Centre of Gravity Centre of Gravity C G
- Slides: 11
Centre of Gravity
Centre of Gravity (C. G. ) l Definition l Finding C. G. of an irregularly shaped thin piece of card
Definition l The Centre of Gravity (C. G. ) of a body is the point through which the whole weight of the body seems to act l For a regular object, the C. G is always at the centre
We can think of the uniform bar as being made up of a lot of tiny particles. Each particle will have a force of gravity pulling it downwards. (weight) The bar will balance at one particular point, P, where the sum of all the clockwise moments of the individual forces is equal to the sum of all the anticlockwise moments of the individual forces.
The effect will be the same as if we had a single force acting downwards at P. So we can think of the gravitational force on the bar as a single force acting downwards at P. The point, P, is called the centre of gravity of the bar
Finding C. G. l If a body is hanging freely at rest, its centre of gravity is always vertically below the pivot.
When the card is released, the weight of the card acts like a single force through the C. G. This is balanced by an equal and opposite force – the reaction of the pin. If the C. G. is not directly beneath the pin, the two forces will form a rotating motion which will make the card swing downwards until the C. G. is directly below the pin. We then hang a plumb line in front of the card and draw a vertical line downwards through the pinhole. The C. G. lies somewhere on this line, AB. We repeat this with the pin at a different position and obtain a second line, CD. Since the C. G. must lie on both lines, it is at the point where the lines intersect.
The Centre of Gravity (C. G. ) of a body is the ____________________________________ For a regular object, the C. G is always at the _____
We can think of the uniform bar as being made up of a lot of __________. Each particle will have a force of gravity pulling it downwards. (weight) The bar will ____ at one particular point, P, where the ____________________ of the individual forces is equal to the _____________________ of the individual forces.
The effect will be the same as if we had a ________ acting downwards at P. So we can think of the gravitational force on the bar as a single force acting downwards at P. The point, P, is called the ___________ of the bar
When the card is released, the weight of the card acts like a single force through the C. G. This is balanced by an equal and opposite force – the reaction of the pin. ___________________________which will make the card swing downwards until the C. G. is directly below the pin. We then hang a plumb line in front of the card and draw a vertical line downwards through the pinhole. The C. G. lies somewhere on this line, AB. We repeat this with the pin at a different position and obtain a second line, CD. Since the C. G. must lie on both lines, it is at the point where the lines intersect.
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