BINARY COMPOUNDS POLYATOMIC COMPOUNDS BINARY COMPOUNDS two elements

BINARY COMPOUNDS & POLYATOMIC COMPOUNDS

BINARY COMPOUNDS (two elements ) 1) THE FIRST ELEMENT REMAINS THE SAME. 2) THE ENDING IS CHANGED ON THE SECOND ELEMENT. EX SULFUR BECOMES SULFIDE EXAMPLE K Br = POTASSIUM BROMIDE

All of the negative elements change their endings to -ide CHLORINE = CHLORIDE BROMINE = BROMIDE FLUORINE = FLUORIDE IODINE = IODIDE OXYGEN = OXIDE SULFUR = SULFIDE NITROGEN = NITRIDE PHOSPHORUS = PHOSPHIDE CARBON= CARBIDE HYDROGEN = HYDRIDE

POLYATOMIC COMPOUNDS 1) THE FIRST ELEMENT STAYS THE SAME. 2) THE POLYATOMIC PART DOES NOT CHANGE ITS ENDING. Ca (CO 3) Calcium carbonate

1) Al 2 S 3 = 2) Ca Br 2 = 3) K Cl = 4) Li 2 O = 5) Ca Cl 2 =

1) Al 2 S 3 = aluminum sulfide 2) Ca Br 2 = calcium bromide 3) K Cl = potassium chloride 4) Li 2 O = lithium oxide 5) Ca Cl 2 = calcium chloride

6) K 2 O = 7) Na 3 P = 8) Al 2 S 3 = 9) Mg O = 10) Li 3 N =

6) K 2 O = potassium oxide 7) Na 3 P = sodium phosphide 8) Al 2 S 3 = aluminum sulfide 9) Mg O = magnesium oxide 10) Li 3 N = lithium nitride

1) Mg (OH)2 = 2) K 2 (C 2 O 4) = 3) (NH 4) Cl = 4) Li 3 (As. O 4) = 5) Na (NO 3) =

1) Mg (OH)2 = magnesium hydroxide 2) K 2 (C 2 O 4) = potassium oxalate 3) (NH 4) Cl = ammonium chloride 4) Li 3 (As. O 4) = lithium arsenate 5) Na (NO 3) = sodium nitrate

6) Li(OH) = 7) Ca 3 (PO 4)2 = 8) Al (IO 3)3 = 9) Ba (NO 3)2 10) Ag (Cl. O 4) = =

6) Li(OH) = lithium hydroxide 7) Ca 3 (PO 4)2 = calcium phosphate 8) Al (IO 3)3 = aluminum iodate 9) Ba (NO 3)2 10) Ag (Cl. O 4) = barium nitrate = silver perchlorate