Distributive Property using the Area Model More Practice
Distributive Property using the Area Model More Practice
Find the area of the rectangle. Area = length x width 6 ft 24 ft
Find the area of the rectangle. Area = length x width 6 ft 24 ft
Find the area of the rectangle. Area = length x width 6 ft 20 ft + 4 ft
Find the area of the rectangle. Area = length x width 6 ft 20 ft + 4 ft
Find the area of the rectangle. Area = length x width 6 ft 20 ft + 4 ft
Find the area of the rectangle. Area = length x width Find the area of each rectangle. 6 ft 20 ft + 4 ft
Find the area of the rectangle. Area = length x width Find the area of each rectangle. 6 ft 6 x 20 = 120 sq ft 20 ft 6 ft + 4 ft
Find the area of the rectangle. Area = length x width Find the area of each rectangle. 6 ft 6 x 20 = 120 sq ft 6 x 4 = 24 sq ft 20 ft + 4 ft
Find the area of the rectangle. Area = length x width Find the area of each rectangle. 6 ft 120 sq ft 20 ft 6 ft + 24 sq ft 4 ft
Find the area of the rectangle. Area = length x width Now put the two rectangles back together. 6 ft 120 sq ft 20 ft 6 ft + 24 sq ft 4 ft
Find the area of the rectangle. Area = length x width Now put the two rectangles back together. 6 ft 120 sq ft 20 ft 24 sq ft + 4 ft
Find the area of the rectangle. Area = length x width Now put the two rectangles back together. 6 ft 120 sq ft 20 ft 24 sq ft + 4 ft
Find the area of the rectangle. Area = length x width Now put the two rectangles back together. 6 ft 120 sq ft + 24 sq ft 24 ft
Find the area of the rectangle. Area = length x width Now put the two rectangles back together. 6 ft 144 sq ft 24 ft
A swimming pool has a shallow end a deep end. Find the surface area of the pool. 8 yds deepw ater 5 yds shallow water 10 yds
Break the pool into a deep end a shallow end. 8 yds deepw ater 5 yds 8 yds shallow water 10 yds
Find the area of the deep end. 8 yds deepw ater 5 yds 8 yds shallow water 10 yds
Find the area of the deep end. 8 yds 8 x 5 = 40 5 yds 8 yds shallow water 10 yds
Find the area of the shallow end. 8 yds 8 x 5 = 40 5 yds 8 yds shallow water 10 yds
Find the area of the shallow end. 8 yds 8 x 5 = 40 5 yds 8 x 10 = 80 10 yds
Now sum the two areas together. 8 yds 8 x 5 = 40 5 yds 8 x 10 = 80 10 yds
Now sum the two areas together. 8 yds 40 5 yds + 80 10 yds
40 + 80 = 120 square yards 8 yds 40 5 yds 80 10 yds
Write an expression that shows how to find the area of the rectangle and uses the distributive property. 9 yds 5 yds 20 yds
Find the areas for each individual rectangle. 9 yds 5 yds 20 yds
Find the areas for each individual rectangle. 9 yds (9 x 5) 5 yds 20 yds
Find the areas for each individual rectangle. 9 yds (9 x 5) (9 x 20) 5 yds 20 yds
Sum the two areas. 9 yds (9 x 5) 5 yds + (9 x 20) 20 yds
(9 x 5) + (9 x 20) = area 9 yds (9 x 5) (9 x 20) 5 yds 20 yds
- Slides: 30