=1

Domino algorithm 10 9 8 7 6 5 4 3 2 1 Loop=1 1 2 3 4 5 6 7 8 9 10 11 12

Domino algorithm 10 9 8 7 6 5 4 3 2 1 Loop=1 Pt 20 X=500 Y=353. 5 reac 3 Loop 0: (3/1) - (4/1) 1 2 3 4 5 6 7 8 9 10 11 12

Domino algorithm 10 9 8 7 6 5 4 3 2 1 Loop=1 Pt 20 X=500 Y=353. 5 reac 3 Loop 1: (6/1) - (7/1) 1 2 3 4 5 6 7 8 9 10 11 12

1) 3) ac ac re 1( (re bump e Lin e 3 2) re ac 6) e 2 ( e 5( Lin ac 4 ) 4(re Line ac re ( e 6 Lin Li n c 5) rea Domino algorithm open end

Domino algorithm Loop=2

Domino algorithm

Domino algorithm

Domino algorithm

Domino algorithm