Thm 5. 1 Products of disjoint cycles o o Every permutation of a finite set can be written as a product of disjoint cycles. My proof: Let π be a permutation of a set A. Define a relation ~ on A as follows: a~b if πn(a) = b for some integer n > 0. Show ~ is an equivalence relation on A. So ~ partitions A into disjoint equivalence classes. The equivalence class of a can be written as the cycle (a π(a) π2(a)…πm-1(a)).
Thm 5. 2 o o Disjoint cycles commute. Example: Let =(124) = (35) Then =(124)(35) and =(35)(124) In array notation:
My Proof of 5. 2 o The Equivalence classes of the relation ~ do not depend on the order of listing.
Thm 5. 3 Order of a Permutation o o The order of a permutation written in disjoint cycles is the least common multiple of the lengths of the cycles. |(1 2 3 4)| = 4 |(5 6 7 8 9 10)| = 6 |(1 2 3 4)(5 6 7 8 9 10)| = lcm(4, 6) = 12 |(1 2 3)(3 4 5)| = |(1 2 3 4 5)| = 5
Thm 5. 4 Products of 2 -cycles o Every permutation in Sn for n ≥ 1 can be written as the product of 2 -cycles.