Circle Tangent Equation Higher GCSE Questions These questions

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Circle – Tangent Equation – Higher – GCSE Questions These questions are the same

Circle – Tangent Equation – Higher – GCSE Questions These questions are the same format as previous GCSE exams. COPY means they use the exact same numbers as the original GCSE question. Otherwise, they are clone questions using different numbers. The worksheets are provided in a variety of sizes.

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GCSE 1 Edexcel Higher: June 2017 Paper 2, Q 23 G is the circle

GCSE 1 Edexcel Higher: June 2017 Paper 2, Q 23 G is the circle with equation x 2 + y 2 = 4 Find an equation of the tangent to G at point T. (Total for Question 1 is 3 marks)

GCSE 1 Edexcel Higher: November 2017 Paper 3, Q 19 Prove algebraically that the

GCSE 1 Edexcel Higher: November 2017 Paper 3, Q 19 Prove algebraically that the straight line with equation is a tangent to the circle with equation x 2 + y 2 = 20 x – 2 y = 10 (Total for Question 1 is 5 marks)

GCSE 1 Edexcel Higher: June 2017 Paper 2, Q 23 G is the circle

GCSE 1 Edexcel Higher: June 2017 Paper 2, Q 23 G is the circle with equation x 2 + y 2 = 4 Find an equation of the tangent to G at point T. (Total for Question 1 is 3 marks)

GCSE 1 Edexcel Higher: November 2017 Paper 3, Q 19 Prove algebraically that the

GCSE 1 Edexcel Higher: November 2017 Paper 3, Q 19 Prove algebraically that the straight line with equation is a tangent to the circle with equation x 2 + y 2 = 20 x – 2 y = 10 (Total for Question 1 is 5 marks)

GCSE 1 Edexcel Higher: June 2017 Paper 2, Q 23 G is the circle

GCSE 1 Edexcel Higher: June 2017 Paper 2, Q 23 G is the circle with equation x 2 + y 2 = 4 Find an equation of the tangent to G at point T. Ta ng en t (Total for Question 1 is 3 marks)

GCSE 1 Edexcel Higher: November 2017 Paper 3, Q 19 Prove algebraically that the

GCSE 1 Edexcel Higher: November 2017 Paper 3, Q 19 Prove algebraically that the straight line with equation is a tangent to the circle with equation x 2 + y 2 = 20 x – 2 y = 10 Tangent = only one 1 solution x = 10 + 2 y (10 + 2 y)2 + y 2 = 20 (10 + 2 y) + y 2 = 20 (100 + 20 y + 4 y 2) + y 2 = 20 5 y 2 + 40 y + 100 = 20 5 y 2 + 40 y + 80 = 0 y 2 + 8 y + 16 = 0 (y + 4) = 0 y = -4 x – (2 x -4) = 10 x – (-8) = 10 x + 8 = 10 x=2 1 solution means line is tangent to circle. (Total for Question 1 is 5 marks)

Questions? Comments? Suggestions? …or have you found a mistake!? Any feedback would be appreciated

Questions? Comments? Suggestions? …or have you found a mistake!? Any feedback would be appreciated . Please feel free to email: tom@goteachmaths. co. uk