Calculating Energy Changes at Phase Changes heating rate

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Calculating Energy Changes at Phase Changes

Calculating Energy Changes at Phase Changes

heating rate = 150 J/min If the substance takes 4 minutes to melt, how

heating rate = 150 J/min If the substance takes 4 minutes to melt, how much heat energy was used to melt it?

What is the melting point of this substance? The boiling point?

What is the melting point of this substance? The boiling point?

Heat of Fusion = amount energy required to change 1 gram of pure substance

Heat of Fusion = amount energy required to change 1 gram of pure substance from solid to liquid at its mp Heat of Fusion = Hf = physical constant for water = 334 J/g (Table B)

How much heat is absorbed when 10 grams of ice melts at 0 o.

How much heat is absorbed when 10 grams of ice melts at 0 o. C? Heat absorbed = mass of substance x heat of fusion of substance Q = m. Hf = (10 g)(334 J/g) = 3340 J Where does this energy go? Particles must overcome forces of attraction to move farther apart

Heat of Vaporization = amount energy required to convert 1 gram of pure substance

Heat of Vaporization = amount energy required to convert 1 gram of pure substance from liquid to gas at its bp Heat of vaporization = Hv for water = 2260 J/g = physical constant

How much energy does it take to vaporize 10 g of water? Q =

How much energy does it take to vaporize 10 g of water? Q = m. Hv Q = (10 g)(2260 J/g) = 22600 J It takes a lot more energy to go from liquid to gas (22, 600 J) than from solid to liquid (3, 340 J). Why?

H 2 O changing from solid to liquid requires 3, 340 J/g

H 2 O changing from solid to liquid requires 3, 340 J/g

H 2 O changing from liquid to gas requires 22, 600 J/g • greater

H 2 O changing from liquid to gas requires 22, 600 J/g • greater energy required to change from solid to liquid because particles are spreading out a lot more!

Heats of fusion & vaporization Determined in calorimetry experiments

Heats of fusion & vaporization Determined in calorimetry experiments

Temperature Q= Q= m. Csolid T m. H Q= m. Cliquid T f Q=

Temperature Q= Q= m. Csolid T m. H Q= m. Cliquid T f Q= m. Hv Q= m. Cgas T Time

3 equations for Q 1. Q = m. C T 2. Q = m.

3 equations for Q 1. Q = m. C T 2. Q = m. Hf 3. Q = m. Hv figure out which to use given problem depends on section of heating curve look for hints in word problem

Q = m. C T Temperature changed T↑ T↓ Initial temperature Start temperature Final

Q = m. C T Temperature changed T↑ T↓ Initial temperature Start temperature Final temperature Ending temperature From __ ˚C to __ ˚C Water

Q = m. Hf Ice Freezing Melting Occurs at 0 C (for H 2

Q = m. Hf Ice Freezing Melting Occurs at 0 C (for H 2 O) At constant temperature

Q = m. Hv Steam Boiling Condensation Occurs at 100 C (for H 2

Q = m. Hv Steam Boiling Condensation Occurs at 100 C (for H 2 O) At constant temperature