CAMPBELL BIOLOGY TENTH EDITION Reece Urry Cain Wasserman

CAMPBELL BIOLOGY TENTH EDITION Reece • Urry • Cain • Wasserman • Minorsky • Jackson 13 Meiosis and Sexual Life Cycles Clicker Questions by Tara Turley-Stoulig © 2014 Pearson Education, Inc.

Which of the following transmits genes from both parents to child, or from one generation of a family to another? a) DNA b) gametes c) somatic cells d) mitosis e) nucleotides © 2014 Pearson Education, Inc.

Which of the following transmits genes from both parents to child, or from one generation of a family to another? a) DNA b) gametes c) somatic cells d) mitosis e) nucleotides © 2014 Pearson Education, Inc.

Fertilization is to zygote as meiosis is to which of the following? a) mitosis b) diploid c) chromosome d) replication e) gamete © 2014 Pearson Education, Inc.

Fertilization is to zygote as meiosis is to which of the following? a) mitosis b) diploid c) chromosome d) replication e) gamete © 2014 Pearson Education, Inc.

Privet shrubs and humans each have a diploid number of 46 chromosomes per cell. Why are the two species so dissimilar? a) Privet chromosomes undergo only mitosis. b) Privet chromosomes are shaped differently. c) Human chromosomes have genes grouped together differently. d) The two species have appreciably different genes. e) Privets do not have sex chromosomes. © 2014 Pearson Education, Inc.

Privet shrubs and humans each have a diploid number of 46 chromosomes per cell. Why are the two species so dissimilar? a) Privet chromosomes undergo only mitosis. b) Privet chromosomes are shaped differently. c) Human chromosomes have genes grouped together differently. d) The two species have appreciably different genes. e) Privets do not have sex chromosomes. © 2014 Pearson Education, Inc.

Why is it more practical to prepare karyotypes by viewing somatic diploid cells rather than haploid gametes? a) Somatic diploid cells do not contain organelles to interfere with karyotyping. b) Both sets of chromosomes, which are present in somatic diploid cells, need to be examined. c) DNA in haploid gametes will not stain. d) The chromosomes are larger in a somatic diploid cell. e) Haploid gametes do not have sex chromosomes. © 2014 Pearson Education, Inc.

Why is it more practical to prepare karyotypes by viewing somatic diploid cells rather than haploid gametes? a) Somatic diploid cells do not contain organelles to interfere with karyotyping. b) Both sets of chromosomes, which are present in somatic diploid cells, need to be examined. c) DNA in haploid gametes will not stain. d) The chromosomes are larger in a somatic diploid cell. e) Haploid gametes do not have sex chromosomes. © 2014 Pearson Education, Inc.

Diploid cells may undergo either mitosis or meiosis. Haploid cells may undergo mitosis (for certain species) but not meiosis because a) the sister chromatids cannot separate. b) the synaptonemal complex is too strong. c) crossing over has occurred. d) cohesins are no longer present. e) homologous chromosomes cannot pair. © 2014 Pearson Education, Inc.

Diploid cells may undergo either mitosis or meiosis. Haploid cells may undergo mitosis (for certain species) but not meiosis because a) the sister chromatids cannot separate. b) the synaptonemal complex is too strong. c) crossing over has occurred. d) cohesins are no longer present. e) homologous chromosomes cannot pair. © 2014 Pearson Education, Inc.

How and at what stage do chromosomes undergo independent assortment? a) meiosis I pairing of homologs b) anaphase I separation of homologs c) meiosis II separation of homologs d) meiosis I metaphase alignment e) meiosis I telophase separation © 2014 Pearson Education, Inc.

How and at what stage do chromosomes undergo independent assortment? a) meiosis I pairing of homologs b) anaphase I separation of homologs c) meiosis II separation of homologs d) meiosis I metaphase alignment e) meiosis I telophase separation © 2014 Pearson Education, Inc.

What allows sister chromatids to separate in which phase of meiosis? a) release of cohesin along sister chromatid arms in anaphase I b) crossing over of chromatids in prophase I c) release of cohesin at centromeres in anaphase I d) release of cohesin at centromeres in anaphase II e) crossing over of homologs in prophase I © 2014 Pearson Education, Inc.

What allows sister chromatids to separate in which phase of meiosis? a) release of cohesin along sister chromatid arms in anaphase I b) crossing over of chromatids in prophase I c) release of cohesin at centromeres in anaphase I d) release of cohesin at centromeres in anaphase II e) crossing over of homologs in prophase I © 2014 Pearson Education, Inc.

Gametes produced from one meiotic event a) are genetically identical to each other. b) each have the same chromosome number. c) are genetically identical to the cells produced from meiosis I. d) are genetically identical to the parent cell. e) each have the same mutations. © 2014 Pearson Education, Inc.

Gametes produced from one meiotic event a) are genetically identical to each other. b) each have the same chromosome number. c) are genetically identical to the cells produced from meiosis I. d) are genetically identical to the parent cell. e) each have the same mutations. © 2014 Pearson Education, Inc.

Crossing over begins to occur during a) anaphase I b) anaphase II c) prophase I d) metaphase II e) telophase II © 2014 Pearson Education, Inc.

Crossing over begins to occur during a) anaphase I b) anaphase II c) prophase I d) metaphase II e) telophase II © 2014 Pearson Education, Inc.

In this cell, what phase is represented? a) mitotic metaphase b) meiosis I anaphase c) meiosis I metaphase d) meiosis II anaphase e) meiosis II metaphase © 2014 Pearson Education, Inc.

In this cell, what phase is represented? a) mitotic metaphase b) meiosis I anaphase c) meiosis I metaphase d) meiosis II anaphase e) meiosis II metaphase © 2014 Pearson Education, Inc.

Scientific Skills Exercise When nutrients are low, cells of the budding yeast (Saccharomyces cerevisiae) exit the mitotic cell cycle and enter meiosis. In this exercise, you will track the DNA content of a population of yeast cells as they progress through meiosis. Researchers grew a culture of yeast cells in a nutrient-rich medium and then transferred them to a nutrientpoor medium to induce meiosis. At different times after induction, the DNA content per cell was measured in a sample of the cells, and the average DNA content per cell was recorded in femtograms (fg; 1 femtogram 1 × 10– 15 gram). Their data are shown in the table to the right. © 2014 Pearson Education, Inc.

Most of the yeast cells in the culture were in G 1 of the cell cycle before being moved to the nutrient-poor medium to induce meiosis. How many femtograms of DNA are there in a yeast cell in G 1? Estimate this value from the data in the table. a) 12 fg b) 24 fg c) 40 fg d) 48 fg © 2014 Pearson Education, Inc.

Most of the yeast cells in the culture were in G 1 of the cell cycle before being moved to the nutrient-poor medium to induce meiosis. How many femtograms of DNA are there in a yeast cell in G 1? Estimate this value from the data in the table. a) 12 fg b) 24 fg c) 40 fg d) 48 fg © 2014 Pearson Education, Inc.

How many femtograms of DNA are present in a cell in G 2? a) 12 fg b) 24 fg c) 40 fg d) 48 fg © 2014 Pearson Education, Inc.

How many femtograms of DNA are present in a cell in G 2? a) 12 fg b) 24 fg c) 40 fg d) 48 fg © 2014 Pearson Education, Inc.

How many femtograms of DNA are present in a cell at the end of meiosis I? a) 12 fg b) 24 fg c) 40 fg d) 48 fg © 2014 Pearson Education, Inc.

How many femtograms of DNA are present in a cell at the end of meiosis I? a) 12 fg b) 24 fg c) 40 fg d) 48 fg © 2014 Pearson Education, Inc.

How many femtograms of DNA are present in a cell at the end of meiosis II? a) 12 fg b) 24 fg c) 40 fg d) 48 fg © 2014 Pearson Education, Inc.

How many femtograms of DNA are present in a cell at the end of meiosis II? a) 12 fg b) 24 fg c) 40 fg d) 48 fg © 2014 Pearson Education, Inc.

A graph with labels indicating the different phases of the meiotic cell cycle (MI meiosis I; MII meiosis II) is shown to the right, based on the data from the table. Think carefully about the point on the graph where the line at the highest value begins to slope downward, indicated by the red arrow. What specific point of meiosis does this “corner” represent? a) metaphase I b) prophase II c) cytokinesis d) anaphase I © 2014 Pearson Education, Inc.

A graph with labels indicating the different phases of the meiotic cell cycle (MI meiosis I; MII meiosis II) is shown to the right, based on the data from the table. Think carefully about the point on the graph where the line at the highest value begins to slope downward, indicated by the red arrow. What specific point of meiosis does this “corner” represent? a) metaphase I b) prophase II c) cytokinesis d) anaphase I © 2014 Pearson Education, Inc.

Based on this data, how much DNA is present in a gamete of Saccharomyces cerevisiae? a) 12 fg b) 24 fg c) 48 fg © 2014 Pearson Education, Inc.

Based on this data, how much DNA is present in a gamete of Saccharomyces cerevisiae? a) 12 fg b) 24 fg c) 48 fg © 2014 Pearson Education, Inc.

Given the fact that 1 fg of DNA 9. 78 105 base pairs (on average), you can convert the amount of DNA per cell to the length of DNA in numbers of base pairs. Millions of base pairs (Mb) is the standard unit for expressing genome size. Calculate the approximate number of base pairs of DNA in the haploid yeast genome. a) 0. 08 Mb (8. 0 104 base pairs) b) 1. 2 Mb (1. 2 106 base pairs) c) 12 Mb (12 106 base pairs) d) 23 Mb (23 106 base pairs) © 2014 Pearson Education, Inc.

Given the fact that 1 fg of DNA 9. 78 105 base pairs (on average), you can convert the amount of DNA per cell to the length of DNA in numbers of base pairs. Millions of base pairs (Mb) is the standard unit for expressing genome size. Calculate the approximate number of base pairs of DNA in the haploid yeast genome. a) 0. 08 Mb (8. 0 104 base pairs) b) 1. 2 Mb (1. 2 106 base pairs) c) 12 Mb (12 106 base pairs) d) 23 Mb (23 106 base pairs) © 2014 Pearson Education, Inc.

Given the fact that 1 fg of DNA 9. 78 105 base pairs (on average), you can estimate the rate of DNA synthesis in Saccharomyces cerevisiae. Approximately how many base pairs per minute were synthesized during the S phase of these yeast cells? a) 0. 19 (1. 9 10– 1) base pair per minute b) 100, 000 (1. 0 105) base pairs per minute c) 200, 000 (2. 0 105) base pairs per minute d) 11, 000 (11. 0 106) base pairs per minute © 2014 Pearson Education, Inc.

Given the fact that 1 fg of DNA 9. 78 105 base pairs (on average), you can estimate the rate of DNA synthesis in Saccharomyces cerevisiae. Approximately how many base pairs per minute were synthesized during the S phase of these yeast cells? a) 0. 19 (1. 9 10– 1) base pair per minute b) 100, 000 (1. 0 105) base pairs per minute c) 200, 000 (2. 0 105) base pairs per minute d) 11, 000 (11. 0 106) base pairs per minute © 2014 Pearson Education, Inc.