Concept Questions A wire initially carrying no current

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Concept Questions A wire, initially carrying no current, has a radius that starts decreasing

Concept Questions A wire, initially carrying no current, has a radius that starts decreasing at t = 0. As it shrinks, which way does current begin to flow in the loop? A) Clockwise B) Counter-clockwise C) No current D) Insufficient information • Calculate flux downwards – we get EMF clockwise • Flux is decreasing • Derivative of flux is negative • EMF is positive clockwise • Current will flow clockwise • Right hand rule – B-field The current that flows will then create a downwards magnetic field, which inside the loop, will • Reinforces magnetic field A) Strengthen it B) Weaken it • Tries to keep the B-flux constant C) No change D) Insufficient information

Concept Question What happens as I drop the magnet into the copper tube? A)

Concept Question What happens as I drop the magnet into the copper tube? A) Falls as usual B) Falls slower C) Falls faster D) Floats constant E) Pops back up and out • As magnet falls, some places have magnetic fields that diminish • Current appears, replacing magnetic field • This acts like a magnet, pulling it back up • At bottom end, current appears to oppose change • This repels the magnet, slowing it down • Current is only caused by motion of magnet • If motion stops, resistance stops current • If motion is small, opposition will be small • It doesn’t stop, it goes slowly S N N S What if we used a superconductor?

Concept Question What is Kirchoff’s law for the loop shown? A) E + L

Concept Question What is Kirchoff’s law for the loop shown? A) E + L (d. I /dt) = 0 B) E – L (d. I /dt) = 0 C) None of the above D) I don’t know Kirchoff’s law for switches I E+ – • The voltage change for an inductor is L (d. I/dt) • Negative if with the current • Positive if against the current L

6 A 6 A 6 A R 2 = 4 L + – In

6 A 6 A 6 A R 2 = 4 L + – In the steady state, with the switch closed, how much current flows through R 2? How much current flows through R 2 the moment after we open the switch? A) 0 A B) 6 A C) 3 A D) 2 A E) None of the above R 1 = 2 Concept Question E = 12 V • In the steady state, the inductor is like a wire • Both ends of R 2 are at the same potential: no current through R 2 • The remaining structure had current I = E/R 1 = 6 A running through it I = E /R 1 = 6 A • Now open the switch – what happens? • Inductors resist changes in current, so the current instantaneously is unchanged in inductor I=6 A • It must pass through R 2

I=1 A – E = 10 V • Note that inductors can produce very

I=1 A – E = 10 V • Note that inductors can produce very high voltages • Inductance causes sparks to jump when you turn a switch off + – Loop has unintended inductance R 2 = 1 k • The current remains constant at 1 A • It must pass through resistor R 2 • The voltage is given by V = IR L + The circuit at right is in a steady state. What will the voltmeter read as soon as the switch is opened? A) 0. l V B) 1 V C) 10 V D) 100 V E) 1000 V R 1 = 10 Concept Question V

Concept Question A capacitor with charge on it has energy U = Q 2/2

Concept Question A capacitor with charge on it has energy U = Q 2/2 C, but Q is constantly changing. Where does the energy go? A) It is lost in the resistance of the wire B) It is stored as kinetic energy of the electrons C) It is stored in the inductor D) Hollywood! I C Q L • Let’s find the energy in the capacitor and the inductor Energy sloshes back and forth

Concept Question If the voltage from a source looks like the graph below, about

Concept Question If the voltage from a source looks like the graph below, about what voltage should it be labeled? A) 0 V B) 170 V C) 120 V D) 85 V E) It should be labeled some other way • Average voltage is zero, but that doesn’t tell us anything • Maximum voltage 170 V is an overstatement • Power is usually proportional to voltage squared

Concept Question A 60 W light bulb is plugged into a standard outlet (

Concept Question A 60 W light bulb is plugged into a standard outlet ( Vrms = 120 V). What is the resistance of the bulb? A) 15 B) 30 C) 60 D) 120 E) 240

Capacitors and Resistors Combined • Capacitors and resistors both limit the current – they

Capacitors and Resistors Combined • Capacitors and resistors both limit the current – they both have impedance • Resistors: same impedance at all frequencies • Capacitors: more impedance at low frequencies Concept Question The circuit at right might be designed to: (A) Let low frequencies through, but block high frequencies (B) Let high frequencies through, but block low frequencies (C) Let small currents through, but not big currents (D) Let big currents through, but not small currents

Impedance Table Resistor Impedance R Phase 0 Vector Direction right Inductors are good for

Impedance Table Resistor Impedance R Phase 0 Vector Direction right Inductors are good for (A) Blocking low frequencies (B) Blocking high frequencies (C) Blocking large currents (D) Blocking small currents Capacitor Inductor down up

Concept Question In the mystery box at right, we can put a 2. 0

Concept Question In the mystery box at right, we can put a 2. 0 F capacitor, a 4. 0 H inductor, or both (in series). Which one will cause the greatest current to flow through the circuit? A) The capacitor B) The inductor C) both D) Insufficient information 60 Hz 170 V L= 4. 0 H 1. 3 k 1. 5 k ? 2. 0 F • We want to minimize impedance • Make the vector sum as short as possible • Recall, capacitors point down, inductors up • The sum is shorter than either separately 1. 4 k

Concept Question L C R f Vmax How will XL and XC compare at

Concept Question L C R f Vmax How will XL and XC compare at the frequency where the maximum power is delivered to the resistor? A) XL > XC B) XL < XC C) XL = XC D) Insufficient information • Resonance happens when XL = XC. • This makes Z the smallest • It happens only at one frequency • Same frequency we got for LC circuit

Concept Question • In the example we just did, we found only some frequencies

Concept Question • In the example we just did, we found only some frequencies get through What happens if this is impossible to meet, because 1/RC > R/L? A) The inequality gets reversed, R/L < < 1/RC B) Pretty much everything gets blocked C) Only a very narrow frequency range gets through L C R f Vmax = 5 V

Concept Question When the voltage shown in blue was passed through two components in

Concept Question When the voltage shown in blue was passed through two components in series, the current shown in red resulted. What two components might they be? A) Capacitor and Inductor B) Inductor and Resistor C) Capacitor and Resistor Voltage Current • The phase shift represents how the timing of the current compares to the timing of the voltage • When it is positive, the current lags the voltage • It rises/falls/peaks later • When it is negative, the current leads the voltage • It rises/falls/peaks earlier

 V 2 = 120 V N 1 =5000 V 1 = 10 k.

V 2 = 120 V N 1 =5000 V 1 = 10 k. V A transformer has 10, 000 V AC going into it, and it is supposed to produce 120 V AC, suitable for household use. If the primary winding has 5, 000 turns, how many should the secondary have? A) 120 B) 240 C) 60 D) None of the above N 2 =? Concept Question

Concept Question A wave has an electric field given by What does the magnetic

Concept Question A wave has an electric field given by What does the magnetic field look like? A) B) C) D) • The magnitude of the wave is B 0 = E 0 / c • The wave is traveling in the z-direction, because of sin(kz - t). • The wave must be perpendicular to the E-field, so perpendicular to j • The wave must be perpendicular to direction of motion, to k • It must be in either +i direction or –i direction • If in +i direction, then E B would be in direction j i = - k, wrong • So it had better be in the –i direction

 Increasing f Increasing Concept Question Radio Waves Microwaves Infrared Visible Ultraviolet X-rays Gamma

Increasing f Increasing Concept Question Radio Waves Microwaves Infrared Visible Ultraviolet X-rays Gamma Rays Red Orange Yellow Green Blue Violet Which of the following waves has the highest speed in vacuum? A) Infrared B) Orange C) Green D) It’s a tie E) Not enough info

Cross-Section • To calculate the power falling on an object, all that matters is

Cross-Section • To calculate the power falling on an object, all that matters is the light that hits it • Example, a rectangle parallel to the light feels no pressure • Ask yourself: what area does the light see? • This is called the cross section If light of intensity S hits an absorbing sphere of radius a, what is the force on that sphere? A) a 2 S /c B) 2 a 2 S /c C) 4 a 2 S /c • As viewed from any side, a sphere looks like a circle of radius a • The cross section for a sphere, then, is a 2

Equations for Test 3 Faraday’s Law Impedance: Power and Pressure Transformers: Inductors: Units: Frequency,

Equations for Test 3 Faraday’s Law Impedance: Power and Pressure Transformers: Inductors: Units: Frequency, Wavelength Speed of Light End of material for Test 3