College Algebra Twelfth Edition Chapter 2 Graphs and

Section 2. 3 Functions • Relations and Functions • Domain and Range • Determining Whether Relations Are Functions • Function Notation • Increasing, Decreasing, and Constant Functions Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved Slide - 2

Relation A relation is a set of ordered pairs. Copyright © 2017, 2013, 2009

Function A function is a relation in which, for each distinct value of the first component of the ordered pairs, there is exactly one value of the second component. Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved Slide - 4

Example 1: Deciding Whether Relations Define Functions (1 of 3) Decide whether the relation defines a function. Solution Relation F is a function, because for each different x-value there is exactly one yvalue. We can show this correspondence as follows. x-values of F y-values of F Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved Slide - 5

Example 1: Deciding Whether Relations Define Functions (2 of 3) Decide whether the relation defines a function. Solution As the correspondence below shows, relation G is not a function because one first component corresponds to more than one second component. x-values of G y-values of G Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved Slide - 6

Example 1: Deciding Whether Relations Define Functions (3 of 3) Decide whether the relation defines a function. Solution In relation H the last two ordered pairs have the same x-value paired with two different y-values, so H is a relation but not a function. Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved Slide - 7

Mapping (1 of 2) Relations and functions can also be expressed as a correspondence or mapping from one set to another. In the example below the arrow from 1 to 2 indicates that the ordered pair (1, 2) belongs to F. Each first component is paired with exactly one second component. Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved Slide - 8

Mapping (2 of 2) In the mapping for relation H, which is not a function, the first component − 2 is paired with two different second components, 1 and 0. Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved Slide - 9

Relations Note Another way to think of a function relationship is to think of the independent variable as an input and the dependent variable as an output. Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved Slide - 10

Domain and Range In a relation consisting of ordered pairs (x, y), the set of all values of the independent variable (x) is the domain. The set of all values of the dependent variable (y) is the range. Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved Slide - 11

Example 2: Finding Domains and Ranges of Relations (1 of 3) Give the domain and range of each relation. Tell whether the relation defines a function. (a) The domain is the set of x-values, The range is the set of y-values, This relation is not a function because the same x-value, 4, is paired with two different y -values, 2 and 5. Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved Slide - 12

Example 2: Finding Domains and Ranges of Relations (2 of 3) Give the domain and range of each relation. Tell whether the relation defines a function. (b) The domain is and the range is This mapping defines a function. Each x-value corresponds to exactly one y-value. Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved Slide - 13

Example 2: Finding Domains and Ranges of Relations (3 of 3) Give the domain and range of each relation. Tell whether the relation defines a function. (c) x − 5 0 5 y 2 2 2 This relation is a set of ordered pairs, so the domain is the set and the of x-values range is the set of y-values The table defines a function because each different x-value corresponds to exactly one yvalue. Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved Slide - 14

Example 3: Finding Domains and Ranges From Graphs (1 of 4) Give the domain and range of each relation. (a) The domain is the set of xvalues which are The range is the set of y-values, Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved Slide - 15

Example 3: Finding Domains and Ranges From Graphs (2 of 4) Give the domain and range of each relation. (b) The x-values of the points on the graph include all numbers between − 4 and 4, inclusive. The y-values include all numbers between − 6 and 6, inclusive. The domain is The range is Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved Slide - 16

Example 3: Finding Domains and Ranges From Graphs (3 of 4) Give the domain and range of each relation. (c) The arrowheads indicate that the line extends indefinitely left and right, as well as up and down. Therefore, both the domain and the range include all real numbers, which is written Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved Slide - 17

Example 3: Finding Domains and Ranges From Graphs (4 of 4) Give the domain and range of each relation. (d) The arrowheads indicate that the line extends indefinitely left and right, as well as upward. The domain is Because there is a least yvalue, − 3, the range includes all numbers greater than or equal to − 3, written Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved Slide - 18

Agreement on Domain Unless specified otherwise, the domain of a relation is assumed to be all real numbers that produce real numbers when substituted for the independent variable. Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved Slide - 19

Vertical Line Test If every vertical line intersects the graph of a relation in no more than one point, then the relation is a function. Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved Slide - 20

Example 4: Using the Vertical Line Test (1 of 4) Use the vertical line test to determine whether each relation graphed is a function. (a) The graph of this relation passes the vertical line test, since every vertical line intersects the graph no more than once. Thus, this graph represents a function. Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved Slide - 21

Example 4: Using the Vertical Line Test (2 of 4) Use the vertical line test to determine whether each relation graphed is a function. (b) The graph of this relation fails the vertical line test, since the same x-value corresponds to two different y-values. Therefore, it is not the graph of a function. Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved Slide - 22

Example 4: Using the Vertical Line Test (3 of 4) Use the vertical line test to determine whether each relation graphed is a function. (c) The graph of this relation passes the vertical line test, because every vertical line intersects the graph no more than once. Thus, this graph represents a function. Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved Slide - 23

Example 4: Using the Vertical Line Test (4 of 4) Use the vertical line test to determine whether each relation graphed is a function. (d) The graph of this relation passes the vertical line test, since every vertical line intersects the graph no more than once. Thus, this graph represents a function. Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved Slide - 24

Example 5: Identifying Functions Domains, and Ranges (1 of 7) Decide whether each relation defines y as a function of x and give the domain and range. (a) Solution In the defining equation (or rule), y is always found by adding 4 to x. Thus, each value of x corresponds to just one value of y, and the relation defines a function. The variable x can represent any real number, so the domain is Because y is always 4 more than x, y also may be any real number, and so the range is Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved Slide - 25

Example 5: Identifying Functions Domains, and Ranges (2 of 7) Decide whether each relation defines a function and give the domain and range. (b) Solution For any choice of x in the domain, there is exactly one corresponding value for y (the radical is a nonnegative number), so this equation defines a function. The equation involves a square root, the quantity under the radical cannot be negative. Solve the inequality. Add 1. Divide by 2. Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved Slide - 26

Example 5: Identifying Functions Domains, and Ranges (3 of 7) Decide whether each relation defines a function and give the domain and range. (b) Solution The domain is Because the radical must represent a non-negative number, as x takes values greater than or equal to Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved Slide - 27

Example 5: Identifying Functions Domains, and Ranges (4 of 7) Decide whether each relation defines a function and give the domain and range. (c) Solution The ordered pairs (16, 4) and (16, − 4) both satisfy the equation. There exists a value of x, 16, that corresponds to two values of y, 4 and − 4, so this equation does not define a function. The domain is Any real number can be squared, so the range of the relation is Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved Slide - 28

Example 5: Identifying Functions Domains, and Ranges (5 of 7) Decide whether each relation defines a function and give the domain and range. (d) Solution By definition, y is a function of x if every value of x leads to exactly one value of y. Substituting a particular value of x into the inequality corresponds to many values of y. The ordered pairs (1, 0), (1, − 1), (1, − 2), and (1, − 3) all satisfy the inequality. Any number can be used for x or for y, so the domain and range are both the set of real numbers, or Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved Slide - 29

Example 5: Identifying Functions Domains, and Ranges (6 of 7) Decide whether each relation defines a function and give the domain and range. (e) Solution Given any value of x in the domain of the relation, we find y by subtracting 1 from x and then dividing the result into 5. This process produces exactly one value of y for each value in the domain, so this equation defines a function. Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved Slide - 30

Example 5: Identifying Functions Domains, and Ranges (7 of 7) Decide whether each relation defines a function and give the domain and range. (e) Solution The domain includes all real numbers except those making the denominator 0. Add 1. Thus, the domain includes all real numbers except 1 and is written The range is the interval Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved Slide - 31

Variations of the Definition of Function 1. A function is a relation in which, for each distinct value of the first component of the ordered pairs, there is exactly one value of the second component. 2. A function is a set of ordered pairs in which no first component is repeated. 3. A function is a rule or correspondence that assigns exactly one range value to each distinct domain value. Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved Slide - 32

Function Notation (1 of 3) When a function is defined with a rule or an equation using x and y for the independent and dependent variables, we say “y is a function of x” to emphasize that y depends on x. We use the notation called function notation, to express this and read as “ of x” or at x The letter is the name given to this function. For example, if we can name the function and write Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved Slide - 33

Function Notation (2 of 3) Note that is just another name for the dependent variable y. For example, if then we find y, or by replacing x with 2. The statement “if x = 2, then y = 1” represents the ordered pair (2, 1) and is abbreviated with function notation as The symbol is read “ of 2” or “ at 2. ” Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved Slide - 34

Function Notation (3 of 3) These ideas can be illustrated as follows. Copyright ©

Caution does not indicate “ times The symbol x, ” but represents the y-value associated with the indicated x-value. As just shown, is the y-value that corresponds to the x-value 2. Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved Slide - 36

Example 6: Using Function Notation (1 of 3) Let each of the following. Simplifying in parts (a) and (c) only. (a) Solution Replace x with 2. Apply the exponent; multiply. Add and subtract. Thus, the ordered pair (2, 3) belongs to . Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved Slide - 37

Example 6: Using Function Notation (2 of 3) Let and simplify each of the

Example 6: Using Function Notation (3 of 3) Let and simplify each of the following. (c) Solution Replace x with a + 1. Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved Slide - 39

Example 7: Using Function Notation (1 of 4) For each function, find (a) Solution

Example 7: Using Function Notation (2 of 4) For each function, find (b) Solution For the y-value of the ordered pair we want where x = 3. As indicated by the ordered pair (3, 1), when x = 3, y = 1, so Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved Slide - 41

Example 7: Using Function Notation (3 of 4) For each function, find (c) Solution In the mapping, the domain element 3 is paired with 5 in the range, so Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved Slide - 42

Example 7: Using Function Notation (4 of 4) For each function, find (d) Solution Find 3 on the x-axis. Then move up until the graph of f is reached. Moving horizontally to the y-axis gives 4 for the corresponding y-value. Thus Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved Slide - 43

Finding an Expression for f of x Consider an equation involving x and y. Assume that y can be expressed as a function of x. To find an expression for use the following steps. Step 1 Solve the equation for y. Step 2 Replace y with Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved Slide - 44

Example 8: Writing Equations Using Function Notation (1 of 3) Assume that y is a function of x. Rewrite each equation using function notation. Then find (a) Solution Let Now find Let x = − 2. Let x = p. Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved Slide - 45

Example 8: Writing Equations Using Function Notation (2 of 3) Assume that y is a function of x. Rewrite each equation using function notation. Then find (b) Solution Solve for y. Multiply by − 1; divide by 4. Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved Slide - 46

Example 8: Writing Equations Using Function Notation (3 of 3) Assume that y is a function of x. Rewrite each equation using function notation. Then find (b) Solution Now find Let x = − 2. Let x = p. Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved Slide - 47

Increasing, Decreasing, and Constant Functions Suppose that a function f is defined over an open interval I and are in I. (a) increases on I if, whenever (b) decreases on I if, whenever (c) is constant on I if, for every Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved Slide - 48

Example 9: Determining Increasing, Decreasing, or Constant Intervals Determine the largest open intervals of the domain for which the function is increasing, decreasing, or constant. Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved Slide - 49

Example 9: Determining Intervals Over Which a Function is Increasing, Decreasing, or Constant (1 of 2) Determine the intervals over which the function is increasing, decreasing, or constant. Solution On the open interval the y-values are decreasing; on the open interval (− 2, 1), the y-values are increasing; on the open interval the y-values are constant (and equal to 8). Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved Slide - 50

Example 9: Determining Intervals Over Which a Function is Increasing, Decreasing, or Constant (2 of 2) Determine the intervals over which the function is increasing, decreasing, or constant. Solution Therefore, the function is decreasing on increasing on (− 2, 1), and constant Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved Slide - 51

Example 10: Interpreting a Graph (1 of 5) This graph shows the relationship between the number of gallons, of water in a small swimming pool and time in hours, t. By looking at this graph of the function, we can answer questions about the water level in the pool at various times. For example, at time 0 the pool is empty. The water level then increases, stays constant for a while, decreases, and then becomes constant again. Use the graph to respond to the following. Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved Slide - 52

Example 10: Interpreting a Graph (2 of 5) (a) What is the maximum number of gallons of water in the pool? When is the maximum water level first reached? Solution The maximum range value is 3000. This maximum number of gallons, 3000, is first reached at Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved Slide - 53

Example 10: Interpreting a Graph (3 of 5) (b) For how long is the water level increasing? decreasing? constant? Solution The water level is increasing for and is decreasing for It is constant for Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved Slide - 54

Example 10: Interpreting a Graph (4 of 5) (c) How many gallons of water are in the pool after 90 h r? ou Solution When t = 90, There are 2000 gal after 90 h r. ou Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved Slide - 55

Example 10: Interpreting a Graph (5 of 5) (d) Describe a series of events that could account for the water level changes shown in the graph. Solution The pool is empty at the beginning and then is filled to a level of 3000 gal during the first 25 h r. For the next 25 h r, the water level then remains the same. At 50 h r, the pool starts to be drained, and this draining lasts for 25 h r, until only 2000 gal remain. For the next 25 h r, the water level is unchanged. ou ou ou Copyright © 2017, 2013, 2009 Pearson Education, Inc. All Rights Reserved Slide - 56