C program 3 Enter first integer C Addition

ﺑﺮﻧﺎﻣﻪ ﺍﻱ ﺩﻳگﺮ ﺑﻪ ﺯﺑﺎﻥ C++ // program #3 Enter first integer // C++ Addition of integers #include <stdio. h> 5 int main() Enter second integer { 3 integer 1, integer 2, sum; Sum is 8 printf( "Enter first integern" ); scanf( "%d" , &integer 1); ﺑﺮﺍﻱ ﺩﺭﻳﺎﻓﺖ ﺍﻃﻼﻋﺎﺕ ﺍﺯ scanf ﺗﺎﺑﻊ printf( "Enter second integern" ); ﻣﻮﺭﺩ ﺍﺳﺘﻔﺎﺩﻩ ﻗﺮﺍﺭ ﻣﻴگﻴﺮﺩ keyboard scanf( "%d" , &integer 2); ﺧﻮﺍﻫﺪ + ﺻﺤﺒﺖ ﺩﺭ ﺍﺩﺍﻣﻪ ﺩﺭﺱ ﺩﺭ ﻣﻮﺭﺩ ﺍﻳﻦ ﺗﺎﺑﻊ sum = integer 1 integer 2; !! ﺷﺪ printf( "Sum is %dn" , sum); return 0; } 3

ﻣﺜﺎﻝ n n int i; int j; int sum, var; float f=0; 8

ﺍﺳﺎﻣﻲ ﻏﻴﺮ ﻣﺠﺎﺯ ﺑﺮﺍﻱ ﻣﺘﻐﻴﺮﻫﺎ ﺑﺮﺧﻲ ﺍﺳﺎﻣﻲ ﺑﺮﺍﻱ ﺳﻴﺴﺘﻢ ﺗﻌﺮﻳﻒ ﺷﺪﻩ ﻫﺴﺘﻨﺪ ﻭ ﻣﺎ ﻣﺠﺎﺯ ﺑﻪ ﺍﺳﺘﻔﺎﺩﻩ ﻧﻴﺴﺘﻴﻢ asm, auto, bool , break , case , catch , char , class , const_cast , continue , default , delete , double , dynamic_cast , else , enum , explicit , export , extern , false , float , for , friend , goto , if, inline , int , long , mutable , namespace , new , operator , private , protected , public , register , reinterpret_cast , return , short , signed , sizeof , static_cast , struct , switch , template , this, throw , true , try , typedef , typeid , typename , union, unsigned , using , virtual , void , volatile , wchar_t , while 9

Data Types Type Length Range unsigned char 1 byte 8 bits 0 to 255 char 1 byte 8 bits -128 to 127 enum 2 bytes 16 bits -32, 768 to 32, 767 unsigned int 2 bytes 16 bits 0 to 65, 535 short int 2 bytes 16 bits -32, 768 to 32, 767 unsigned long 4 bytes 32 bits 0 to 4, 294, 967, 295 long 4 bytes 32 bits -2, 147, 483, 648 to 2, 147, 483, 647 float 4 bytes 32 bits 3. 4 * (10^-38) to 3. 4 * (10^+38) double 8 bytes 64 bits 1. 7 * (10^-308) to 1. 7 * (10^+308) long double 10 bytes 80 bits 3. 4 * (10^-4932) to 1. 1 * (10^+4932) 10