CSC 282 Algorithms Daniel Stefankovic CSB 620 stefankocs

CSC 282 – Algorithms Daniel Stefankovic – CSB 620 stefanko@cs. rochester. edu TA: Girts Folkmanis – CSB 614 gfolkman@cs. rochester. edu www. cs. rochester. edu/~stefanko/Teaching/06 CS 282

Grading formula 25% - homework 30% - quizzes 25% - midterm (Tu, Oct. 24) 30% - final (Th, Dec. 21)

25% - homework • turn in before class on the due date • no late homework accepted • two lowest homework scores dropped 30% - quizzes • 1 each week • 10 min • closed book • no make-up quizzes • two lowest quiz grades dropped

What is an algorithm? algorithm = problem-solving procedure Algoritmi de numero Indorum (Al-Khwarizmi Concerning the Hindu Art of Reckoning) CORRECTNESS EFFICIENCY

Problem: is n a prime? PRIMALITY: INSTANCE: a natural number n QUESTION: is n a prime? Is 12345678987654321 a prime?

Problem: is n a prime? Algorithm 1: 1 for k from 2 to n-1 do 2 if k divides n then RETURN “composite” 3 RETURN “prime” Is 12345678987654321 a prime?

Problem: is n a prime? Algorithm 1: 1 for k from 2 to n-1 do 2 if k divides n then RETURN “composite” 3 RETURN “prime” Algorithm 2: 1 for k from 2 to √n do 2 if k divides n then RETURN “composite” 3 RETURN “prime”

Problem: is n a prime? Algorithm 2: 1 for k from 2 to √n do 2 if k divides n then RETURN “composite” 3 RETURN “prime” CORRECT?

Problem: is n a prime? RSA cryptosystem needs primes with 1024 -4096 bits. Running time of our algorithms: Algorithm 1: 21024 – 24096 Algorithm 2:

Problem: is n a prime? RSA cryptosystem needs primes with 1024 -4096 bits. Running time of our algorithms: Algorithm 1: 21024 – 24096 Algorithm 2: 2512 – 22048 NOT EFFICIENT

What means efficient? “efficient program using other efficient as subroutines is efficient” running time is bounded by a polynomial in the input size

Input size How many bits needed to represent n?

Input size How many bits needed to represent n? log n Algorithm 2: 1 for k from 2 to √n do 2 if k divides n then RETURN “composite” 3 RETURN “prime” √n polynomial(log n) ? ? ?

What means efficient? running time is bounded by a polynomial in the input size More refined classification asymptotic notation

Asymptotic notation DEF: Let f, g: N R+. We say f(n) = O(g(n)) if ( C) ( n) f(n) C. g(n)

Asymptotic notation DEF: Let f, g: N R+. We say f(n) = O(g(n)) if ( C) ( n) f(n) C. g(n) 1 2 3 4 5 n 2 + n 3 = O(n 4) n 2 / log(n) = O(n. log n) 5 n + log(n) = O(n) nlog n = O(n 100) 3 n = O(2 n. n 100)

Asymptotic notation 1 2 3 4 5 n 2 + n 3 = O(n 4) n 2 / log(n) O(n. log n) 5 n + log(n) = O(n) nlog n O(n 100) 3 n O(2 n. n 100)

Asymptotic notation 1 2 3 4 5 6 n! = O(3 n) n +1 = O(n) 2 n+1 = O(2 n) (n+1)! = O(n!) 1+c+c 2+…+cn = O(cn) 1+c+c 2+…+cn = O(1) n!= n. (n-1). (n-2) … 3. 2. 1

Asymptotic notation 1 2 3 4 5 6 n! O(3 n) n+1 = O(n) 2 n+1 = O(2 n) (n+1)! O(n!) 1+c+c 2+…+cn = O(cn) 1+c+c 2+…+cn = O(1) for c>1 for c<1

Asymptotic notation DEF: Let f, g: N R+. We say f(n) = (g(n)) if f(n)=O(g(n)) and g(n)=O(f(n))

What means efficient? polynomial-time = running time is bounded by a polynomial in the input size, i. e. , ( k) T(n) = O(nk) More refined analysis = asymptotics for the running time (as a function of input-size) ideally we would like f(n) such that T(n) = (f(n))