Chapter 21 Electric Charge and Electric Field Copyright

  • Slides: 38
Download presentation
Chapter 21 Electric Charge and Electric Field Copyright © 2009 Pearson Education, Inc.

Chapter 21 Electric Charge and Electric Field Copyright © 2009 Pearson Education, Inc.

21 -11 Electric Dipoles An electric dipole consists of two charges Q, equal in

21 -11 Electric Dipoles An electric dipole consists of two charges Q, equal in magnitude and opposite in sign, separated by a distance. The dipole moment, p = Q , points from the negative to the positive charge. Copyright © 2009 Pearson Education, Inc.

21 -11 Electric Dipoles An electric dipole in a uniform electric field will experience

21 -11 Electric Dipoles An electric dipole in a uniform electric field will experience no net force, but it will, in general, experience a torque: (cf. Chapt. 10) So how was I able to move the 2 x 4 using the electric field of the rod? Copyright © 2009 Pearson Education, Inc.

21 -11 Electric Dipoles Recall: The electric field created by a dipole is the

21 -11 Electric Dipoles Recall: The electric field created by a dipole is the sum of the fields created by the two charges; far from the dipole, the field shows a 1/r 3 dependence: Copyright © 2009 Pearson Education, Inc.

Along p axis Copyright © 2009 Pearson Education, Inc.

Along p axis Copyright © 2009 Pearson Education, Inc.

21 -11 Electric Dipoles Example: The dipole moment of a water molecule is 6.

21 -11 Electric Dipoles Example: The dipole moment of a water molecule is 6. 3 x 10 -30 C·m. A sample contains 1021 water molecules, with their dipole moments all oriented in the direction of an electric field of 2. 5 x 105 N/C. How much work is required to rotate the dipoles from this orientation ( = 0 ) to one in which all moments are perpendicular to the field ( = 90 )? Copyright © 2009 Pearson Education, Inc.

Solution: Copyright © 2009 Pearson Education, Inc.

Solution: Copyright © 2009 Pearson Education, Inc.

21 -13 Photocopy Machines and Computer Printers Use Electrostatics Photocopy machine: • drum is

21 -13 Photocopy Machines and Computer Printers Use Electrostatics Photocopy machine: • drum is charged positively • image is focused on drum • only black areas stay charged and therefore attract toner particles • image is transferred to paper and sealed by heat Copyright © 2009 Pearson Education, Inc.

21 -13 Photocopy Machines and Computer Printers Use Electrostatics Copyright © 2009 Pearson Education,

21 -13 Photocopy Machines and Computer Printers Use Electrostatics Copyright © 2009 Pearson Education, Inc.

21 -13 Photocopy Machines and Computer Printers Use Electrostatics Laser printer is similar, except

21 -13 Photocopy Machines and Computer Printers Use Electrostatics Laser printer is similar, except a computer controls the laser intensity to form the image on the drum. Copyright © 2009 Pearson Education, Inc.

Summary of Chapter 21 • Two kinds of electric charge – positive and negative.

Summary of Chapter 21 • Two kinds of electric charge – positive and negative. • Charge is conserved. • Charge on electron: e = 1. 602 x 10 -19 C. • Conductors: electrons free to move. • Insulators: nonconductors. Copyright © 2009 Pearson Education, Inc.

Summary of Chapter 21 • Charge is quantized in units of e. • Objects

Summary of Chapter 21 • Charge is quantized in units of e. • Objects can be charged by conduction or induction. • Coulomb’s law: • Electric field is force per unit charge: Copyright © 2009 Pearson Education, Inc.

Summary of Chapter 21 • Electric field of a point charge: • Electric field

Summary of Chapter 21 • Electric field of a point charge: • Electric field can be represented by electric field lines. • Static electric field inside conductor is zero; surface field is perpendicular to surface. Copyright © 2009 Pearson Education, Inc.

Chapter 22 Gauss’s Law Copyright © 2009 Pearson Education, Inc.

Chapter 22 Gauss’s Law Copyright © 2009 Pearson Education, Inc.

Units of Chapter 22 • Electric Flux • Gauss’s Law • Applications of Gauss’s

Units of Chapter 22 • Electric Flux • Gauss’s Law • Applications of Gauss’s Law • Experimental Basis of Gauss’s and Coulomb’s Laws Copyright © 2009 Pearson Education, Inc.

22 -1 Electric Flux Electric flux: Electric flux through an area is proportional to

22 -1 Electric Flux Electric flux: Electric flux through an area is proportional to the total number of field lines crossing the area. Copyright © 2009 Pearson Education, Inc.

22 -1 Electric Flux Example 22 -1: Electric flux. Calculate the electric flux through

22 -1 Electric Flux Example 22 -1: Electric flux. Calculate the electric flux through the rectangle shown. The rectangle is 10 cm by 20 cm, the electric field is uniform at 200 N/C, and the angle θ is 30°. Copyright © 2009 Pearson Education, Inc.

22 -1 Electric Flux through a closed surface: Copyright © 2009 Pearson Education, Inc.

22 -1 Electric Flux through a closed surface: Copyright © 2009 Pearson Education, Inc.

22 -2 Gauss’s Law Copyright © 2009 Pearson Education, Inc.

22 -2 Gauss’s Law Copyright © 2009 Pearson Education, Inc.

22 -2 Gauss’s Law Copyright © 2009 Pearson Education, Inc.

22 -2 Gauss’s Law Copyright © 2009 Pearson Education, Inc.

22 -2 Gauss’s Law The net number of field lines through the surface is

22 -2 Gauss’s Law The net number of field lines through the surface is proportional to the charge enclosed, and also to the flux, giving Gauss’s law: This can be used to find the electric field in situations with a high degree of symmetry. Copyright © 2009 Pearson Education, Inc.

22 -2 Gauss’s Law For a point charge, Spherical symmetry Therefore, Solving for E

22 -2 Gauss’s Law For a point charge, Spherical symmetry Therefore, Solving for E gives the result we expect from Coulomb’s law: Copyright © 2009 Pearson Education, Inc.

22 -2 Gauss’s Law Using Coulomb’s law to evaluate the integral of the field

22 -2 Gauss’s Law Using Coulomb’s law to evaluate the integral of the field of a point charge over the surface of a sphere surrounding the charge gives: Looking at the arbitrarily shaped surface A 2, we see that the same flux passes through it as passes through A 1. Therefore, this result should be valid for any closed surface. Copyright © 2009 Pearson Education, Inc.

22 -2 Gauss’s Law Finally, if a gaussian surface encloses several point charges, the

22 -2 Gauss’s Law Finally, if a gaussian surface encloses several point charges, the superposition principle shows that: Therefore, Gauss’s law is valid for any charge distribution. Note, however, that it only refers to the field due to charges within the gaussian surface – charges outside the surface will also create fields. Copyright © 2009 Pearson Education, Inc.

22 -2 Gauss’s Law The figure shows five charged clumps of plastic and an

22 -2 Gauss’s Law The figure shows five charged clumps of plastic and an electrically neutral coin as well as a Gaussian surface S. What is the flux through S if the charges are: ? Copyright © 2009 Pearson Education, Inc.

22 -2 Gauss’s Law A charge of 1. 8 n. C is placed at

22 -2 Gauss’s Law A charge of 1. 8 n. C is placed at the center of a cube 3 cm on an edge. What is the electric flux through each face? Copyright © 2009 Pearson Education, Inc.

22 -2 Gauss’s Law A charge of 1. 8 n. C is placed at

22 -2 Gauss’s Law A charge of 1. 8 n. C is placed at the center of a cube 3 cm on an edge. What is the electric flux through each face? Copyright © 2009 Pearson Education, Inc.

22 -3 Applications of Gauss’s Law Example 22 -3: Spherical conductor. A thin spherical

22 -3 Applications of Gauss’s Law Example 22 -3: Spherical conductor. A thin spherical shell of radius r 0 possesses a total net charge Q that is uniformly distributed on it. Determine the electric field at points (a) outside the shell, and (b) within the shell. (c) What if the conductor were a solid sphere? Copyright © 2009 Pearson Education, Inc. Spherical symmetry

22 -3 Applications of Gauss’s Law Example 22 -4: Solid sphere of charge. An

22 -3 Applications of Gauss’s Law Example 22 -4: Solid sphere of charge. An electric charge Q is distributed uniformly throughout a nonconducting sphere of radius r 0. Determine the electric field (a) outside the sphere (r > r 0) and (b) inside the sphere (r < r 0). Copyright © 2009 Pearson Education, Inc. Spherical symmetry

22 -3 Applications of Gauss’s Law Example 22 -5: Nonuniformly charged solid sphere. Suppose

22 -3 Applications of Gauss’s Law Example 22 -5: Nonuniformly charged solid sphere. Suppose the charge density of a solid sphere is given by ρE = αr 2, where α is a constant. (a) Find α in terms of the total charge Q on the sphere and its radius r 0. (b) Find the electric field as a function of r inside the sphere. Copyright © 2009 Pearson Education, Inc. Spherical symmetry

22 -3 Applications of Gauss’s Law Example 22 -6: Long uniform line of charge.

22 -3 Applications of Gauss’s Law Example 22 -6: Long uniform line of charge. A very long straight wire possesses a uniform positive charge per unit length, λ. Calculate the electric field at points near (but outside) the wire, far from the ends. Cylindrical symmetry Copyright © 2009 Pearson Education, Inc.

22 -3 Applications of Gauss’s Law Example 22 -7: Infinite plane of charge. Charge

22 -3 Applications of Gauss’s Law Example 22 -7: Infinite plane of charge. Charge is distributed uniformly, with a surface charge density σ (σ = charge per unit area = d. Q/d. A) over a very large but very thin nonconducting flat plane surface. Determine the electric field at points near the plane. Copyright © 2009 Pearson Education, Inc. Planar, Cylindrical, & Mirror Symmetry

22 -3 Applications of Gauss’s Law Example 22 -8: Electric field near any conducting

22 -3 Applications of Gauss’s Law Example 22 -8: Electric field near any conducting surface. Show that the electric field just outside the surface of any good conductor of arbitrary shape is given by E = σ/ε 0 where σ is the surface charge density on the conductor’s surface at that point. Copyright © 2009 Pearson Education, Inc. Approximate Planar & Cylindrical Symmetry

22 -3 Applications of Gauss’s Law Conceptual Example 22 -9: Conductor with charge inside

22 -3 Applications of Gauss’s Law Conceptual Example 22 -9: Conductor with charge inside a cavity. Suppose a conductor carries a net charge +Q and contains a cavity, inside of which resides a point charge +q. What can you say about the charges on the inner and outer surfaces of the conductor? Copyright © 2009 Pearson Education, Inc.

22 -3 Applications of Gauss’s Law Procedure for Gauss’s law problems: 1. Identify the

22 -3 Applications of Gauss’s Law Procedure for Gauss’s law problems: 1. Identify the symmetry, and choose a gaussian surface that takes advantage of it (with surfaces along surfaces of constant field). 2. Draw the surface. 3. Use the symmetry to find the direction of E. 4. Evaluate the flux by integrating. 5. Calculate the enclosed charge. 6. Solve for the field. Copyright © 2009 Pearson Education, Inc.

22 -4 Experimental Basis of Gauss’s and Coulomb’s Laws In the experiment shown, Gauss’s

22 -4 Experimental Basis of Gauss’s and Coulomb’s Laws In the experiment shown, Gauss’s law predicts that the charge on the ball flows onto the surface of the cylinder when they are in contact. This can be tested by measuring the charge on the ball after it is removed – it should be zero. Copyright © 2009 Pearson Education, Inc.

Summary of Chapter 22 • Electric flux: • Gauss’s law can be used to

Summary of Chapter 22 • Electric flux: • Gauss’s law can be used to calculate the field in situations with a high degree of symmetry. • Gauss’s law applies in all situations. • Follows from Coulomb’s Law Copyright © 2009 Pearson Education, Inc.

Questions? Copyright © 2009 Pearson Education, Inc.

Questions? Copyright © 2009 Pearson Education, Inc.