Chapter 6 Stability Stability Definitions A system is

Chapter 6 Stability

Stability Definitions • A system is stable if the natural response approaches zero as time approaches infinity • A system is unstable if the natural response approaches infinity as time approaches infinity • A system is marginally stable if the natural response neither decays nor grows but remains constant or oscillates. • A system is stable if every bounded input yields a bounded output • A system is unstable if any bounded input yields an unbounded output

Common cause of problems in finding closed-loop poles: a. original system; b. equivalent system Stable systems have closed-loop transfer functions with poles in the left half-plane. Unstable systems have closed-loop transfer functions with at least one pole in the right half-plane, and/or poles of multiplicity greater than one on the imaginary axis Marginally stable systems have closed-loop transfer functions with only imaginary axis poles of multiplicity one and poles in the left halfplane.

Routh-Hurwitz Criterion Using this method we can tell how many closed-loop poles are in the left half-plane, in the right half-plane and on the imaginary axis. The method requires two steps: (1) Generate the data table (Routh table) and (2) Interpret the table to determine the number of poles in LHP and RHP.

Initial layout for Routh table

Completed Routh table

Feedback system for Example 6. 1; b. Equivalent closed-loop system

Completed Routh table for Example 6. 1 Interpretation of Routh table The number of roots of the polynomial that are in the right half-plane is equal to the number of sign changes in the first column.

R-H: Special case. Zero in the first column Replace the zero with from –ive or +ive side. , the value of is then allowed to approach zero Problem Determine the stability of the closed-loop transfer function

R-H: Special case. Zero in the first column Problem Determine the stability of the closed-loop transfer function Solution Write a polynomial that has the reciprocal roots of the denominator

R-H: Special case. Entire row is zero Problem Determine the number of right-half-plane poles in the closed transfer function Solution: Form an auxiliary polynomial, P(s) using the entries of row above row of zeros as coefficient, then differentiate with respect to s finally use coefficients to replace the rows of zeros and continue the RH procedure.

Root positions to generate even polynomials: A , B, C, or any combination An entire row of zeros will appear when a purely even or odd polynomial is a factor of the original polynomial. Even polynomials have roots that are symmetrical about the origin. If we don’t have a row of zeros, we cannot possibly have roots on the imaginary axis.

Routh table for Example 6. 5 Problem Determine the number of poles in the right-half-plane, left-halfplan and on the axis for the closed transfer function

Summary of pole locations for Example 6. 5

Feedback control system for Example 6. 6 Problem Determine the number of poles in the right-half-plane, left-halfplan and on the axis for system Solution: The closed loop transfer function is

Routh table for Example 6. 6 2 poles in RHP, 2 poles in LHP no poles on The system is unstable axis

Feedback control system for Example 6. 7 Problem Determine the number of poles in the right-half-plane, left-halfplan and on the axis for system Solution: The closed loop transfer function is

Routh table for Example 6. 7 Table for polynomial whose roots are the reciprocal of the original 2 sign changes, 2 poles in RHP system is unstable

Feedback control system for Example 6. 8 Problem Determine the number of poles in the right-half-plane, left-halfplan and on the axis for system. Draw conclusions about stability of the closed loop system. Solution: The closed loop transfer function is

Routh table for Example 6. 8 There is a row of zeros in the s 5, so the s 6 row forms an even polynomial. 2 sign changes from the even polynomial so 2 poles in the RHP and because of symmetry about origin 2 will be in the LHP The 2 remaining poles are on the axis

Summary of pole locations for Example 6. 5

Feedback control system for Example 6. 9 Problem Find the range of gain K for the system that will cuase the system to be stable, unstabel, and marginally stable. Assume K>0. Solution: The closed loop transfer function is

Routh table for Example 6. 9 For K < 1386 the system is stable. For K > 1386 the system is unstable. For K = 1386 we will have entire row of zeros (s row). We form the even polynomial and differentiate and continue, no sign changes from the even polynomial so the 2 roots are on the axis and the system is marginally stable

Routh table for Example 6. 10 Problem Factor the polynomial Solution: from the Routh table we see that the s 1 row is a row of zeros. So the even polynomial at the s 2 row is since this polynomial is a factor of the original, dividing yields As the other factor so

Stability is State Space Example 6. 11 Problem Given the system Find out how many poles in the LHP, RHP and on the Solution: First form (s. I-A) Now find the det (s. I-A) = axis

Routh table for Example 6. 11 One sign change, so 1 pole in the LHP and the system is unstable