Chapter 11 Life CycleBased Testing Levels of Software

Chapter 11 Life Cycle-Based Testing

Levels of Software Applications • Up to now we have focused on testing techniques at the unit (or program) level. • In any medium to large software systems, there are many programs (sometimes thousands) that formulate various levels of functions to components - to a complete application. • For example a typical ERP (Enterprise Resource Processing) package such as SAP or People. Soft or CRM may be composed of multiple layers of application: – A comprehensive ERP package to satisfy a wide range of requirements contains • • Human Resource – Benefits management – Payroll Manufacturing – Production Planning and Scheduling – Inventory Distribution – Warehouse management – Logistics Financial.

Levels of Testing • Testing at the program unit level is not enough to handle medium and large software systems. • The different levels of software must be integrated and tested step-by-step - - - until the complete package is integrated and tested as a whole system: 1. Integration Test (Functional or higher Component level) • • • 2. monthly pay computation for regular employees, not including direct bank deposit or check printing - (“big” functional level) Complete Payroll - (“very big functional” or component level) Complete Human Resource - (“big component” or system level) System Test (component or complete system level) • • Human resource - (“big component” or system level) Manufacturing and Finance - (Integrated system level) Complete ERP - (“very large” Integrated system level)

Integration and System tests 1. Integration test can be helped with insights to the “structural” design of the software. – – 2. Which are the pieces ? - would help us decide what pieces need to be tested How are the pieces put together? - would help us decide where the “linkages” or couplings are and where the test focus points are. System test can be helped with insights to the “behavior” or “functional behavior” of the software as specified in the requirements – Given (a) some pre-conditional state and (b) some input or stimuli what should the • • i) output be and ii) the post-conditional state be.

Levels and Life Cycle Models • Levels of testing depend primarily on the software life cycle used. • BUT, most forms of testing levels are derived from the V-Model version of the good, old Waterfall Model. • Iterative models introduce the need for regression testing. • System testing is greatly enhanced when an executable specification is used.

The Waterfall Lifecycle

High Level Design Requirements specification Detailed. Design Coding Unit, Integration, and System Testing Maintenance

The V-Model

Evaluation of the Waterfall Model • Advantages – hierarchical structure maps nicely into large projects – phases have well-defined end products • (see IBM’s entry and exit criteria) – Unit level work can be done in parallel, reducing overall project interval • Disadvantages – Extremely long feedback cycle for customer – Very late synthesis (begins at integration testing) – Staff limitations may not support the advantage of massive parallel development at the unit level – Requires “perfect foresight”, otherwise early faults propagate

Spin-off Models • • • Practitioner responses to waterfall limitations Iterative Development The Spiral Model Rapid Prototyping Executable Specification Agile models – Scrum – e. Xtreme Programming (XP) – Test-Driven Development • Two promising hybrids – Agile Model-Driven Development (AMDD) – Model-Driven Agile Develoipment (MDAD)

Iterative Development

Iterative Development • Preserves a single high level design phase – amortizing design across increments is risky. Early design decisions may eliminate later design choices – defines the sequence and content of “builds” (or increments) • Builds create the need for regression testing • Preserves the advantages of Waterfall, AND • Responds to Waterfall defects – staffing limitations – late synthesis – long feedback cycle with customer

The Spiral Model • Proposed by Barry Boehm in 1988 • Very similar to the Iterative Model – builds are selected based on risk and feasibility • Pictured as an expanding spiral superimposed on the x-y plane (see internet for copyrighted images) • “Quadrants” correspond to a sequence of build activities – – determining objectives risk analysis development and test planning next increment • Single high level design phase is lost (which might be an inherent risk)

“Perfect Foresight? ” • Waterfall and the iterative variations have no answer for the customer who does not have a clear, complete idea of what is needed. • “Requirements Elicitation” is the process of helping customers and developers reach a common understanding of a proposed system. • Three lifecycle responses. . . – Rapid Prototyping – Executable Specification – the Agile methods

Rapid Prototyping

Rapid Prototyping • Helps customer identify needs and defects – – – “I’ll know what I want when I see it. ” provides the “does view” that customers appreciate ideal to give the “look and feel” of menu-driven systems modify prototype per customer feedback Sometimes done for feasibility • Advantages: – improved and early feedback with customer – better basis for design • Keep or dispose? – once it has served its purpose, the prototype can be archived. – possible to use to identify test scenarios

Executable Specification

Executable Specification • Very similar to Rapid Prototyping – early feedback – “look and feel” • Best for event-driven systems • Executable model is the specification – finite state machine – State. Chart • Need an “engine” – model is executed by the engine – usually interactively with customer

Evaluation of Executable Specification • Intended for “reactive systems” (event-driven) • Advantages – – early feedback automatic generation of system test cases can be used for operator training support for early analysis • Disadvantages – modeling can be difficult – training may be necessary – engine can be expensive

Generic Agile Lifecycle

Agile Development • Best response to the customer who does not know what is needed, i. e. , “perfect foresight” • Customer-driven, hence excellent customer feedback • Short increments (early synthesis) • We look at – e. Xtreme Programming (XP) – Test-Driven Development (TDD) – Scrum

e. Xtreme Programming

e. Xtreme Programming • Kent Beck, 1996 • Distinguishing characteristic: pair programming – one person has the detailed view (and the keyboard) – partner has the overall view, and acts as a constant reviewer – roles can change • Bottom-up development precludes a single, high level design phase – (but that might not be possible with an uncertain customer anyway)

Test-Driven Development (TDD)

Test-Driven Development (TDD) • Extreme case of agile development • Bottom-up development based on test cases – derived from customer-provided user stories – very quick feedback • Very small increments – early synthesis – excellent fault isolation – refactoring results in clean code • BUT, no opportunity for a comprehensive design

TDD Example: a Boolean Function to Determine Leap Years • Definition: A year is a leap year if it is a multiple of 4, but century years are leap years only if they are multiples of 400. • Test-Driven Development would break this into small, individual user stories (also called tasks). • “Coded” here in a pseudo-code (a lingua franca) that resembles Visual Basic.

User Story 1: A year divisible by 4 is a leap year Test Case 1 Input: 2012 Expected Output: True (existing) Pseudo-Code in normal font Function is. Leap(year) As Boolean End is. Leap Running Test Case 1 on this code fails. Add just enough code to make the test pass.

User Story 1: A year divisible by 4 is a leap year Test Case 1 Input: 2012 Expected Output: True (updated) Pseudo-Code in bold face font Function is. Leap(year) As Boolean dim year AS Integer 'MOD is the modulo arithmetic built-in operator in most languages If (( year MOD 4) = 0) Then Is. Leap = True End. If End is. Leap Test Case 1 passes. Now do User Story 2.

User Story 2: A year not divisible by 4 is a common year Test Case 1 Test Case 2 Input: 2012 Expected Output: True Input: 2007 Expected Output: False (existing) Pseudo-Code in normal font Function is. Leap(year) As Boolean dim year AS Integer If (( year MOD 4) = 0) Then Is. Leap = True End. If End is. Leap Test Case 1 passes. Test Case 2 fails. Now add just enough code so that Test Case 2 passes.

User Story 2: A year not divisible by 4 is a common year Test Case 1 Test Case 2 Input: 2012 Expected Output: True Input: 2011 Expected Output: False (updated) Pseudo-Code In bold face font Function is. Leap(year) As Boolean dim year AS Integer is. Leap = False If (( year MOD 4) = 0) Then Is. Leap = True End. If End is. Leap Test Cases 1 and 2 pass. Now do User Story 3

User Story 3: A century year not divisible by 400 is a common year Test Case 1 Test Case 2 Test Case 3 Input: 2012, Expected Output: True Input: 2011, Expected Output: False Input: 1900, Expected Output: False (existing) Pseudo-Code In normal font Function is. Leap(year) As Boolean dim year AS Integer is. Leap = False If (( year MOD 4) = 0) Then Is. Leap = True End. If End is. Leap Test Cases 1 and 2 pass. Test Case 3 fails. Now add just enough code so that Test Case 3 passes.

User Story 3: A century year not divisible by 400 is a common year Test Case 1 Test Case 2 Test Case 3 Input: 2012, Expected Output: True Input: 2011, Expected Output: False Input: 1900, Expected Output: False (updated) Pseudo-Code In bold face font Function is. Leap(year) As Boolean dim year AS Integer is. Leap = False If ((( year MOD 4) = 0) AND NOT((year MOD 100) = 0))) Then Is. Leap = True End. If End is. Leap Test Cases 1, 2 and 3 pass. Now do User Story 4

User Story 4: A century year divisible by 400 is a leap year Test Case 1 2 3 4 Input: 2012, 2011, 1900, 2000, Expected Output: True False True (existing) Pseudo-Code In normal font Function is. Leap(year) As Boolean dim year AS Integer is. Leap = False If ((( year MOD 4) = 0) AND NOT((year MOD 100) = 0))) Then Is. Leap = True End. If End is. Leap Test Cases 1, 2 and 3 pass. Test case 4 fails. Now add just enough code so that test case 4 passes.

User Story 4: A century year divisible by 400 is a leap year Test Case 1 2 3 4 Input: 2012, 2011, 1900, 2000, Expected Output: True False True (updated) Pseudo-Code In bold face font Function is. Leap(year) As Boolean dim year AS Integer is. Leap = False If ((( year MOD 4) = 0) AND NOT((year MOD 100) = 0))) OR ((year MOD 400 = 0)) Then Is. Leap = True End. If End is. Leap Test Cases 1, 2, 3 and 4 pass. Done with function is. Leap.

Advantages of Test Driven Development • In this example, the steps are deliberately small. • Customer and developer can (should!) jointly determine granularity of user stories. • Fault isolation is greatly simplified (in fact, trivial). If a test case fails, the fault must be in the most recently added code. • Once a new test case passes, a working (subset) of the desired software can always be delivered. • Something always works!

Disadvantages of Test Driven Development • Useful granularity is an issue. • There is no guarantee that user stories “arrive” in a sensible order. • There is no guarantee that user stories are the “same size” (or require similar effort) • Bottom-up coding often results in poorly structured code, making refactoring necessary.

Scrum Lifecycle

Scrum (not an acronym) • • • Created in 1993 by Jeff Sutherland Formalized in 1995 by Ken Schwaber Very popular today, both in US and Europe Named for the importance of teamwork in rugby n. b. : material in the series of slides on Scrum is taken from http: //www. scrumalliance. org/learn_about_scrum)

Scrum—New Terms for Existing Ideas • Three roles – Product owner – Scrum Master – Self-organizing team • Three ceremonies – Sprint planning meeting – Daily scrum meeting – Sprint review meeting • Three artifacts – Product backlog, – Sprint backlog – Burndown chart

Product Owner Responsibilities • Define the features of the product; • Decide on release date and content; • Be responsible for the profitability of the product (ROI); • Prioritize features according to market value; • Adjust features and priority every 30 days, as needed; and • Accept or reject work results. • Question: Product Owner = Customer?

Scrum Master Responsibilities • Ensure that the team is fully functional and productive • Enable close cooperation across all roles and functions • Remove barriers • Shield the team from external interferences • Ensure that the process is followed (sprint planning, daily meeting, sprint review) • Question: Scrum Master = Supervisor?

Scrum Team Responsibilities • Cross-functional with 7 +/- 2 members • Selects the Sprint goal and specifies work results • Has the right to do everything within the boundaries of the project guidelines to reach the Sprint goal • Organizes itself and its work • Demonstrates work results to Product Owner. • Question: Scrum Team = Development Team?

Comparison of Model Driven Development (MDD) and Test Driven Development (TDD) • First American’s view of Eagles and Mice – Eagles have the “big picture” – Mice focus on the details – (both views are important!) • MDD is a rigorous, top-down approach. • TDD is a bottom-up approach.

TDD is. Leap in Visual Basic (refactored) Public Function is. Leap(year) As Boolean Dim year As Integer Dim c 1, c 2, c 3 As Boolean 1. c 1 = (year Mod 4 = 0) 2. c 2 = (year Mod 100 = 0) 3. c 3 = (year Mod 400 = 0) 4, is. Leap = False 5. If ( (c 1 AND NOT(c 2)) OR (c 3)) Then 6. Is. Leap = True 7. Else 8. Is. Leap = False 9. End. If End Function

Decision Table Model of is. Leap Conditions r 1 r 2 r 3 r 4 r 5 r 6 r 7 r 8 C 1. year is a multiple of 4 T T F F C 2. year is a century year T T F F C 3. year is a multiple of 400 T F T F X X X Actions (logically impossible) X A 1. year is a common year A 2. year is a leap year test case: year = X X 2000 x X 1900 2012 2011

Agile Model-Driven Development • Scott Ambler • Model just enough for the present user story • Design is necessary! • BUT the modeling is still not in one phase

Agile Model-Driven Development

Model-Driven Agile Development

TDD is. Leap in Visual Basic (refactored) Public Function is. Leap(year) As Boolean Dim year As Integer Dim c 1, c 2, c 3 As Boolean 1. c 1 = (year Mod 4 = 0) 2. c 2 = (year Mod 100 = 0) 3. c 3 = (year Mod 400 = 0) 4, is. Leap = False 5. If ( (c 1 AND NOT(c 2)) OR (c 3)) Then 6. Is. Leap = True 7. Else 8. Is. Leap = False 9. End. If End Function

Decision Table Model of is. Leap Conditions r 1 r 2 r 3 r 4 r 5 r 6 r 7 r 8 C 1. year is a multiple of 4 T T F F C 2. year is a century year T T F F C 3. year is a multiple of 400 T F T F X X X Actions (logically impossible) X A 1. year is a common year A 2. year is a leap year test case: year = X X 2000 x X 1900 2012 2011

MDD is. Leap in Visual Basic Public Function is. Leap(year) As Boolean Dim year As Integer Dim c 1, c 2, c 3 As Boolean 1. c 1 = (year Mod 4 = 0) 2. c 2 = (year Mod 100 = 0) 3. c 3 = (year Mod 400 = 0) 4, is. Leap = False 5. If c 1 Then 6. If c 2 Then 7. If c 3 Then 8. is. Leap = True ‘rule r 1 9. Else 10. is. Leap = False ‘rule r 2 11. End If 12. Else 13. is. Leap = True ‘rule r 4 14. End If 15. Else 16. is. Leap = False ‘rule r 8 17. End If End Function

Observations • The TDD version is less complex (really? ) – Why? • The TDD version gradually built up to a compound condition (that might be hard to understand, and to modify). • The decision table model assures – What? • Both versions require 4 test cases