Chapter 34 The Wave Nature of Light Interference

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Chapter 34 The Wave Nature of Light; Interference Copyright © 2009 Pearson Education, Inc.

Chapter 34 The Wave Nature of Light; Interference Copyright © 2009 Pearson Education, Inc.

Units of Chapter 34 • Waves versus Particles; Huygens’ Principle and Diffraction • Huygens’

Units of Chapter 34 • Waves versus Particles; Huygens’ Principle and Diffraction • Huygens’ Principle and the Law of Refraction • Interference – Young’s Double-Slit Experiment • Intensity in the Double-Slit Interference Pattern • Interference in Thin Films • Michelson Interferometer • Luminous Intensity Copyright © 2009 Pearson Education, Inc.

34 -1 Waves versus Particles; Huygens’ Principle and Diffraction Huygens’ principle: every point on

34 -1 Waves versus Particles; Huygens’ Principle and Diffraction Huygens’ principle: every point on a wave front acts as a point source; the wave front as it develops is tangent to all the wavelets. Copyright © 2009 Pearson Education, Inc.

34 -1 Waves versus Particles; Huygens’ Principle and Diffraction Huygens’ principle is consistent with

34 -1 Waves versus Particles; Huygens’ Principle and Diffraction Huygens’ principle is consistent with diffraction: Copyright © 2009 Pearson Education, Inc.

34 -2 Huygens’ Principle and the Law of Refraction Copyright © 2009 Pearson Education,

34 -2 Huygens’ Principle and the Law of Refraction Copyright © 2009 Pearson Education, Inc.

34 -2 Huygens’ Principle and the Law of Refraction Huygens’ principle can also explain

34 -2 Huygens’ Principle and the Law of Refraction Huygens’ principle can also explain the law of refraction. As the wavelets propagate from each point, they propagate more slowly in the medium of higher index of refraction. This leads to a bend in the wave front and therefore in the ray. Copyright © 2009 Pearson Education, Inc.

34 -2 Huygens’ Principle and the Law of Refraction The frequency of the light

34 -2 Huygens’ Principle and the Law of Refraction The frequency of the light does not change, but the wavelength does as it travels into a new medium: Copyright © 2009 Pearson Education, Inc.

34 -2 Huygens’ Principle and the Law of Refraction Highway mirages are due to

34 -2 Huygens’ Principle and the Law of Refraction Highway mirages are due to a gradually changing index of refraction in heated air. Copyright © 2009 Pearson Education, Inc.

Bouncing light (1972) Copyright © 2009 Pearson Education, Inc.

Bouncing light (1972) Copyright © 2009 Pearson Education, Inc.

Concep. Test 34. 1 Superposition If waves A and B are superposed (that is,

Concep. Test 34. 1 Superposition If waves A and B are superposed (that is, their amplitudes are added) the resultant wave is 1) 2) 3) 4)

Concep. Test 34. 1 Superposition If waves A and B are superposed (that is,

Concep. Test 34. 1 Superposition If waves A and B are superposed (that is, their amplitudes are added) the resultant wave is 1) The amplitudes of waves A and B have to 2) be added at each point! 3) 4)

Concep. Test 34. 2 a The two waves shown are 1) out of phase

Concep. Test 34. 2 a The two waves shown are 1) out of phase by 180 o 2) out of phase by 90 o 3) out of phase by 45 o 4) out of phase by 360 o 5) in phase Phase Difference I

Concep. Test 34. 2 a Phase Difference I The two waves shown are 1/4

Concep. Test 34. 2 a Phase Difference I The two waves shown are 1/4 1) out of phase by 180 o 2) out of phase by 90 o 3) out of phase by 45 o 4) out of phase by 360 o 5) in phase The two waves are out of phase by 1/4 wavelength (as seen in the figure), which corresponds to a phase difference of 90 o. Follow-up: What would the waves look like for (4) to be correct?

34 -3 Interference – Young’s Double. Slit Experiment If light is a wave, interference

34 -3 Interference – Young’s Double. Slit Experiment If light is a wave, interference effects will be seen, where one part of a wave front can interact with another part. One way to study this is to do a double-slit experiment: Copyright © 2009 Pearson Education, Inc.

34 -3 Interference – Young’s Double. Slit Experiment If light is a wave, there

34 -3 Interference – Young’s Double. Slit Experiment If light is a wave, there should be an interference pattern. Copyright © 2009 Pearson Education, Inc.

34 -3 Interference – Young’s Double. Slit Experiment The interference occurs because each point

34 -3 Interference – Young’s Double. Slit Experiment The interference occurs because each point on the screen is not the same distance from both slits. Depending on the path length difference, the wave can interfere constructively (bright spot) or destructively (dark spot). Copyright © 2009 Pearson Education, Inc.

34 -3 Interference – Young’s Double. Slit Experiment We can use geometry to find

34 -3 Interference – Young’s Double. Slit Experiment We can use geometry to find the conditions for constructive and destructive interference: and Copyright © 2009 Pearson Education, Inc.

34 -3 Interference – Young’s Double. Slit Experiment Between the maxima and the minima,

34 -3 Interference – Young’s Double. Slit Experiment Between the maxima and the minima, the interference varies smoothly. Copyright © 2009 Pearson Education, Inc.

Concep. Test 34. 3 a Double Slits I In a double-slit experiment, when 1)

Concep. Test 34. 3 a Double Slits I In a double-slit experiment, when 1) spreads out the wavelength of the light is 2) stays the same increased, the interference 3) shrinks together pattern 4) disappears

Concep. Test 34. 3 a Double Slits I In a double-slit experiment, when 1)

Concep. Test 34. 3 a Double Slits I In a double-slit experiment, when 1) spreads out the wavelength of the light is 2) stays the same increased, the interference 3) shrinks together pattern d sin = m If is increased and d does not change, change then must increase, increase so the pattern spreads out. 4) disappears

34 -3 Interference – Young’s Double. Slit Experiment Conceptual Example 34 -1: Interference pattern

34 -3 Interference – Young’s Double. Slit Experiment Conceptual Example 34 -1: Interference pattern lines. (a) Will there be an infinite number of points on the viewing screen where constructive and destructive interference occur, or only a finite number of points? (b) Are neighboring points of constructive interference uniformly spaced, or is the spacing between neighboring points of constructive interference not uniform? Copyright © 2009 Pearson Education, Inc.

34 -3 Interference – Young’s Double. Slit Experiment Example 34 -2: Line spacing for

34 -3 Interference – Young’s Double. Slit Experiment Example 34 -2: Line spacing for double-slit interference. A screen containing two slits 0. 100 mm apart is 1. 20 m from the viewing screen. Light of wavelength λ = 500 nm falls on the slits from a distant source. Approximately how far apart will adjacent bright interference fringes be on the screen? Copyright © 2009 Pearson Education, Inc.

34 -3 Interference – Young’s Double. Slit Experiment Conceptual Example 34 -3: Changing the

34 -3 Interference – Young’s Double. Slit Experiment Conceptual Example 34 -3: Changing the wavelength. (a) What happens to the interference pattern in the previous example if the incident light (500 nm) is replaced by light of wavelength 700 nm? (b) What happens instead if the wavelength stays at 500 nm but the slits are moved farther apart? Copyright © 2009 Pearson Education, Inc.

Concep. Test 34. 4 Path Difference In a double-slit experiment, what 1) there is

Concep. Test 34. 4 Path Difference In a double-slit experiment, what 1) there is no difference path difference have the waves 2) half a wavelength from each slit traveled to give a 3) one wavelength position? 4) three wavelengths 5) more than three wavelengths Intensity minimum at the indicated

Concep. Test 34. 4 Path Difference In a double-slit experiment, what 1) there is

Concep. Test 34. 4 Path Difference In a double-slit experiment, what 1) there is no difference path difference have the waves 2) half a wavelength from each slit traveled to give a 3) one wavelength minimum at the indicated position? 4) three wavelengths 5) more than three wavelengths Intensity 3 2 For destructive interference 7 /2 5 /2 3 /2 = (m + 1/2) /2 = 1/2 , 3/2 , 5/2 , 7/2 , …

34 -3 Interference – Young’s Double. Slit Experiment Since the position of the maxima

34 -3 Interference – Young’s Double. Slit Experiment Since the position of the maxima (except the central one) depends on wavelength, the firstand higher-order fringes contain a spectrum of colors. Copyright © 2009 Pearson Education, Inc.

34 -3 Interference – Young’s Double. Slit Experiment Example 34 -4: Wavelengths from double-slit

34 -3 Interference – Young’s Double. Slit Experiment Example 34 -4: Wavelengths from double-slit interference. White light passes through two slits 0. 50 mm apart, and an interference pattern is observed on a screen 2. 5 m away. The firstorder fringe resembles a rainbow with violet and red light at opposite ends. The violet light is about 2. 0 mm and the red 3. 5 mm from the center of the central white fringe. Estimate the wavelengths for the violet and red light. Copyright © 2009 Pearson Education, Inc.

34 -4 Intensity in the Double-Slit Interference Pattern The electric fields at the point

34 -4 Intensity in the Double-Slit Interference Pattern The electric fields at the point P from the two slits are given by . where Treat Copyright © 2009 Pearson Education, Inc. and as components of vectors

34 -4 Intensity in the Double-Slit Interference Pattern The two waves can be added

34 -4 Intensity in the Double-Slit Interference Pattern The two waves can be added using phasors, to take the phase difference into account: if Copyright © 2009 Pearson Education, Inc.

34 -4 Intensity in the Double-Slit Interference Pattern The time-averaged intensity is proportional to

34 -4 Intensity in the Double-Slit Interference Pattern The time-averaged intensity is proportional to the square of the field: Copyright © 2009 Pearson Education, Inc.

34 -4 Intensity in the Double-Slit Interference Pattern This plot shows the intensity as

34 -4 Intensity in the Double-Slit Interference Pattern This plot shows the intensity as a function of angle. Copyright © 2009 Pearson Education, Inc.

34 -4 Intensity in the Double-Slit Interference Pattern Example 34 -5: Antenna intensity. Two

34 -4 Intensity in the Double-Slit Interference Pattern Example 34 -5: Antenna intensity. Two radio antennas are located close to each other, separated by a distance d. The antennas radiate in phase with each other, emitting waves of intensity I 0 at wavelength λ. (a) Calculate the net intensity as a function of θ for points very far from the antennas. (b) For d = λ, determine I and find in which directions I is a maximum and a minimum. (c) Repeat part (b) when d = λ/2. Copyright © 2009 Pearson Education, Inc.

34 -5 Interference in Thin Films Another way path lengths can differ, and waves

34 -5 Interference in Thin Films Another way path lengths can differ, and waves interfere, is if they travel through different media. If there is a very thin film of material – a few wavelengths thick – light will reflect from both the bottom and the top of the layer, causing interference. This can be seen in soap bubbles and oil slicks. Some light always reflects at the interface of two media with n 1 n 2 Copyright © 2009 Pearson Education, Inc.

34 -5 Interference in Thin Films The wavelength of the light will be different

34 -5 Interference in Thin Films The wavelength of the light will be different in the oil and the air, and the reflections at points A and B may or may not involve phase changes. Copyright © 2009 Pearson Education, Inc.

34 -5 Interference in Thin Films A similar effect takes place when a shallowly

34 -5 Interference in Thin Films A similar effect takes place when a shallowly curved piece of glass is placed on a flat one. When viewed from above, concentric circles appear that are called Newton’s rings. Copyright © 2009 Pearson Education, Inc.

34 -5 Interference in Thin Films A beam of light reflected by a material

34 -5 Interference in Thin Films A beam of light reflected by a material with index of refraction greater than that of the material in which it is traveling, changes phase by 180° or ½ cycle. Copyright © 2009 Pearson Education, Inc.

Concep. Test 34. 6 a Parallel Slides I Consider two identical microscope 1) all

Concep. Test 34. 6 a Parallel Slides I Consider two identical microscope 1) all black slides in air illuminated with light from 2) all white a laser. The slides are exactly parallel, and the top slide is moving slowly upward. What do you see when looking from the top view? 3) fringes moving apart 4) alternately all black, then all bright

Concep. Test 34. 6 a Parallel Slides I Consider two identical microscope 1) all

Concep. Test 34. 6 a Parallel Slides I Consider two identical microscope 1) all black slides in air illuminated with light from 2) all white a laser. The slides are exactly parallel, and the top slide is moving slowly upward. What do you see when looking from the top view? As the distance between the two slides decreases, the path difference between the interfering rays changes. Thus, the phase between the interfering rays keeps changing, alternately in phase (constructive) and out of phase (destructive) as the top slide moves. 3) fringes moving apart 4) alternately all black, then all bright

34 -5 Interference in Thin Films Example 34 -6: Thin film of air, wedge-shaped.

34 -5 Interference in Thin Films Example 34 -6: Thin film of air, wedge-shaped. A very fine wire 7. 35 x 10 -3 mm in diameter is placed between two flat glass plates. Light whose wavelength in air is 600 nm falls (and is viewed) perpendicular to the plates and a series of bright and dark bands is seen. How many light and dark bands will there be in this case? Will the area next to the wire be bright or dark? Copyright © 2009 Pearson Education, Inc.

34 -5 Interference in Thin Films Example 34 -7: Thickness of soap bubble skin.

34 -5 Interference in Thin Films Example 34 -7: Thickness of soap bubble skin. A soap bubble appears green (λ = 540 nm) at the point on its front surface nearest the viewer. What is the smallest thickness the soap bubble film could have? Assume n = 1. 35. Copyright © 2009 Pearson Education, Inc.

34 -5 Interference in Thin Films Problem Solving: Interference 1. Interference occurs when two

34 -5 Interference in Thin Films Problem Solving: Interference 1. Interference occurs when two or more waves arrive simultaneously at the same point in space. 2. Constructive interference occurs when the waves are in phase. 3. Destructive interference occurs when the waves are out of phase. 4. An extra half-wavelength shift occurs when light reflects from a medium with higher refractive index. Copyright © 2009 Pearson Education, Inc.

34 -5 Interference in Thin Films Example 34 -8: Nonreflective coating. What is the

34 -5 Interference in Thin Films Example 34 -8: Nonreflective coating. What is the thickness of an optical coating of Mg. F 2 whose index of refraction is n = 1. 38 and which is designed to eliminate reflected light at wavelengths (in air) around 550 nm when incident normally on glass for which n = 1. 50? Copyright © 2009 Pearson Education, Inc.

Concep. Test 34. 6 c Parallel Slides III Consider two identical microscopic slides in

Concep. Test 34. 6 c Parallel Slides III Consider two identical microscopic slides in air illuminated with light 1) spaced farther apart from a laser. The bottom slide is rotated upward so that the wedge 2) spaced closer together angle gets a bit smaller. What 3) no change happens to the interference fringes? ray 2 ray 1 ray 3 t

Concep. Test 34. 6 c Parallel Slides III Consider two identical microscopic slides in

Concep. Test 34. 6 c Parallel Slides III Consider two identical microscopic slides in air illuminated with light 1) spaced farther apart from a laser. The bottom slide is rotated upward so that the wedge 2) spaced closer together angle gets a bit smaller. What 3) no change happens to the interference fringes? The path difference between ray 2 and ray 3 is 2 t (in addition, ray 3 experiences a phase change of 180°). Thus, the dark fringes will occur for: 2 t = m l m = 0, 1, 2, … If t gets smaller, ray 2 and ray 3 have to be farther apart before they can interfere, so the fringes move apart. ray 2 ray 1 ray 3 t

34 -6 Michelson Interferometer The Michelson interferometer is centered around a beam splitter, which

34 -6 Michelson Interferometer The Michelson interferometer is centered around a beam splitter, which transmits about half the light hitting it and reflects the rest. It can be a very sensitive measure of length. Copyright © 2009 Pearson Education, Inc.

34 -7 Luminous Intensity The intensity of light as perceived depends not only on

34 -7 Luminous Intensity The intensity of light as perceived depends not only on the actual intensity but also on the sensitivity of the eye at different wavelengths. Luminous flux: 1 lumen = 1/683 W of 555 -nm light Luminous intensity: 1 candela = 1 lumen/steradian Illuminance: luminous flux per unit area Copyright © 2009 Pearson Education, Inc.

34 -7 Luminous Intensity Example 34 -9: Lightbulb illuminance. The brightness of a particular

34 -7 Luminous Intensity Example 34 -9: Lightbulb illuminance. The brightness of a particular type of 100 -W lightbulb is rated at 1700 lm. Determine (a) the luminous intensity and (b) the illuminance at a distance of 2. 0 m. Copyright © 2009 Pearson Education, Inc.

Summary of Chapter 34 • The wave theory of light is strengthened by the

Summary of Chapter 34 • The wave theory of light is strengthened by the interference and diffraction of light. • Huygens’ principle: every point on a wave front is a source of spherical wavelets. • Wavelength of light in a medium with index of refraction n: • Young’s double-slit experiment demonstrated interference. Copyright © 2009 Pearson Education, Inc.

Summary of Chapter 34 • In the double-slit experiment, constructive interference occurs when •

Summary of Chapter 34 • In the double-slit experiment, constructive interference occurs when • and destructive interference when • Two sources of light are coherent if they have the same frequency and maintain the same phase relationship. Copyright © 2009 Pearson Education, Inc.

Summary of Chapter 34 • Interference can occur between reflections from the front and

Summary of Chapter 34 • Interference can occur between reflections from the front and back surfaces of a thin film. • Light undergoes a 180° phase change if it reflects from a medium of higher index of refraction. Copyright © 2009 Pearson Education, Inc.