Chapter 5 Chemical Reactions and Quantities Chemical Changes
- Slides: 24
Chapter 5 Chemical Reactions and Quantities Chemical Changes Balancing Chemical Equations Lecture. PLUS Timberlake 1
Physical Properties color melting point boiling point electrical conductivity density state (solid, liquid, or gas) Lecture. PLUS Timberlake 2
Physical Changes in physical properties melting boiling condensation No change occurs in the identity of the substance Example: Ice , rain, and. Lecture. PLUS steam are all water 3 Timberlake
Chemical Change Atoms in the reactants are rearranged to form one or more different substances Old bonds are broken; new bonds form Examples: Fe and O 2 form rust (Fe 2 O 3) Ag and S form tarnish (Ag 2 S) Lecture. PLUS Timberlake 4
Learning Check E 1 Classify each of the following as a 1) physical change or 2) chemical change A. ____ a burning candle B. ____ melting ice C. ____ toasting a marshmallow D. ____ cutting a pizza E. ____ polishing silver Lecture. PLUS Timberlake 5
Solution E 1 Classify each of the following as a 1) physical change or 2) chemical change A. __2__ a burning candle B. __1_ melting ice C. __2__ toasting a marshmallow D. __1__ cutting a pizza E. __2__ polishing silver Lecture. PLUS Timberlake 6
Chemical Reaction A process in which at least one new substance is produced as a result of chemical change. Lecture. PLUS Timberlake 7
A Chemical Reaction Reactants Products Lecture. PLUS Timberlake 8
Learning Check E 2 A. How does an equation indicate a change in the identity of the reacting substances? B. How did the yellow and green reactants combine? C. Did all the reactants form product? Why or why not? Lecture. PLUS Timberlake 9
Learning Check E 2 A. How does an equation indicate a change in the identity of the reacting substances? The formulas of the reactants are different than the formulas of the products. B. How did the yellow and green reactants combine? 1 yellow combined with 1 green. C. Did all the reactants form product? Why or why not? No. There were more yellow reactants than green. Lecture. PLUS Timberlake 10
Writing a Chemical Equation Chemical symbols give a “before-and-after” picture of a chemical reaction Reactants Mg. O + Products C magnesium oxide reacts with carbon CO to form Lecture. PLUS Timberlake + Mg carbon monoxide and magnesium 11
Learning Check E 3 12 oz of dough, 4 oz mushrooms, 12 slices pepperoni, 8 oz cheese and 5 oz tomato sauce are used to make a pizza. Write a recipe in words for putting together a pizza. How would you write the recipe as an equation? Lecture. PLUS Timberlake 12
Solution E 3 Example: Combine 12 oz dough + 4 oz mushrooms + 12 slices pepperoni + 8 oz cheese + 5 oz tomato sauce and heat 30 minutes at 350°C to produce 1 pizza 12 oz dough + 4 oz mshrm + 12 pep + 8 oz chse 1 pizza + 5 oz tom sauce Lecture. PLUS Timberlake 13
Reading A Chemical Equation 4 NH 3 + 5 O 2 4 NO + 6 H 2 O Four molecules of NH 3 react with five molecules O 2 to produce four molecules NO and six molecules of H 2 O or Four moles NH 3 react with 5 moles O 2 to produce four moles NO and six moles H 2 O Lecture. PLUS Timberlake 14
A Balanced Chemical Equation Same numbers of each type of atom on each side of the equation Al + S Al 2 S 3 Not Balanced 2 Al + 3 S Al 2 S 3 Balanced Lecture. PLUS Timberlake 15
Matter Is Conserved H 2 + Cl 2 2 HCl + + Total atoms 2 H, 2 Cl = Total atoms 2 H, 2 Cl Total Mass 2(1. 0) + 2(35. 5) 73. 0 g = Total Mass 2(36. 5) 73. 0 g = Lecture. PLUS Timberlake 16
Law of Conservation of Mass In any ordinary chemical reaction, matter is not created nor destroyed Lecture. PLUS Timberlake 17
Balance Equations with Coefficients in front of formulas balance each type of atom 4 NH 3 + 5 O 2 4 NO + 6 H 2 O 4 N = 4 N 12 H = 12 H 10 O = 10 O Lecture. PLUS Timberlake 18
Steps in Balancing An Equation Fe 3 O 4 + H 2 Fe + H 2 O Fe: Fe 3 O 4 + H 2 3 Fe + H 2 O O: Fe 3 O 4 + H 2 3 Fe + 4 H 2 O H: Fe 3 O 4 + 4 H 2 3 Fe + 4 H 2 O Lecture. PLUS Timberlake 19
Learning Check E 4 Fe 3 O 4 + 4 H 2 3 Fe + 4 H 2 O A. Number of H atoms in 4 H 2 O 1) 2 2) 4 3) 8 B. Number of O atoms in 4 H 2 O 1) 2 2) 4 3) 8 C. Number of Fe atoms in Fe 3 O 4 1) 1 2) 3 Lecture. PLUS Timberlake 3) 4 20
Solution E 4 Fe 3 O 4 + 4 H 2 3 Fe + 4 H 2 O A. Number of H atoms in 4 H 2 O 3) 8 B. Number of O atoms in 4 H 2 O 2) 4 C. Number of Fe atoms in Fe 3 O 4 2) 3 Lecture. PLUS Timberlake 21
Learning Check E 5 Balance each equation. The coefficients for each equation are read from left to right A. Mg + 1) 1, 3, 2 B. Al + 1) 3, 3, 2 N 2 2) 3, 1, 2 Cl 2 2) 1, 3, 1 Lecture. PLUS Timberlake Mg 3 N 2 3) 3, 1, 1 Al. Cl 3 3) 2, 3, 2 22
Learning Check E 5 C. Fe 2 O 3 + 1) 2, 3, 2, 3 D. Al Al + + Fe 2) 2, 3, 4, 3 Fe + 2) 2, 1, 1, 1 H 2 SO 4 1) 3, 2, 1, 2 2) 2, 3, 1, 3 Lecture. PLUS Timberlake + CO 2 3) 1, 1, 2, 3 Fe. O 1) 2, 3, 3, 1 E. C Al 2 O 3 3) 3, 3, 3, 1 Al 2(SO 4)3 + H 2 3) 2, 3, 2, 3 23
Solution E 5 A. 3 Mg + N 2 Mg 3 N 2 B. 2 Al + 3 Cl 2 2 Al. Cl 3 C. 2 Fe 2 O 3 + 3 C D. 2 Al + 3 Fe. O E. 2 Al + 3 H 2 SO 4 Lecture. PLUS Timberlake 4 Fe + 3 CO 2 3 Fe + Al 2 O 3 Al 2(SO 4)3 24 + 3 H 2
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