Counting Atoms Chemistry is a quantitative science we

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Counting Atoms • Chemistry is a quantitative science - we need a "counting unit.

Counting Atoms • Chemistry is a quantitative science - we need a "counting unit. " • The MOLE • 1 mole is the amount of substance that contains as many particles (atoms or molecules) as there are in 12. 0 g of C-12.

Avogadro Paper The Mole is Developed Carbon Atoms Number Hydrogen Atoms Mass (amu) 12

Avogadro Paper The Mole is Developed Carbon Atoms Number Hydrogen Atoms Mass (amu) 12 Mass (amu) 1 Mass carbon / Mass hydrogen 12 amu = 1 amu 12 1 24 [2 x 12] 2 [2 x 1] 24 amu = 2 amu 120 [10 x 12] 10 [10 x 1] 120 amu = 10 amu 12 1 600 amu = 50 amu 12 1 600 [50 x 12] Avogadro’s (6. 02 x number Number Mass Ratio 1023) x (12) 50 [50 x 1] Avogadro’s number (6. 02 x 1023) x (1) (6. 02 x 1023) x (12) = (6. 02 x 1023) x (1) 12 1

How Big is a Mole? One mole of marbles would cover the entire Earth

How Big is a Mole? One mole of marbles would cover the entire Earth (oceans included) for a depth of two miles. One mole of $1 bills stacked one on top of another would reach from the Sun to Pluto and back 7. 5 million times. It would take light 9500 years to travel from the bottom to the top of a stack of 1 mole of $1 bills.

Particles in a Mole Amedeo Avogadro (1776 – 1856) ? quadrillions trillions billions thousands

Particles in a Mole Amedeo Avogadro (1776 – 1856) ? quadrillions trillions billions thousands millions 1 mole = 60221367360000000 or 6. 022 x 1023 There is Avogadro's number of particles in a mole of any substance.

Avogadro’s Number q A MOLE of any substance contains as many elementary units (atoms

Avogadro’s Number q A MOLE of any substance contains as many elementary units (atoms and molecules) as the number of atoms in 12 g of the isotope of carbon-12. q This number is called AVOGADRO’s number NA = 6. 02 x 1023 particles/mol q The mass of one mole of a substance is called MOLAR MASS symbolized by MM q Units of MM are g/mol q Examples H 2 hydrogen 2. 02 g/mol He helium 4. 0 g/mol N 2 nitrogen 28. 0 g/mol O 2 oxygen 32. 0 g/mol CO 2 carbon dioxide 44. 0 g/mol

Molecular Weight and Molar Mass Molecular weight is the sum of atomic weights of

Molecular Weight and Molar Mass Molecular weight is the sum of atomic weights of all atoms in the molecule. example: Na. Cl has a molecular weight of 58. 5 a. m. u. this is composed of a single molecule of Na. Cl Molar mass = molecular weight in grams. example: Na. Cl has a molar mass of 58. 5 grams this is composed of a 6. 02 x 1023 molecules of Na. Cl

The Molar Mass and Number of Particles in One-Mole Quantities Substance Molar Mass Number

The Molar Mass and Number of Particles in One-Mole Quantities Substance Molar Mass Number of Particles in One Mole Carbon (C) 12. 0 g 6. 02 x 1023 C atoms Sodium (Na) 23. 0 g 6. 02 x 1023 Na atoms Iron (Fe) 55. 9 g 6. 02 x 1023 Fe atoms Na. F (preventative for dental cavities) 42. 0 g 6. 02 x 1023 Na. F formula units Ca. CO 3 (antacid) 100. 1 g 6. 02 x 1023 Ca. CO 3 formula units C 6 H 12 O 6 (glucose) 180. 0 g 6. 02 x 1023 glucose molecules C 8 H 10 N 4 O 2 (caffeine) 194. 0 g 6. 02 x 1023 caffeine molecules

Stoichiometry Island Diagram Known Mass Substance A Substance B 1 m ole = )

Stoichiometry Island Diagram Known Mass Substance A Substance B 1 m ole = ) mo lar Volume (gases) Unknown ma ss rm ola (g ) ole 1 m Use coefficients from balanced chemical equation 1 mole = 22. 4 L @ STP Mole = g s( Mass as m 1 mole = 22. 4 L @ STP Mole Volume (gases) s Particles cle rti a p ) 23 s 10 cule x e 22 ol 6. 0 or m = s ole (atom m 1 1 m ole (at om = 6. 0 22 x 1 rm 0 23 ole pa r cu les ticle s ) so Particles Stoichiometry Island Diagram

Stoichiometry Island Diagram Known Unknown Substance A Substance B M Mass Mountain Mass Liter

Stoichiometry Island Diagram Known Unknown Substance A Substance B M Mass Mountain Mass Liter Lagoon V Volume Mole Volume Particles P Particle Place Stoichiometry Island Diagram