 # COMP 1321 Digital Infrastructure Richard Henson University of

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Download presentation COMP 1321 Digital Infrastructure Richard Henson University of Worcester October 2012 Week 2: CPUs and Motherboards Problem for Processor design Data needs to be stored n Memory consists of ‘cells’ (effectively switches) n ØRecorded digitally » either a “ 0” or a “ 1” » no middle way Binary Numbers n n Base 2… based on 0 and 1 To represent binary, need “on/off” switches Ø mechanical… too slow Ø electronic… Ok if fast enough » early electronic switches large and needed a lot of energy » Head of IBM (1950 s) said that the world needed only four of these computers anyway (!) » use of transistors made the computer more widespread Number Theory: decimal representation of 2, 314 2 Thousands 10 x 10 103 3 Hundreds 10 x 10 102 1 Tens 10 101 4 units 1 100 bracket form: (2 x 103) + (3 x 102) + (1 x 101) + (4 x 100 ) most significant digit 2 least significant digit 4 Some definitions… binary digit bit 0 or 1 n byte: a group of 8 bits n (nibble: a group of 4 bits) n word: a group of bits of a fixed length (actual length of a word is rather arbitrary) n Binary representation of the four bit word 1101 1 1 0 1 2 x 2 x 2 2 1 23 22 21 20 bracket form: (1 x 23) + (1 x 22) + (0 x 21) + (1 x 20 ) 8 + 4 + 0 + 1 = 13 in denary (decimal) Binary representation of the 8 bit word 1011 0101 27 26 25 24 23 22 21 20 1 0 1 0 1 128 + 0 + 32 + 16 + 0 + 4+ 0 + 1 = 181 Q. How many different binary numbers can an 8 bit word hold? A. 256 (= 28) ranging from 0000 to 1111 The 16 bit number 0000 0011 0101 n (a) To what decimal number is it equal? n (b) What is the value of the most significant bit? n (c) How many different 16 bit binary numbers can be represented? The 16 bit number 0000 0011 0101 (a) To what decimal number is it equal? Answer: 32 + 16 + 0 + 4 + 0 + 1 = 53 n (b) What is the value of the most significant bit? Answer: 0 n (c) How many different 16 bit binary numbers can be represented? Answer: 216 = 65536 (which is 64 k) n Shorthand Rows of 1 s and 0 s can be very confusing n Easy to make mistakes n Solution: divide into blocks of 4 digits use the decimal numbers corresponding to each block n Problem: confusion with 10 or more n Solution: use letters for 10 to 15 n Hexadecimal notation Decimal 0 1 2 3 4 5 6 7 8 9 Binary Hexadecimal 0000 0001 0010 0011 0100 0101 0110 0111 1000 1001 0 1 2 3 4 5 6 7 8 9 Hexadecimal notation Decimal 10 11 12 13 14 15 Binary 1010 1011 1100 1101 1110 1111 Hexadecimal A B C D E F Notation n Useful to know what type of number we are dealing with e. g. “ 110” Øuse subscript at the end Ø 11010 = 110 (denary) Ø 1102 = 110 (binary) = 6 (denary) Ø 110 H or 11016 = 110 (hexadecimal) = 272 (denary) n So now you know! Now, let’s make a Computer … at least the CPU … Pentium 4 Ultra Sparc 1 Pentium 3 Opteron Itanium 2 Mc. Kinley 21364  CPU with INPUT & OUTPUT Computer Program (Code) 1 do this… 2 do that 3 now this 4 goto 1 Plus Data… Memory CPU Keyboard VDU Pentium Data Cache Code Cache Instruction Fetch Instruction Decode Execution Unit Minimalist CPU What is needed to build a CPU? ALU (Arithmetic Logic Unit) Memory (to store intermediate data) Input Output “Execution Unit” A Good Name ! Arithmetic Logic Unit Input A Input B ALU (or Integer Execution Unit) 3 add Output 2 5 3 sub 2 1 Processing Idea Nr. 1 Move data in and out of data memory store 1. Move data from memory 3 2. add 2 5 0 3 1 2 2 3 5 Memory DRAM, Hard Disk. . 4 3. Move data into memory Processing Idea Nr. 2 Move instructions into CPU from code memory Instruction Memory (Code Memory) mov 3 in from memory 3 mov 2 in from memory IP add the two numbers mov the result to memory Program add 2 5 0 3 1 2 2 3 4 5 Registers are high-speed memory on the CPU chip Parking places for data on the move AX and BX are used for ALU operations AX BX 6 8 0 6 1 8 MAR 4 MAR is memory address register, here 4. So result, 6+8=14 will go into memory cell address 4 4 Our computer so far … 0 1 Instruction Memory Data Memory mar ip 4 A couple of extra bits 1. Line of code goes in 2. Electrical bit signals come out Instruction Register 1. Memory Data Register add ax, bx 2. Instruction Memory 34 Data • • • Energize ax Energize bx Select ALU “add" 0 2 1 8 Data Memory 2 Address 4 34 Moving data into Registers For example … mov ax ,  mov bx ,  Instruction Memory AX BX 8 7 mar 0 5 1 8 2 7 3 6 4 1 mov ax ,  mov bx , Moving data into Memory For example … mov  , ax mov  , bx Instruction Memory AX BX 8 7 mov  , ax mov , bx mar 0 7 5 1 8 2 7 3 8 6 4 1 Adding Numbers For example … Add ax, bx Instruction Memory AX BX 8 7 15 mar 0 5 1 8 2 7 3 6 4 1 add ax , bx … this means ‘ add ax to bx, put the answer in ax’ So THAT’S how it works! Next week: the programming!