Chapter 12 Kinematics ME 242 Chapter 12 Question

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Chapter 12 Kinematics

Chapter 12 Kinematics

ME 242 Chapter 12 Question 1 We obtain the acceleration fastest (A)By taking the

ME 242 Chapter 12 Question 1 We obtain the acceleration fastest (A)By taking the derivative of x(t) (B)By Integrating x(t) twice (C)By integrating the accel as function of displacement (D)By computing the time to liftoff, then choosing the accel such that the velocity is 160 mph

ME 242 Chapter 12 160 mi/h = 235 ft/s Question 2 The acceleration is

ME 242 Chapter 12 160 mi/h = 235 ft/s Question 2 The acceleration is approximately (A)92 ft/s 2 (B)66 ft/s 2 (C)85. 3 ft/s 2 (D)182 ft/s 2 (E)18. 75 ft/s 2 Ya pili

ME 242 Chapter 12 Solution: 160 mi/h = 235 ft/s We use v*dv =

ME 242 Chapter 12 Solution: 160 mi/h = 235 ft/s We use v*dv = a*dx 1/ v 2 = a*d, Integrate: 2 Question 2 The acceleration is approximately where d is the length of the runway, and the 2 (A)92 ft/s start velocity = 0 (B)66 ft/s 2 (C)85. 3 ft/s 2 (D)182 ft/s 2 (E) 18. 75 ft/s 2 Ya kwanza

Question 3 Road map: We obtain the velocity fastest (A)By Taking the derivative of

Question 3 Road map: We obtain the velocity fastest (A)By Taking the derivative of a(t) (B)By Integrating a(t) (C)By integrating the accel as function of displacement (D)By computing the time to bottom, then computing the velocity.

ME 242 Tutoring • Graduate Assistant Ms. Yang Liu will be available to assist

ME 242 Tutoring • Graduate Assistant Ms. Yang Liu will be available to assist with homework preparation and answer questions. • Coordination through the Academic Success Center in TBE-A 207 Tuesday and Friday mornings. • Contact hours: MW after class

ME 242 Reading Assignments • Look up the next Homework assignment on Mastering •

ME 242 Reading Assignments • Look up the next Homework assignment on Mastering • Example: your second assignment covers sections 12. 5 and 12. 6 • Study the text and practice the examples in the book • An I-Clicker reading test on each chapter section will be given at the start of each lecture • More time for discussion and examples

Supplemental Instruction ME 242 • Questions – Yang Liu – Ph. D student in

Supplemental Instruction ME 242 • Questions – Yang Liu – Ph. D student in ME – yangliu 205@gmail. com – Lab: SEB 4261

Chapter 12 -5 Curvilinear Motion X-Y Coordinates

Chapter 12 -5 Curvilinear Motion X-Y Coordinates

Here is the solution in Mathcad

Here is the solution in Mathcad

Example: Hit target at Position (360’, -80’)

Example: Hit target at Position (360’, -80’)

Example: Hit target at Position (360, -80)

Example: Hit target at Position (360, -80)

NORMAL AND TANGENTIAL COMPONENTS (Section 12. 7) When a particle moves along a curved

NORMAL AND TANGENTIAL COMPONENTS (Section 12. 7) When a particle moves along a curved path, it is sometimes convenient to describe its motion using coordinates other than Cartesian. When the path of motion is known, normal (n) and tangential (t) coordinates are often used. In the n-t coordinate system, the origin is located on the particle (the origin moves with the particle). The t-axis is tangent to the path (curve) at the instant considered, positive in the direction of the particle’s motion. The n-axis is perpendicular to the t-axis with the positive direction toward the center of curvature of the curve.

NORMAL AND TANGENTIAL COMPONENTS (continued) The positive n and t directions are defined by

NORMAL AND TANGENTIAL COMPONENTS (continued) The positive n and t directions are defined by the unit vectors un and ut, respectively. The center of curvature, O’, always lies on the concave side of the curve. The radius of curvature, r, is defined as the perpendicular distance from the curve to the center of curvature at that point. The position of the particle at any instant is defined by the distance, s, along the curve from a fixed reference point.

ACCELERATION IN THE n-t COORDINATE SYSTEM Acceleration is the time rate of change of

ACCELERATION IN THE n-t COORDINATE SYSTEM Acceleration is the time rate of change of velocity: . . a = dv/dt = d(vut)/dt = vut + vut. Here v represents the change in. the magnitude of velocity and ut represents the rate of change in the direction of ut. After mathematical manipulation, the acceleration vector can be expressed as: . a = v ut + (v 2/r) un = at ut + an un.

ACCELERATION IN THE n-t COORDINATE SYSTEM (continued) So, there are two components to the

ACCELERATION IN THE n-t COORDINATE SYSTEM (continued) So, there are two components to the acceleration vector: a = a t ut + a n un • The tangential component is tangent to the curve and in the direction of increasing or decreasing velocity. . at = v or at ds = v dv • The normal or centripetal component is always directed toward the center of curvature of the curve. an = v 2/r • The magnitude of the acceleration vector is a = [(at)2 + (an)2]0. 5

NORMAL AND TANGENTIAL COMPONENTS (Section 12. 7) When a particle moves along a curved

NORMAL AND TANGENTIAL COMPONENTS (Section 12. 7) When a particle moves along a curved path, it is sometimes convenient to describe its motion using coordinates other than Cartesian. When the path of motion is known, normal (n) and tangential (t) coordinates are often used. In the n-t coordinate system, the origin is located on the particle (the origin moves with the particle). The t-axis is tangent to the path (curve) at the instant considered, positive in the direction of the particle’s motion. The n-axis is perpendicular to the t-axis with the positive direction toward the center of curvature of the curve.

Normal and Tangential Coordinates Velocity Page 53

Normal and Tangential Coordinates Velocity Page 53

Normal and Tangential Coordinates ‘e’ denotes unit vector (‘u’ in Hibbeler)

Normal and Tangential Coordinates ‘e’ denotes unit vector (‘u’ in Hibbeler)

‘e’ denotes unit vector (‘u’ in Hibbeler)

‘e’ denotes unit vector (‘u’ in Hibbeler)

Learning Techniques • Complete Every Homework • Team with fellow students • Study the

Learning Techniques • Complete Every Homework • Team with fellow students • Study the Examples • Ask: Ms. Yang, peers, me • Mathcad provides structure and numerically correct results

Course Concepts • Math • Think Conceptually • Map your approach BEFORE starting work

Course Concepts • Math • Think Conceptually • Map your approach BEFORE starting work

12. 8 Polar coordinates

12. 8 Polar coordinates

Polar coordinates ‘e’ denotes unit vector (‘u’ in Hibbeler)

Polar coordinates ‘e’ denotes unit vector (‘u’ in Hibbeler)

Polar coordinates ‘e’ denotes unit vector (‘u’ in Hibbeler)

Polar coordinates ‘e’ denotes unit vector (‘u’ in Hibbeler)

12. 10 Relative (Constrained) Motion v. A is given as shown. Find v. B

12. 10 Relative (Constrained) Motion v. A is given as shown. Find v. B Approach: Use rel. Velocity: v. B = v. A +v. B/A (transl. + rot. )

Vectors and Geometry r(t) y q q(t) x

Vectors and Geometry r(t) y q q(t) x

12. 10 Relative (Constrained) Motion V_truck = 60 V_car = 65 Make a sketch:

12. 10 Relative (Constrained) Motion V_truck = 60 V_car = 65 Make a sketch: A V_rel v_Truck B The rel. velocity is: V_Car/Truck = v_Car -v. Truck

Example Vector equation: Sailboat tacking at 50 deg. against Northern Wind (blue vector) We

Example Vector equation: Sailboat tacking at 50 deg. against Northern Wind (blue vector) We solve Graphically (Vector Addition)

Example Vector equation: Sailboat tacking at 50 deg. against Northern Wind An observer on

Example Vector equation: Sailboat tacking at 50 deg. against Northern Wind An observer on land (fixed Cartesian Reference) sees Vwind and v. Boat. Land

12. 10 Relative (Constrained) Motion Plane Vector Addition is two-dimensional. v. A v. B/A

12. 10 Relative (Constrained) Motion Plane Vector Addition is two-dimensional. v. A v. B/A

Example cont’d: Sailboat tacking against Northern Wind 500 150 i 2. Vector equation (1

Example cont’d: Sailboat tacking against Northern Wind 500 150 i 2. Vector equation (1 scalar eqn. each in i- and j-direction). Solve using the given data (Vector Lengths and orientations) and Trigonometry

Chapter 12. 10 Relative Motion

Chapter 12. 10 Relative Motion

Vector Addition

Vector Addition

Differentiating gives:

Differentiating gives:

Exam 1 • We will focus on Conceptual Solutions. Numbers are secondary. • Train

Exam 1 • We will focus on Conceptual Solutions. Numbers are secondary. • Train the General Method • Topics: All covered sections of Chapter 12 • Practice: Train yourself to solve all Problems in Chapter 12

Exam 1 Preparation: Start now! Cramming won’t work. Questions: Discuss with your peers. Ask

Exam 1 Preparation: Start now! Cramming won’t work. Questions: Discuss with your peers. Ask me. The exam will MEASURE your knowledge and give you objective feedback.

Exam 1 Preparation: Practice: Step 1: Describe Problem Mathematically Step 2: Calculus and Algebraic

Exam 1 Preparation: Practice: Step 1: Describe Problem Mathematically Step 2: Calculus and Algebraic Equation Solving

And here a few visual observations about contemporary forms of socializing, sent to me

And here a few visual observations about contemporary forms of socializing, sent to me by a colleague at the Air Force Academy. Enjoy!

Having coffee with friends.

Having coffee with friends.

A day at the beach.

A day at the beach.

Cheering on your team.

Cheering on your team.

Out on an intimate date.

Out on an intimate date.

Having a conversation with your BFF

Having a conversation with your BFF

A visit to the museum

A visit to the museum

Enjoying the sights

Enjoying the sights